Displaying 1 result from an estimated 1 matches for "pourcentag".
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pourcentage
2007 Jun 06
2
names not inherited in functions
...)),chiffr)
rownames(chiffr) <- NULL
chiffr <- data.frame (nom.chiffr, chiffr)
return(chiffr)
}
res <- rep(NA, 4)
for (i in 1 : ncol(tablo))
res <- rbind(res,descriptifvar(tablo[,i]))
colnames(res) <- c("variable", "niveau", "effectif", "pourcentage")
return(res[-1,])
}
# NB I used this function on a data.frame with only factors in