Displaying 20 results from an estimated 54 matches for "pharmaci".
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pharmacy
2009 Mar 31
0
USA Pharmacy Discount ID 443
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2006 Dec 13
1
Questions about saving output files and popup
Hi all:
After calculating in R I want to show the answer and some explanations not
graphic plots in another new device and then save it as txt.file. However, I
couldn't find any package or command to do it yet. I know some commands about
generating graphics on different types of display or printing device. ex :
windows(), postscript(), pdf() and etc. But these all works for graphic plots,
2012 Oct 24
2
Recode function car package erases previous values
Hi all,
I am attempting to create a new variable based on values of other variables. The variable is called pharm. It basically takes the numeric code of 1 as yes and 0 to be No from the variable B20_C1 (a question on a survey). However, I would also like to have a level for non-respondents and these are captured in the variable nr.B20C, which is a 1 when there is a non-response on the whole group
2018 May 22
0
remove rows of a matrix by part of its row name
Hello,
Please always cc the list.
As for the question, yes, it does. If you want to remove just the ones
with exactly 73.1 use the pattern
grep("^73\\.1$", etc)
Explanation:
Beginning of string: ^
End of string: $
Escape special characters: \\ (needed because the period is a special
character.)
Hope this helps,
Rui Barradas
On 5/22/2018 12:50 PM, Ahmed Serag wrote:
> Thank
2011 Feb 28
1
Robust variance estimation with rq (failure of the bootstrap?)
I am fitting quantile regression models using data collected from a
sample of 124 patients. When modeling cross-sectional associations, I
have noticed that nonparametric bootstrap estimates of the variances
of parameter estimates are much greater in magnitude than the
empirical Huber estimates derived using summary.rq's "nid" option.
The outcome variable is severely skewed, and I am
2018 May 22
4
remove rows of a matrix by part of its row name
Dear R-experts,
How can I remove a certain feature or observation by a part of its name. To be clear, I have a matrix with 766 observations as a rows. The row names are like this
70/556
71.1/280
72.1/556
72.1/343
73.1/390
73.1/556
Now I would like to remove all the rows that contain the text 73.1
Any ideas or suggestion please ?
Regards
**********************
Ahmed Serag
Analytical
2015 Jun 16
1
FXS Solutions for modems and other non jitter tolerant devices
Jon Pounder wrote:
>
>
<snip>
> Fax is really the only need recently, and even that has alternatives like emailing scans that most people prefer now.
>
The legal and medical communities still seem to prefer faxing, in the ( mistaken? ) belief that it is more secure. In fact the medical community is fearful of the legal beagles.
These groups are really slow to change.
At least in
2002 Jun 14
1
ODESOLVE
Dear All,
I am experiencing a difficulty with the "lsoda" function in ODESOLVE
library; my differentiation function contains a covariate changes with time,
and I don't know how to incorporate that without using loops and so on. Does
anyone know how to do it?
Your help will be very much appreciated!!
In-Sun
In-Sun Nam
School of Pharmacy and Pharmaceutical Sciences
University of
2006 May 17
1
Example Syntax for if - then- and - else Statements
Hello R users,
I am a fairly new R user, however, one of the problems I am having is
the use of applying if-, and-, then-, else- statements in R against
datasets & dataframe. Rtips mentions it, but without simple examples I
am not quite sure what my syntax should look like. I am particularly
interested in syntax that can be used with the transform function. for
example
if foo[,1] ==
2007 Oct 22
1
loess coefficients output
May I inquire about how to obtain the coefficients from a loess fit of
multiple covariates? I have tried terms and coef, but it does not provide
me with the coefficients to identify the terms of the entire regression
equation.
Many thanks
Paul
--
Paul R. Hutson, Pharm.D.
Associate Professor
UW School of Pharmacy
777 Highland Avenue
Madison WI 53705-2222
2009 Jul 15
1
interacting variables in a formulae in R
Dear R Mailing Subscribers,
I just have a question of how R handles interacting variables in model
creation using glm for instance.
if I write :
>>
model=glm(solution~descriptor1+descriptor2+descriptor3,family=binomial(link="logit"))
I should end up with coefficients for a logistic model that I can introduce
easily in the mathematical form of such a model (weighted sum of
2011 Apr 04
0
AIC for robust regression
I am interested in comparing the fit of robust (i.e., S and MM) and
non-robust (i.e., OLS) estimators when applied to a particular data set.
The paper entitled "A comparison of robust versions of the AIC based on M, S
and MM-estimators" (available at:
http://ideas.repec.org/p/ner/leuven/urnhdl123456789-274771.html) presents
formulas for robust Akaike information criteria (AIC) for the M,
2011 Nov 08
1
Rename a directory in R
Hi,
I want to be able to rename a folder using R, similar to file.rename. I want to paste " - done" onto the folder name. The reason for this is we run a loop on a large number of folders on a server and it would be nice for people to be able to log in and instantly see if their data has been processed so they can remove it.
I have searched the help list but have not found anything and
2006 Dec 30
1
Odd hangup problem TDM400P
On an Asterisk 1.2.12.1 system using a TDM400P with two FXO and two FXS modules, servicing two POTS lines:
When dialing a number, such as a bank, or pharmacy, where it is required to enter a long series of numbers via the phone's keypad, an unexpected hangup occurs.
The hangup does *not* occur when entering the numbers, as one might initially expect, but after the called end begins to
2010 Jul 01
1
Samba as a Client Accessing Windows 2008 Roaming Profiles
Hello,
I am using Samba on Linux as a CLIENT which is accessing Windows Server 2008
and I am trying to setup roaming profiles on the Linux/Samba client. My
Linux distribution is openSUSE 11.3 RC1/Factory and YaST does a very good
job at setting up Kerberos/Samba to join the domain. It all seems to work,
except the Linux profile isn't synchronized back to the Windows domain
server. I assume
2012 May 04
1
colours in a pdf
Hi,
I'm plotting PDFs and have a problem. If I have more than 8 sources of data the colours are repeated. These plots are used to remove poor data from the sets so it would be helpful if I could expand the colour range. Is there any way to do this?
The plots are coloured by defining a vector colsVec<-1:(length(mzXMLfiles))
And defined in the loop for (file in 1:length(mzXMLfiles))
as
2011 Jan 20
1
fix sign of a coefficient in formula
Dear R users & experts,
I'd like to create a model using lm (or glm) under some constraints of
how coefficients for each component could look like (sort of a range of
coefficients that should be allowed).
So let's go for an example :
model=lm(age ~ eyecolor + height, data=inputdata)
So let's suppose that R pops out a model with positive estimates for the
coefficients eyecolor
2002 Feb 19
1
Summary re: read.table on Mac OS 10
Thanks to all who responded. Not all of the advice
helped me with that particular problem, but, I have
learned a lot just from your answers.
1. R for Mac 10 (Carbon version) uses the Mac
convention of using ":" for the usual Unix "/" and thanks
to Dr. Lumley for that since I'm new to R, Mac10, Macs
in general, and Unix.
2. Interestingly, Dr. Ripley suggested to
2006 Mar 03
0
Hidden links on ROR Wiki
Hello list members,
Today I noticed on http://wiki.rubyonrails.com/rails/pages/WorkingProfessionallyWithRails that there were a ton of spam links in the source code that I couldn''t see on the page itself. Upon careful examination I found the links to be hidden:
I am posting the content here for reference and to show patterns of spam:
<u
2018 May 22
0
remove rows of a matrix by part of its row name
Hello,
Use grep to get the row indices and then subset with a *negative* index
to remove those rows.
rn <- scan(what = character(), text = "
70/556
71.1/280
72.1/556
72.1/343
73.1/390
73.1/556
")
mat <- matrix(rnorm(6*6), nrow = 6)
row.names(mat) <- rn
inx <- grep("73\\.", row.names(mat))
new_mat <- mat[-inx, ]
new_mat
Hope this helps,
Rui Barradas
On