Displaying 1 result from an estimated 1 matches for "ppmtp".
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ppmt
2018 May 10
0
the first name of the first column
...less you have
good reason not to. I have done that here.
It looks like this is what you want; if so, you really need to go through
an R tutorial or two to learn the basics:
d <-
structure(list(region = structure(c(1L, 1L, 1L, 1L), .Label = "zilan",
class = "factor"),
Fe_ppmtp = c(8.36, 8.78, 16.52, 42.22), Zn.ppmtp = c(0.44,
0.58, 2.28, 14.22), Mn_tp = c(6.9, 21.16, 27.58, 34.7), Cu_tp = c(0.5,
0.24, 0.8, 31.9)), class = "data.frame", row.names = c(NA,
-4L))
> md <- as.matrix(d[,-1]) ## knowledge of indexing is essential in R !
> md
Fe_...