search for: perlmans

I could do this in various hacky ways, but what's the right way? I have a nice application of the by function, which does what I want. The output looks like this: > auc_stress lab.samples.stress$subid: 2 cortisol amylase 1 919.05 6834.8 ---------------------------------------------------------------------------------------------------------------------------

I made this rather cool plot which I am quite pleased with: http://brainimaging.waisman.wisc.edu/~perlman/data/BeeswarmLinesDemo.pdf However, I feel there must be a better way to do it than what I did. I'm attaching the code to create it, which downloads the data by http so it should run for you if you have the current version of beeswarm installed (which was just updated today,

Hi I've just installed R on our Sun kit in the lab and on my Linux box at home. My statistical expertise is not advanced - I have completed Open University probability and statistics courses, and been using Gary Perlmans !STAT package for analyses of variance, descriptive stats, linear regression, non-parametric stats etc for 10 years or so. (so be gentle with me :-) ) However, R is clearly a much more powerful package, which is still being developed (the Perlman package appears to be static) and includes superb g...

Consider the following: > x<-list(c(1,2,3),c(4,5,6)) > x[1] [[1]] [1] 1 2 3 > x[2] [[1]] [1] 4 5 6 So far that all seems reasonable. But now there's a problem. I'm used to python, where I would say x[2][1] and get the value 4. But I can't figure out how to do that in R. > x[2][1] [[1]] [1] 4 5 6 > x[2,1] Error in x[2, 1] : incorrect number of dimensions I have

Hello, I've been searching on the web for a few hours and seem to be stuck on this. The code pasted below generates a histogram of subject responses in four different conditions in an experiment. This version of the graph is one I'm using for internal consistency checking, so I've set it up to indicate the order of the responses, which is contained in the variable StimCount. The

To whom it may concern: I spoke with Alfred Perlman today and he suggested I ask you to post this position on your site for me. Thank you in advance for your consideration! Amy Amy Loofbourow MIPS Technologies www.mips.com 408-530-5324 Amy Loofbourow Loofbourow Associates 408-569-3469 - Mobile KERNEL SW Development Engineer Although this position is posted on a FreeBSD site, we are

I am getting an error message from scatterplot: > library(car) > scatterplot(Prestige$income~Prestige$type) Error in Summary.factor(c(2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, : range not meaningful for factors In addition: Warning message: In Ops.factor(x[floor(d)], x[ceiling(d)]) : + not meaningful for factors > The command does output the kind of graph that I want (boxplots).

I have a data frame in wide format. There are six variables that represent two factors in long format 3x2, Valence and Temperature: > head(dpts) File Subj Time Group PainNeg.hot PainNeg.warm SociNeg.hot SociNeg.warm Positiv.hot Positiv.warm Errors 1 WB101_1_1_dp.txt 101 1 MNP 30.700000 13.75000 16.319048 35.166667 30.18333 14.383333 1 2