search for: podling

Hallo Excel attachment is not allowed here, but shading area is answered many times elsewhere. Use something like . "shading area r" in google. See eg. https://www.geeksforgeeks.org/how-to-shade-a-graph-in-r/ Cheers Petr -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of George Brida Sent: Wednesday, March 1, 2023 3:21 PM To: r-help at

On 21/03/2023 9:58 a.m., PIKAL Petr wrote: > Hallo Duncan > > Tested but does not work so something other must be wrong. > > R version 4.2.2. >> installed.packages()[,"Package"] > base boot class cluster codetools compiler datasets foreign graphics grDevices grid KernSmooth

As Peter says, the list is very cautious about what types of files it allows. A handy way to supply some sample data is the dput() function. In the case of a large dataset something like dput(head(mydata, 100)) should supply the data we need. Just do dput(mydata) where *mydata* is your data. Copy the output and paste it here. On Wed, 1 Mar 2023 at 09:58, PIKAL Petr <petr.pikal at

Good morning, I would like to send you a bug with openssh for windows - versions OpenSSH_3.7.1p1, SSH protocols 1.5/2.0, OpenSSL 0.9.7b 10 Apr 2003 OpenSSH_3.8.1p1, OPENSSL 0.9.7.d 17 Mar 2004 When I try to execute a remote command via ssh from unix machine to windows machine with openssh installed, the return code of ssh is always 0 even if remote command fails. Example : ssh initiated

hi,all: I come here to consult that whether FFmpeg could be replaced with Theora in our project. Here the thing. Our project, Bluesky( http://incubator.apache.org/projects/bluesky.html) is podling in Apache incubation. However, core function of our system, the encode/decode part which implemented by FFmpeg(GPL licensed)(we mainly use libavcodec and libavformat library), conflicts with Apache Software License. Thus we have to remove FFmpeg and find a subsittute. People at Apache community rec...

Dear R users, I have an xlsx file (attached to this mail) that shows the values of a "der" series observed on a daily basis from January 1, 2017 to January 25, 2017. This series is strictly positive during two periods: from January 8, 2017 to January 11, 2017 and from January 16, 2017 to January 20, 2017. I would like to plot the series with two shaded areas corresponding to the

Hi I am not sure if it is more readable > paste(paste(unlist(strsplit(x,"")),".", sep=""), collapse="") [1] "1.0.1.1.0.1.1.1." If you did not want last dot, it is a bit shorter. > paste(unlist(strsplit(x,"")),collapse=".") [1] "1.0.1.1.0.1.1.1" > Cheers Petr Tento e-mail a jak?koliv k n?mu p?ipojen?

Dear Petr, Thanks for your reply and the solution. The example dataset contains data for the first six days of the year 1986. "X1986.01.01.10.30.00" is 01 January 1986 and the rest of the variable is redundant information. The last date is given as "X2016.12.31.10.30.00". I realized that I missed one information in my previous email, I would like to compute the weekly average

Hi Based on your explanation I would advice to use ?cut.POSIXt with breaks "week". However your data are rather strange, you have data frame with names which looks like dates names(test) [1] "X1986.01.01.10.30.00" "X1986.01.02.10.30.00" "X1986.01.03.10.30.00" [4] "X1986.01.04.10.30.00" "X1986.01.05.10.30.00"

Dear all, I have daily data in wide-format from 01/01/1986 to 31/12/2016 by ID. I would like to convert this to weekly average data. The data has been generated by an algorithm. I know that I can use the lubridate package but that would require me to first convert the data to long-form (which is what I want). I am at a bit of loss of how to extract the date from the variable names and then

Hi -- I'm looking for alternatives to regex for a fairly simply 'reformatting' problem. Alternatives only because a lot of folks have trouble parsing/interpreting regex expressions, and I'm looking for suggestions for something more 'transparent'. Here is an example of what I'm trying to do. Take the following string, which I call x, and for each character in the

Forgot the year if you also want to summarise by that. > x <- structure(list(X1986.01.01.10.30.00 = c(16.8181762695312, 16.8181762695312, + 18.8294372558594, 16 .... [TRUNCATED] > library(tidyverse) > library(lubridate) > # convert to long form > x_long <- gather(x, key = 'date', value = "value", -ID) > #

Dear Rcommunity, I hope this email finds you well. I am writing to seek your assistance with a data visualization problem I am facing while working with R. Problem Description: I have a dataframe named "df" containing the following columns: "longitude", "latitude", "sea_currents_mag", and "sea_currents_direction". The dataframe includes sea

OpenPGP Public Key Server For questions or comments regarding this key server site, contact PGP Key Server Administrator <pks@gpg.cz> Current version: 0.9.4+patch2+JHpatch2 NOTE! This service is provided to facilitate public-key cryptography for demonstration and educational purposes. It is the responsibility of users of public-key cryptography to ensure that their activities conform to

OpenPGP Public Key Server For questions or comments regarding this key server site, contact PGP Key Server Administrator <pks@gpg.cz> Current version: 0.9.4+patch2+JHpatch2 NOTE! This service is provided to facilitate public-key cryptography for demonstration and educational purposes. It is the responsibility of users of public-key cryptography to ensure that their activities conform to

OpenPGP Public Key Server For questions or comments regarding this key server site, contact PGP Key Server Administrator <pks@gpg.cz> Current version: 0.9.4+patch2+JHpatch2 NOTE! This service is provided to facilitate public-key cryptography for demonstration and educational purposes. It is the responsibility of users of public-key cryptography to ensure that their activities conform to

OpenPGP Public Key Server For questions or comments regarding this key server site, contact PGP Key Server Administrator <pks@gpg.cz> Current version: 0.9.4+patch2+JHpatch2 NOTE! This service is provided to facilitate public-key cryptography for demonstration and educational purposes. It is the responsibility of users of public-key cryptography to ensure that their activities conform to

?Startup says: "Note that when the site and user profile files are sourced only the base package is loaded, so objects in other packages need to be referred to by e.g. utils::dump.frames or after explicitly loading the package concerned." So you need utils::installed.packages and utils::install.packages . Duncan Murdoch On 21/03/2023 8:04 a.m., PIKAL Petr wrote: > Dear all.

Friends, I am doing a URL classification, based on certain key words whether it contains an executive information or not. I have already went through 50K URL's and identified the key words and made it as 0, 1 ( 0 - do not have the key word and 1 - have the key word) and 0- do not contain executive information 1 - contains executive information. A sample set of data is shown below. DomainID

Hi all; I need to put 12 different plot2 into the same matrix. So my array for the matrix will be par(mfrow=c(3,4)). I am running ggplot2 to produce my 12 plots. For some reason, par(mfrow=c(3,4)) did not turn out 3*4 matrix. my basic R codes for each plot is par(mfrow=c(3,4)) library(ggplot2) p <- ggplot(a, aes(x=Genotypes, y=Plant_hight, size=Plant_hight, color=Showing_rate)) + . . Best