Displaying 5 results from an estimated 5 matches for "ploc".
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2007 Jul 08
1
generating a data frame with a subset from another data frame
R gurus,
I have a data set that looks something like this:
Site Species DBH #Vines
G PLOC 45.9 4
G ACNE 23.3 1
G ACNE 12.0 0
G FRAM 35.9 5
G AEGL 11.2 2
N PLOC 77.3 12
N JUNI 78.6 7
N ACNE 18.9 1
N ACNE 15.7 3
N ACRU 35.5 4
H ACSA2 24.1 6
H ULAM 35.2 7
There are 730 individual trees (22 species) from four sites in the
actual data set. I would like to create a second data frame that...
2010 Jan 07
1
LD50 and SE in GLMM (lmer)
...ol)
hat <- limfo$hat
se <- limfo$se
x <- limfo$x
upper <- hat+se
lower <- hat-se
ord <- order(x)
plot(x, hat, yaxt="n", type="l", xlab=nam, ylab="")
rug(x)
lines(x[ord], lower[ord])
lines(x[ord], upper[ord])
ploc <- c(0.01, 0.05, 0.1, 0.2, 0.5, 0.8, 0.9)
axis(2, at=log(ploc/(1-ploc)), labels=paste(ploc), las=2)
}
## Usage
model4 <- lmer (y~time + (1|blc/instar),family=binomial)
ciplot(obj=model4)
Linda Buergi
Environmental Science, Policy and Management
UC Berkeley, Berkeley, Californ...
2012 Aug 06
2
Identify points that lie within polygon
I have a complex 2D polygon with thousands of vertices, and I'd like to be
able to identify points from a large set contained within the polygon, and
was wondering if there might be an efficient way of doing this? Any advice
would be useful! Here is a small example of what I mean:
# make polygon
v1<-c(0,1,1,2,1,3,6,7)
v2<-c(1,3,3,5,6,7,8,9)
plot(v1, v2, type = "n" )
2008 May 07
3
predict lmer
Hi,
I am using lmer to analyze habitat selection in wolverines using the
following model:
(me.fit.of <-
lmer(USED~1+STEP+ALT+ALT2+relM+relM:ALT+(1|ID)+(1|ID:TRKPT2),data=vdata,
control=list(usePQL=TRUE),family=poisson,method="Laplace"))
Here, the habitat selection is calaculated using a so-called discrete
choice model where each used location has a certain number of
alternatives
2007 Aug 31
1
Strange behavior using subset
...gt; Warning messages:
> 1: longer object length
> is not a multiple of shorter object length in: is.na(e1) | is.na(e2)
> 2: longer object length
> is not a multiple of shorter object length in: `==.default`
> (Species, c("ACNE", "ACSA2", "JUNI", "PLOC", "ULAM"))
If I then only select for two species instead of five, the error
messages disappear HOWEVER, the data will be cut in half, so the new
data frame only contains 13 records of species 1 (instead of 26 as in
the original) and 12 records of species 2 (instead of the orig...