Displaying 1 result from an estimated 1 matches for "pred_temp".
2007 Dec 11
1
Using predict()?
...-statistic: 29.97 on 1 and 13 DF, p-value: 0.0001067
> # From the linear model summary output above, the equation for the
least squares line is:
> # y = -0.3143 + 0.2120*x or chirps = -0.3143 + 0.2120*temp
>
I can then determine the answer to the prediction, using algebra and R:
> pred_temp <- (18+0.3143)/0.2120
> pred_temp
[1] 86.3882
However, I'd like to try to use the predict() function. Since 'chirps'
and 'temp' are just vectors of numbers, and not dataframes, these
failed:
predict(chirps.res, newdata=data.frame(chirp=18))
predict(chirps.res, newdata=&qu...