Displaying 14 results from an estimated 14 matches for "pi0".
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2003 Dec 30
1
floor of n observations in number generators
...already been mentioned.
If you use a calculation to generate n observations in random number
generators and you don't round to the nearest integer you may be
generating n-1 numbers not n numbers as you thought depending on the
storage precision of the calculation.
e.g.
> m <- 1000
> pi0 <- 0.9
> length(rnorm(m * (1-pi0)))
[1] 99 # Should be 100
> options(digits=16)
> m * (1-pi0)
[1] 99.99999999999997
> identical(m*(1-pi0), 100)
[1] FALSE
Random number generation generates the floor of n observations, this
feature occurs on R-1.8.1 on linux Redhat8, and winXP (also...
2006 Oct 02
1
qvalue
Dear colleagues,
This is not strictly a R question, but I hope it is ok to ask on the
list.
I fed a vector of p-values from about 20 million anova tests to the
package q-value and obtained this output:
> qsummary(asso_p.qvalue)
Call:
qvalue(p = asso_p.vec)
pi0: 1
Cumulative number of significant calls:
<1e-04 <0.001 <0.01 <0.025 <0.05 <0.1 <1
p-value 22711 59067 262103 551316 1013241 1936797 20048103
q-value 3554 5211 9275 12807 16951 24557 20048103
I can see that there are many hits with very s...
2011 Apr 18
1
qvalue
I am using storey's qvalue package but I keep on getting errors. Why is
this?
> qvalue(p, lambda=0.5)$pi0
[1] "ERROR: p-values not in valid range."
Error in qvalue(p, lambda = 0.5)$pi0 :
$ operator is invalid for atomic vectors
--
Thanks,
Jim.
[[alternative HTML version deleted]]
2010 Feb 11
1
histogam plots
...range in a xy plot for several
plots, instead of specifying
them for each plot.
The following is my code for generalizing the matrix and draw the
histogram.
############gen is the function to generate the dta
gen <- function(m, rho) {
library(MASS)
set.seed(103)
theta <- 0
theta1 <- 2
pi0 <- 0.9
mzero <- pi0*m
mean <- c(rep(theta, mzero), rep(theta1,m-mzero))
J <- rep(1, m)
var <- function(rho) {(1-rho)*diag(m)+ rho*J%*%t(J)}
t <- mvrnorm(1, mean, var(rho))
return(t)
}
####### w is the matrix. A histgram is drawn for each of the rows.
n <...
2012 Apr 24
2
Some Help Needed
Dear all,
I need to do some calculation where the code used are below. I get
error message when I choose k to be large, say greater than 25.
The error message is
"Error in integrate(temp, lower = 0, upper = 1, k, x, rho, m) :
the integral is probably divergent".
Can anyone give some help on resolving this. Thanks.
Hannah
m <- 100
alpha <- 0.05
rho <- 0.1
F0
2004 Dec 20
1
Re: [BioC] limma, FDR, and p.adjust
...the same result as specifying a
Q-value in the fdr function itself calculating a false discovery rate threshold alpha level so that FDR<=Q.
So it adjusts for all FDR desired levels. If your p-value threhold is 0.05 then the expected proportion of false discoveries is 5%.
e.g.
n <- 1000
pi0 <- 0.5
x <- rnorm(n, mean=c(rep(0, each=n*pi0), rep(3, each=n - (n*pi0))))
p <- 2*pnorm( -abs(x))
p <- sort(round(p,3))
p.adjusted <- p.adjust(p, method="fdr")
# Controlling fdr at Q, and p.adjust at level alpha
Qvalue <- alpha <- 0.05
threshold <- fdr(p, Q=Qv...
2024 Sep 15
2
Weekend Puzzle: computer posing as an UPS
...er *AND* wait for clients (like upsmon running on the Pi) to
> disconnect before proceeding with its own power-off/reboot.
Wow, I never would have guessed that this is a workable approach
(running the Pi this way not the nut part). Do you have ports that are
more than 500 mA, and does the Pi (pi0?) really work with 5V 500 mA?
2004 Dec 20
1
[BioC] limma, FDR, and p.adjust
You asked the same question on the Bioconductor mailing list back in August. At that time, you
suggested yourself a solution for how the adjusted p-values should be interpreted. I answered
your query and told you that your interpretation was correct. So I'm not sure what more can be
said, except that you should read the article Wright (1992), which is cited in the help entry for
p.adjust(),
2020 May 22
0
Speexdsp --enable-neon doesn't compile on 64bit
Complains about missing Int16 functionality.
So for 64bit on Arm you have to compile without –enable-neon and that has a huge effect on the AEC functionality.
The Pi3 with neon is just struggling with the AEC routines as its audibly better on a Pi4 but its not the garble that a Pi0 produces.
Without the neon on the Pi3 the 1.2 – 1.85 perf boost of neon with FFT is lost and it really effects AEC effectiveness.
There are quite a number of low cost ArmSocs now all approx. Pi3 level and above that really benefit from neon support with FFT.
Arm have specific Libs for this
https:...
2024 Sep 15
1
Weekend Puzzle: computer posing as an UPS
Cheers all,
I am experimenting with a Raspberry Pi, and it is fed from my PC
(Debian-ish Linux) that is in turn protected by an UPS - so runs NUT.
As far as the Pi is concerned, the bigger computer is its wall power
source (provides the USB socket) and being a smart machine with NUT
running, it could pose as an UPS itself. That is, if the big computer is
going to shut down (including
2024 Sep 15
1
Weekend Puzzle: computer posing as an UPS
Cheers all,
I am experimenting with a Raspberry Pi, and it is fed from my PC
(Debian-ish Linux) that is in turn protected by an UPS - so runs NUT.
As far as the Pi is concerned, the bigger computer is its wall power
source (provides the USB socket) and being a smart machine with NUT
running, it could pose as an UPS itself. That is, if the big computer is
going to shut down (including
2011 Jun 27
1
Hardy Weinberg Simulation
...is a 2 x 3
and 80% pf the tables are true nulls and 20% are non-nulls. The nulls follow
the Hardy Weinberg distribution (ratio) 1:2:1.
I have the code below but the p-values are not what I am expecting. I want
to use the Cochran Armitage trend test to get the p-values.
num.reps=10
num.vars=1000
pi0 = 80
num.subjects = 100
#Create list control list.control and list.treatment
#Minor alleles will be from (0.10, 0.30)
#num.subjects is the number of subjects in each
datamat = matrix(0,num.vars,3)
list.treat <- vector("list", 1) # create list
for (i in 1: num.reps)
{
list.treat[[i]]...
2017 May 24
3
Three new releases
Hi,
I'm announcing two new releases of opus, along with the first release of
the new libopusenc library.
First for opus, we just fixed a bad bug in the surround encoding code
that would cause very bad quality on signals beyond a certain amplitude.
Thanks to Franziska Trojahn and others from HfT Leipzig for finding this
issue through their listening test[1] (the quality of the two bad files
2008 Jun 30
4
Rebuild of kernel 2.6.9-67.0.20.EL failure
Hello list.
I'm trying to rebuild the 2.6.9.67.0.20.EL kernel, but it fails even without
modifications.
How did I try it?
Created a (non-root) build environment (not a mock )
Installed the kernel.scr.rpm and did a
rpmbuild -ba --target=`uname -m` kernel-2.6.spec 2> prep-err.log | tee
prep-out.log
The build failed at the end:
Processing files: kernel-xenU-devel-2.6.9-67.0.20.EL
Checking