search for: precip

Dear R-users Sorry for posting the previous message too soon before I have finished it. I have matrix (mprecip) with headers: > dim(mprecip) [1] 6268 170 > mprecip date GilzeRijen Eindhoven Volkel ZuidLimburg Arcen Ubachsberg 1 01/01/1978 NA 0.0 NA 0.1 NA NA 2 01/02/1978 NA 0.0 NA 0.0 NA NA 3 01/03/1978...

note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7 input="precip...

The simplest would be to convert precip to character and then back to a factor if you really want it to be a factor. This will also remove the levels that no longer exist. str(dat) # 'data.frame': 5 obs. of 3 variables: # $ Sites : Factor w/ 5 levels "Site1","Site2",..: 1 2 3 4 5 # $ temp : num 14 15 1...

...:5,3]<-"20" but it generated NA> do you have any suggestions for me? dat<-structure(list(Sites = structure(1:5, .Label = c("Site1", "Site2", "Site3", "Site4", "Site5"), class = "factor"), temp = c(14, 15, 12, 12.5, 17), precip = structure(c(3L, 4L, 5L, 2L, 1L), .Label = c("15", "34", "high", "low", "medium"), class = "factor")), .Names = c("Sites", "temp", "precip"), class = "data.frame", row.names = c(NA, -5L )) > dat[...

Hi all, i'm sure there is an easy way to do this, but i'm stumped, so any help would be appreciated. i have a single column of data for precipitation every 15 minutes over a year. i want to sum the precip to daily data. so the first 96 records = the first day, the second 96 records = the second day, and so on.... is there a way to write a for loop that would sum the data to daily, and write each value to a second object so i end up with...

Hello, I have two different files which I'd like to combine to make one data frame but I've no idea how to do it! The first file has two columns; one is the date, the following is a binary code for debris flow events. Then my other file has also two columns; the date and then precipitation data. The thing is, is that the two date columns don't all contain the same dates. The binary one is every day from April - October from 1900 - 2005, yet the precipitation file has dates from from say, 1911 to 2004, with some missing data on certain months and during certain years. So...

Dear R community, I am having trouble determining how to create the graph I want utilizing my relatively limited knowledge of R. So far I have been using the lattice library to create most of what I need. The dataset (enviro) consists of 2 variables (Temp and Precip) for each Day of a 2-yr period (Year). I wish to display Temp and Precip along the y axis plotted by Day on the x axis to allow comparison (one year's data in each of 2 panels stacked on top of each other) between the years. Essentially what I want it to look like is an xyplot (Temp ~ Day...

Dear group, First I provide you with an example, I found in the newsgroup. Then I'd like to explain my problem to you by means of the output. enviro <- data.frame(Year = rep(2001:2002, each = 365), Day = rep(1:365, 2), Precip = pmax(0, rnorm(365 * 2)), Temp = 2 + 0.2 * rnorm(365 * 2)) xyplot(Precip + Temp ~ Day | Year, data=enviro, layout = c(1, 2), panel = panel.superpose.2, type = c('h', 'l')) Now my question. How can I achieve different labels for two y-...

Dear all, I'm having trouble getting the correct spacing between x-axis labels on a barplot. This is the command I'm using to generate the plot: temp <- barplot(precip, beside=TRUE, xaxt="n", las=1, xpd=FALSE, col="grey28", ylim=c(0, max(precip))) Here is the structure of temp: > str(temp) ?num [1:96, 1] 0.7 1.9 3.1 4.3 5.5 6.7 7.9 9.1 10.3 11.5 ... And here is the structure of the data being plotted: > str(precip) ?num [1:96] 1841 287...

...tor, i.e. W[[1]]$year, etc.. You can also use data frame indices for the columns, i.e. W[[1]][ ,1] or W[[1]][ ,"year"] . All of which I believe you know. However, I will hazard a *guess* (so exercise due diligence and check) as to the cause of your original error, "dd(data = W[[1]]$Precip, time.scale = W[[1]]$year) Fehler in W[[1]]$year : $ operator is invalid for atomic vectors' even though I know **nothing** about the dd() function. My guess is: "data" is usually an argument to a function that tells it to use "nonstandard evaluation" to look for arguments...

Hello friends of R, My name is Toni, i'm 25 and I'm working on the Meteorological Investigation team from Balearic Islands. I had contact to you because I have a problem: I done a file for every day since 1912 about precipitation. That file has the following structure: > str(Ast) Loading required package: sp Formal class 'SpatialPixelsDataFrame' [package "sp"] with 7 slots ..@ data :'data.frame': 499105 obs. of 2 variables: .. ..$ PRECIP.pred: num [1:499105] 0.000536 0.000536...

Hi, I am using mgcv:gam and have developed a model with 5 smoothed predictors and one factor. gam1 <- gam(log.sp~ s(Spr.precip,bs="ts") + s(Win.precip,bs="ts") + s( Spr.Tmin,bs="ts") + s(P.sum.Tmin,bs="ts") + s( Win.Tmax,bs="ts") +factor(site),data=dat3) The total deviance explained = 70.4%. I would like to extract the variance explained by each predictor. Is there a...

...mple way to do this? I know I could do this using facetting if they were both the same type of plot (for example, if they were both boxplots), but I haven't been able to figure it out for two different types of plots. Below is my test case: library(ggplot2) library(gridExtra) #generate test precipitation data year<-c(2000,2001,2002,2003,2004) precip<-c(46,100,80,74,20) yp<-data.frame(year, precip) #generate test fecal coliform data year2<-c(2000,2000,2000,2000,2000,2000,2000,2000,2000,2000, 2001,2001,2001,2001,2001,2001,2001,2001,2001,2001, 2002,2002,2002,2002,2002,2002,2002,200...

Dear R-users, I am trying to make a plot with ggplot-geom_tile(), but cannot remove some unwanted (white) lines through my plot. Below a reproducible example: ##### library(ggplot2) tot=as.data.frame(rep(seq(-50,50,5),each=21)) names(tot)="precip" temp=rep(seq(-5,5,0.5),21) tot$temp=temp disc=array(dim=c(21,21)) for(i in 1:21){ for(y in 1:21){ temp<- rev(seq(10000+((i-1)*500),12000+((i-1)*500),100)) disc[i,y]=temp[y] }} disc1=t(disc) bla=as.vector(disc1) tot$dis=bla cols=c("darkred"," white",&quo...

Hello I have a matlab MAT file that contains one single variable: a. The structure of a is as follows: a.river1.flow (flow values) a.river1.date_flow (date) a.river1.precip (precipitation values) a.river1.date_precip a.river2.flow a.river2.date_flow a.river2.precip a.river2.date_precip I have used readMat to load the variable a in R, however I have no idea how readMat translates a. I managed to get some values out of data=readMat("matfile.mat") data$a[,,1...

Just found because an old (written for S+) function of mine did label plots wrongly with R. Example --- inspired from example(qqnorm) --- data(precip) qqnorm(precip, ylab = "Precipitation [in/yr] ...") qqnorm(precip, ylab = "Precipitation [in/yr] ...", datax = TRUE) this is all "fine" -- `datax' is a switch that just switches the axes but keeps the meaning of "ylab labels the data axis" (i.e, when...

Dear all, quite a naive question: I have a data frame and I computed "the kernel density estimate" with density on each column. Now I'd like to export in a txt file the density function output for each column, but, when if I use write.table, I get a message "Error in as.data.frame.default(x[[i]], optional = TRUE) : can't coerce class "density" into a

...ith using a "for" loop to read and separate a large dataset. The response I got worked great, but now I have another problem with using my loop. Basically I have a number of different files containing columned data. There are 132 datasets, named such that I have something in the form... precip_colxxx.txt ...where xxx is a number ranging from 1 to 132. What I want to do is read in every 13th table and extract the third column, and then place this in a new dataset. The new dataset will thus compose of 11 columns of data. I have written the following bit of script to read in every 13th tab...

..., I'm attempting to add a "Julian Day" column to a data frame. Here is my code and the resulting data frame: vic.data <- read.table("C:/VIC/data/vic.data.csv", header=F) names(vic.data) <- c("year", "month", "day", "precip", "evap", "runoff", "baseflow", "Tsup", "SM1", "SM2", "SM3", "SWE") vic.data$temp.date <- as.Date(paste(vic.data$year, "/", vic.data$month, "/", vic.data$day, sep=""))...

Hello, I am new to R exploratory data analysis and plotting. Is anyone aware of a way to overlay a set of conditional histograms with conditional PDFs? Below, I generate a lattice plot of precipitation histograms based on different months and stations, given a subset of the dataset: histogram(~ data | month * station, data = sta.stack[sta.stack[,"type"]=="precip" & (sta.stack[,"month"]=="Dec" | sta.stack[,"month"]=="Jan" |...