Displaying 11 results from an estimated 11 matches for "petzev".
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petzel
2011 Apr 28
2
for loop with global variables
Hi,
is there a possibility to use global variables in a for loop. More
specifically, I want to do the following:
output.1<-rbind("a","b")
output.2<-rbind("c","d")
output.3<-rbind("e","f")
.
.
.
output.n<-rbind(...,...)
next I want to create a data frame with two columns:
Outputs
Values output.1 "a","b"
2012 Jun 23
3
Event Studies in R
Dear all
I tried finding a package for event studies but unfortunately without
success. Does anyone know which package suits best for such an analysis?
Thank you in advance.
Regards
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2011 Mar 03
2
Multivariate Granger Causality Tests
Dear Community,
For my masters thesis I need to perform a multivariate granger causality
test. I have found a code for bivariate testing on this page
(http://www.econ.uiuc.edu/~econ472/granger.R.txt), which I think would not
be useful for the multivariate case. Does anybody know a code for a
multivariate granger causality test. Thank you in advance.
Best Regards
--
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2011 Apr 28
1
AutomaticTRUE/FALSE Matrix Generation
Dear All,
I am a newbee in R an have the following problem. I have variables AB,BC,CD
to which outputs are assigned. Now AB[,1], for example, outputs a list,
which is a random combination of the following characters: "AB", "BC", "CD".
What I want to do is to build a 3x3 matrix with colnames and rownames equal
to "AB", "BC", "CD". Matrix
2011 Jun 20
6
for loop and linear models
Hi,
I have two datasets, x and y. Simplified x and y denote:
X
Y
A B C A B C . . . . . . . . . . . . . . . . . .
I want to implement all possible models such as lm(X$A~Y$A), lm(X$B~Y$B),
lm(X$C~Y$C)... I have tried the following:
fun<- function(x,y){
for(i in 1:length(colnames(x))){
for(j in 1:length(colnames(y))){
2011 Apr 04
1
Granger Causality in a VAR Model
Dear Community,
I am new to R and have a question concerning the causality () test in
the vars package. I need to test whether, say, the variable y Granger
causes the variable x, given z as a control variable.
I estimated the VAR model as follows: >model<-VAR(cbind(x,y,z),p=2)
Then I did the following: >causality(model, cause="y"). I thing this
tests the Granger causality of
2011 Apr 25
2
extracting names from matrix according to a condition
Dear Community,
I have a matrix with assigned colnames and rolnames as follows:
A B
NR 0.15 0,05
AL 0,05 0,05
. . .
. . .
. . .
I want to extract the names of the rows for which A>0,1 and B<0,1. In
the above example this would be observation NR only. Hence the output
should write for
2011 Apr 26
0
Problem with lapply and splitted variables
Dear Community,
I have the following two variables, which I have split according to a
factor:
*y1*
[1]
1
2
3 [2]
2
3
4
and
*y2*
A B [1]
1 4
2 5
3 6 [2]
2 5
3 6
4 7
Now I need the following Vector Autoregressive Models:
VAR(cbind(y1[1],y2[1]$A)), VAR(cbind(y1[1],y2[1]$B)),
VAR(cbind(y1[2],y2[2]$A)), VAR(cbind(y1[2],y2[2]$B)). My problem is that
when using this argument: lapply(y2,
2011 Apr 29
1
matrix evaluation using if function
Hi All,
I am trying to create a function which evaluates whether the values (which
are equal to one) of a matrix are the same as their mirror values. Consider
the following matrix:
> n<-matrix(cbind(c(0,1,1),c(1,0,0),c(0,1,0)),3,3)
> colnames(n)<-cbind("A","B","C");rownames(n)<-cbind("A","B","C")
> n
A B C
A 0 1 0
B
2013 Feb 11
1
store variables in a for loop using get()
Dear R list,
I have a problem in assigning values to existing data frames in R. I have a
vector x containing the names of the data frames, which I create to store
the results for each variable (a1,a2,a3) obtained in time series moving
regressions. Thus, say,
x=c('a1','a2','a3')
Moreover, b is a vector containig unique dates of the points in time of the
moving
2011 Apr 14
1
Automatically extract info from Granger causality output
Dear Community,
this is my first programming in R and I am stuck with a problem. I
have the following code which automatically calculates Granger
causalities from a variable, say e.g. "bs" as below, to all other
variables in the data frame:
log.returns<-as.data.frame( lapply(daten, function(x) diff(log(ts(x)))))
y1<-log.returns$bs
y2<- log.returns[,!(names(log.returns) %in%