Displaying 20 results from an estimated 75 matches for "polynome".
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polynom
2007 Nov 06
1
How to find the zero (only the real solution) with the package polynom ?
Hello,
I have 3 columns : a, b and a*b
I would like to find the pair (a,b) so that a*b is the minimum but not from
the points I measured but from the fit of the curve (I have more points that
the ones given below but I fit only on this part because I
know that the minimum a*b is in this interval).
I thought doing it this way :
- to fit a*b=f(a)
abfit<-lm(ab ~ poly(a,8,raw=T))
- to use the
2004 Jun 25
4
Bug in parse(text = <long polynom>) (PR#7022)
Merci beaucoup, Jean,
for the bug report -- which I'm no "completeing" to R-bugs
>>>>> "Jean" == Jean Coursol <coursol@cristal.math.u-psud.fr>
>>>>> on Thu, 24 Jun 2004 15:22:37 +0200 (CEST) writes:
Jean> I was exploring the polynom library with students:
<and found a segmentation fault from parsing a long expression>
2000 Aug 31
1
Install polynom pack
Dear R people:
I am trying to download the package polynom to R version 1.0.1.1.
on Windows.
Here are my commands and output:
> install.packages("polynom",lib="c:\rw1011\library",CRAN="http://www.r-project.org/src/contrib/")
Error in start[k]:(start[k + 1] - 1) : NA/NaN argument
In addition: Warning message:
Download had nonzero exit status in:
2003 Jul 10
2
please help on frag polynoms
hi there,
can anyone help me on the topic of frag polynoms?
i just heard of a friend of mine, that i could build in a functioon called
fragpoly (he was talking of such a function in the 'stata' language) in order
to improve my process of finding an optimal linear model.
instead of trying a vast amount of transformed inputdata to find the best
fit and then step backwards down to e.g.
2008 Mar 07
5
Puzzling coefficients for linear fitting to polynom
Hi,
I can not comprehend the linear fitting results of polynoms. For
example, given the following data (representing y = x^2):
> x <- 1:3
> y <- c(1, 4, 9)
performing a linear fit
> f <- lm(y ~ poly(x, 2))
gives weird coefficients:
> coefficients(f)
(Intercept) poly(x, 2)1 poly(x, 2)2
4.6666667 5.6568542 0.8164966
However the fitted() result makes sense:
>
2002 May 10
1
updata.packages()
Something strange is happening with update.packages on my machine (Win2000,
R-1.5.0 installed from binaries). Some of the packages (see below) keep
getting updated every time. When I issue update.packages() I get this
every time for the last few days (I think since I installed 1.5 and the
packages but I am not sure). This happens with CRAN shown below and also
with CRAN set to
2002 May 01
1
polynom division
Dear R-users,
is there any package that allows for a division of two polynomials?
Regards,
M. Fischer
Dr. Matthias Fischer
Friedrich-Alexander-Universit?t Erlangen-N?rnberg
Lehrstuhl f?r Statistik und ?konometrie
Lange Gasse 20
90403 N?rnberg
Telefon: 0911 / 5302-271
Telefax: 0911 / 5302-277
E-Mail: Matthias.Fischer at wiso.uni-erlangen.de
1997 Apr 24
0
R-alpha: polynom add-on
I've packaged Bill's polynom add-on for R (i.e., converted man pages and
took care of TITLE and INDEX). Apart from the missing poly() everything
should be fine ...
The package can be found in the CRAN src/contrib area.
I've also added it to the Debian ix86 r-contrib package.
-k
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r-devel mailing list --
2006 Feb 22
1
Gram-Charlier series
Good day everyone,
I want to use the Gram-Charlier series expansion to model
some data. To do that, I need functions to:
1) Calculate 'n' moments from given data
2) Transform 'n' moments to 'n' central moments, or
3) Transform 'n' moments to 'n' cumulants
4) Calculate a number of Hermite polynomials
Are there R-functions to do any of the above?
2002 Oct 09
5
polynomial
Any better (more efficient, built-in) ideas for computing
coef[1]+coef[2]*x+coef[3]*x^2+ ...
than
polynom <- function(coef,x) {
n <- length(coef)
sum(coef*apply(matrix(c(rep(x,n),seq(0,n-1)),ncol=2),1,function(z)z[1]^z[2]))
}
?
Ben
--
318 Carr Hall bolker at zoo.ufl.edu
Zoology Department, University of Florida http://www.zoo.ufl.edu/bolker
2002 Aug 05
1
polynom Fit
Please, I'm a beginner with the R language. I'm looking for a function to
compute a Polynomfit for simple x-y Data. Who can help?
Many Greetings
E.A. Welge
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2008 May 24
0
solving 10oth-order polynom
I'm one of the many who is far more interested in the reason for the
request than in the numerical method to use. The way I see it, the
methodology of, say, polyroot() suffices in a mathematical sense. If
your coefficients are mathematically exact (as opposed to measured
values), the near-singularities and such don't really matter, assuming
infinite precision math. So, what
2010 Dec 07
0
R programing help-newton iterations for the square root
From: jypuppy36@hotmail.com
To: r-help-bounces@r-project.org
Subject: R programing help-newton iterations for the square root
Date: Tue, 7 Dec 2010 12:00:01 -0800
NEWTON ITERATIONS FOR THE SQUARE ROOT
Newton iterations to find the root of a real valued function f , i.e. a number x for which f (x) = 0, are of the form
Example. To find the square root of a positive number y we can use
2007 Nov 07
3
Can I replace NA by 0 (if yes, how) ?
Hello,
I'm trying to fit some points with a 8-degrees polynom (result of lm is
stored in pfit).
In most of the case, it is ok but for some others, some coefficients are
"NA".
I don't really understand the meaning of these "NA".
And the problem is that I can't perform a derivation
(pderiv<-as.function((deriv(polynomial(pfit$coefficients))))) on pfit due to
the
2003 Mar 04
3
linear model with arma errors
Dear all,
I'm looking for how can I estimate a linear model with ar(ma) errors :
y(t)=a*X(t)+e(t) with
P(B)e(t)=Q(B)u(t)
where u is a white noise and P, Q are some polynomes.
Could you help me ?
Gr?gory Benmenzer
2005 Aug 08
2
coefficient of polynomial expansion
Hi,
I would like to get the coefficient of polynomial expansion. For example,
(1+ x)^2 = 1 + 2x + x^2, and the coefficients are 1, 2 and 1.
(1 + x + x^2)^3 = 1 + 3*x + 6*x^2 + 7*x^3 + 6*x^4 + 3*x^5 + x^6, and
the coefficients are 1, 3, 6, 7, 6, 3, and 1.
I know that we can use polynom library. Is there any other way to do
it without loading a library.
Thanks a lot for your help.
Peter
2006 Jun 13
1
poly(*,*) in lm() (PR#8972)
Full_Name: Jens Keienburg
Version: 2.3.0
OS: Windows XP
Submission from: (NULL) (193.174.53.122)
I used the function lm() to calculate the coefficients of a polynome. If I used
the function poly(t,2) to denote a polynome of form 1 + x + x^2, the
coefficients are wrong. I appended an excerpt below:
> t=1:100
> p=-20 - 10 * t + 2 * t^2
> p
[1] -28 -32 -32 -28 -20 -8 8 28 52 80 112 148
188 232 280 332 388 448...
2007 Mar 13
1
estimating an ARIMA model with constraints
Hi,
I am trying to estimate an ARIMA model in the case where I have some
specific knowledge about the coefficients that should be included in the
model. Take a classical ARIMA (or even ARMA) model:
P(B) X(t) = Q(B) epsilon(t),
where X(t) is the data, epsilon is a white noise, B is the backward operator
and P and Q are some polynoms. Additionally, assume that you know in advance
how P and Q
2010 Oct 14
1
Fw: Problem to create a matrix polynomial
Awaiting some suggestion. Was my question not very understandable? Please let me know how can I offer more elaborate clarification.
Additionally, I would like to solve the determinant of "p1" for the values of "z" (I am working with some multivariate time series modelling). When I use det() function, it am getting error that, that function is not for objects with class
2004 Dec 03
5
how can I get the coefficients of x^0, x^1, x^2, . , x^6 from expansion of (1+x+x^2)^3
Hi,
I would like to get the coefficients of x^0, x^1, x^2, . , x^6 from
expansion of (1+x+x^2)^3.
The result should be 1, 3, 6, 7, 6, 3, 1;
How can I calculate in R?
You help will be greatly appreciated.
Peter
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