search for: pp2

...7961631 04R 1 3 2 -0.13795380 04R 1 4 3 -0.20726073 04R 1 > > sapply(times, class) time error runway flight "numeric" "numeric" "factor" "factor" I want to plot this using ggplot2 library(ggplot2) pp2 = qplot(times$time, times$error, times) pp2 = pp2 + facet_wrap(~ times$runway) print(pp2) But when I try it, I get the error Error in fix.by(by.x, x) : 'by' must specify valid column(s) I get the same error if I make times$time a factor: > > times$time = as.factor(times$time)...

Hi R, I have a list > class(pp2) [1] "list" > length(pp2) [1] 1244 It is in the below format RIC Trade.Date Close.Price Currency.Code Convertion.Rate New.Price ABCD.SZ 2008/02/29 15.30 CNY 0.1408 2.154240 ABCD.SZ 2008/01/31 15.27 CNY 0.1392 2.125584 ABCD.SZ...

I am using ggplot2 to make a boxplot that overlays a scatterplot: pp = qplot(time, error, data=times, size=I(1), geom="jitter", main=title, ylab="Error (min)", xlab="Time before ON (min)", alpha=I(1/10), color=times$runway, ylim=c(-30,40)) pp2 = pp + with(times, facet_wrap(~ runway, ncol=2)) print(pp2 + geom_boxplot(alpha=.5, color="blue", outlier.colour="green", outlier.size=1)) The x variable is a factor for every minute from 0:60. My problem is that ggplot2 labels every factor value on the x axis, and they over...

Can anyone explain what I'm missing here? max(pp1 <- package_version(c("0.99999911.3","1.0.4","1.0.5"))) ## [1] ?1.0.4? max(pp2 <- package_version(c("1.0.3","1.0.4","1.0.5"))) ## [1] ?1.0.5? I've looked at ?package_version , to no avail. Since max() goes to .Primitive("max") I'm having trouble figuring out where it goes from there: I **think** this is related to ?xtfrm ,...

Hi I looked, but I didn't find it: I need an array [0 to 101] where each element is a list (the result of Kest in spatstat). I.e. I want to do: A[2] <- Kest(pp1) A[3] <- Kest(pp2) ... A[101] <- Kest(pp100) How can I create A ? Rainer -- Rainer M. Krug, Dipl. Phys. (Germany), MSc Conservation Biology (UCT) Department of Conservation Ecology University of Stellenbosch Matieland 7602 South Africa

Hello. I have n files in a directory: file1, ..., filen. I read them with the following commands: list=scan(file="list",what=list(nom="")) # in the file list, I have all the filenames. n=length(list[[1]]) for (i in 1:n){ aux <- paste("p",i,sep="") assign(aux, as.matrix(read.table(list[[1]][i]))) } R creates the matrices p1,p2,...,pn. I want

...ta(ts01), y2) ? #vertices for area under y1 mat1 <- cbind(c(index(ts01)[1], index(ts01), index(ts01)[length(index(ts01))]), c(ymin, coredata(ts01), ymin)) ? #vertices for area under y2 mat2 <- cbind(c(index(ts01)[1],index(ts01), index(ts01)[length(index(ts01))]), c(ymin, y2, ymin)) ? pp2 <- as(mat2, "gpc.poly") pp1 <- as(mat1, "gpc.poly") ? m <-max( (max(coredata(ts01)) - bl)/3, abs(min(coredata(ts01)) - bl)/3) m1 <- bl+m m2 <- bl+2*m ? ##### cutting the blue poly above the baseline # poly above the baseline s1 <- setdiff(pp1, pp2) y2...

This patch set fixes a two year old bug in guestfish, namely that the 'glob' command does not expand /dev/* patterns. https://bugzilla.redhat.com/show_bug.cgi?id=635971 Rich.

Hi I have two processes which take with a certain probability (p1 and p2) x number of years to complete (age1 and age2). As soon as thge first process is completed, the second one begins. I want to calculate the time it takes for the both processes to be completed. I have the following script which gives me the answer, butI think there must be a more elegant way of doing the calculations

Full_Name: Ed Borasky Version: R-beta 2.1.0 2005-04-08 OS: Linux 2.6.11 GCC 3.3.5 Submission from: (NULL) (24.21.57.139) I downloaded the latest R-beta tarball and did a build with the default options. OS is Linux 2.6.11 and compiler is GCC 3.3.5. "make check-all" failed with the following message: make[3]: Entering directory `/home/znmeb/R-beta/tests' running code in

Good Morning We are planning a Windows 2003 migration project through out our company and we are currently using SAMBA on the following platforms. to communicate with our NT servers, MPE/ix 6.5 pp2 and 7.0 HP-UX 11i Linux RedHat 9 Can you please advise which SAMBA version should we install for each of the above O/S's and where we may download these from? Many Thanks David Jason Senior Systems Administrator Metropolitan Health Group Cape Town Ph Office + 27214804784 Fax +27214...

Dear all, I'm looking for primary help at aggregating table() results and at writing a loop (if useful) My dataset ( http://goo.gl/gEPKW ) is composed of 23k rows, each one representing a point in the space of which we know the land cover over 10 years (column y01 to y10). I need to analyse it with a temporal sliding window of 5 years (y01 to y05, y02 to y06 and so forth) For each period

Hello We are running samba on SGI/SUN/HP fileservers. We saw a problem on the SGI fileservers. After a while a lot of defunct smbd deamons were hanging and occupying the slots in the process table. We saw the problem with IRIX 5.2 and samba 1.9.16p11 and IRIX 6.2 and samba 1.9.17.p4 . Has anybody seen this problem before? This is a serious problem, because the smbd daemons are filling the

...identemente tiene distintas estructuras en el archivo de base, de las cuales R toma una inoportuna para mi. Si alguien tiene una idea al respecto, es bienvenida. Por ejemplo, parece que sería de utilidad poder indicar el parámetro sep="," cuando, una vez importados los datos, indico: pami$PP2 <- as.numeric(pami$PP) # o pami$PP2 <- as.numeric(as.character(pami$PP)) porque en ambos casos, devuelve NA.- Como concepto, me sirvió ver: https://www.r-bloggers.com/using-r-common-errors-in-table-import/ y también: https://martinsbioblogg.wordpress.com/2013/03/24/using-r-reading-tables-that...

Dear R users, I have a function (below) which encompasses several tests. However, when I run it, only the output of the last test is displayed. How can I ensure that the function root(var) will run and display the output from all tests, and not just the last one? Thank you, b. root <- function(var) { #---Phillips-Perron PP.test(var, lshort = TRUE) PP.test(var, lshort = FALSE)

En general lo que yo uso en esos casos es as.numeric(as.character(X)) No se los términos correctos pero los factores aunque se muestren con los nombres de las diferentes clases, internamente son clases separadas que se nombran como enteros por ejemplo del 1 al n de clases. Cuando usas directamente as.nuemric sobre un factor, este toma los numeros de las clases y no el valor de clase. Fijate en

...tderr, _("glob: guestfs_glob_expand call failed: %s\n"), + argv[i]); + goto error0; } /* If there were no matches, then we add a single element list * containing just the original argv[i] string. */ if (pp[0] == NULL) { - char **pp2; - - pp2 = realloc (pp, sizeof (char *) * 2); - if (pp2 == NULL) { - perror ("realloc"); - free (pp); - goto error0; - } - pp = pp2; - - pp[0] = strdup (argv[i]); - if (pp[0] == NULL) { - perror ("strdup"); - free (pp); - goto error0; - } - pp[1] = NULL; + cha...

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