search for: pquantile

...he server response time: σ = qPN i=1(Ri − μ)2/(N − 1). • Confidence interval for the response time at confidence 100c% is given as: [μ − zpσ/√N, μ + zpσ/pN], where p = (1 + c)/2, and zp is the quantile of the unit normal distribution at p. If N <= 30, we replace zp by tp;n−1, which is the pquantile of a t-variate with n−1 degrees of freedom, assuming that the response time values from N runs come from a normal distribution. We verified that response times do come from a normal distribution using a normal proability plot. DISCLAIMER:\ ===============...{{dropped:31}}

Hi All, is there any effiective and dense/compact method to calculate the mean of a list of - of course coincident - matrices on an element by element basis? The resulting matrix' [i, j]-th element is the mean of the list's matrices' [i, j]-th elements respectively... Iterating by for statement is quite straightforward, but I am seeking for a more elegant solution, and my attempt with