search for: pm25

Hi - I am trying to find and describe missing data in a time series. For instance, in the library openair, there is a data frame called "mydata": library(openair) head(mydata) date ws wd nox no2 o3 pm10 so2 co pm25 1 1998-01-01 00:00:00 0.60 280 285 39 1 29 4.7225 3.3725 NA 2 1998-01-01 01:00:00 2.16 230 NA NA NA 37 NA NA NA 3 1998-01-01 02:00:00 2.76 190 NA NA 3 34 6.8300 9.6025 NA 4 1998-01-01 03:00:00 2.16 170 493 52 3 35 7.6625 10.2175 NA 5 1998-01-01 04:00:00 2.40 180...

Hi all -- I am working on 64-bit Windows XP. I'm not a very technical person when it comes to the command line stuff, so please forgive me if this is a stupid question. I have a bunch of HDF files, and I want to dump a single PM25 data layer from each file to .txt by invoking ncdump.exe from system(). Here's a sample command string: "C:/ncdump -v PM25 C:/01aug2010.hdf > C:/01aug2010.txt" This works perfectly in Python, but does not actually generate the .txt file in R when: system(command) It does show...

...tunately, you failed to show us the critical information necessary to give you a definitive answer: the structure of a single record. However, I will wing it based on your description and assume that each record contains the following information something like this: Latitude Longitude Date Time pm25 + other stuff maybe. If this is the case, 1) You do not need to sort anything. R has robust date-time manipulation and computation capabilities to handle dates and times, though in this case you only need dates. R knows all about how to order dates and times. 2) You do not have to physically gro...

...pitalized G, P and S) and pollutant name. Names with no ?L? prefix or 01/04 suffix are lag 0. Lag 01 is average of lag 0 and 1, and 04 is average of 0 to 4 days. How can one do that in R? I will ignore the other components( e.g. 10 , max or mean) Current stand L1o3maxG10 L1o3P10 L2o3G10 noxP10 pm25S_01 comeanS_03 noxP_04 What I want to get : pollutant Lag station o3 1 G o3 1 P o3 2 G nox 0 P Pm25 01 S co 03 S nox 04 P Thanks -- View this message in context: http://r.789695.n4.nabble.com/Split-data-frame-and-create-a-new-column-tp4649683.html Sent from the R help mailing list archive...

Hi Gustav, Try this: lapply(1:length(models),function(i) lapply(models[[i]],function(x) summary(x)$coef[2,]))[[1]] #1st list component [[1]] #??? Estimate?? Std. Error????? z value???? Pr(>|z|) # pm10 #5.999185e-04 1.486195e-04 4.036606e+00 5.423004e-05 #[[2]] #??? Estimate?? Std. Error????? z value???? Pr(>|z|) #ozone #0.0010117294 0.0003792739 2.6675428048 0.0076408155 #[[3]] #???