search for: pendeo

...hancements to the plot routines (albeit pretty silly enhancements). As another side note: calling rug() with color set to '#00000033' lets you see dense regions as darker than sparse regions, without having to resort to calling jitter() first. Carl -- Sent from my Cray XK6 "Pendeo-navem mei anguillae plena est."

Hi I want to generate 4 random number which sum up to 100 always Please help ----- Thanks in Advance Arun -- View this message in context: http://r.789695.n4.nabble.com/runif-with-condition-tp4278704p4278704.html Sent from the R help mailing list archive at Nabble.com.

Hi, I would like to produce a plot with a symbol on every nth point in a time series data, like the one in the following: http://www.phon.ucl.ac.uk/home/yi/ProsodyPro/EnglishFocus.png x <- seq(-100,1000,25) plot(x,type="l") Could someone help me out with the above example? Thanks.... [[alternative HTML version deleted]]

Would like to know how much data can R process - number of rows and columns? [[alternative HTML version deleted]]

...image of the original data(x vs y) that looks like plot(x,y) . Anyway, I just seem to be blanking: is there some vectorized way to place values, or even a constant value, into all elements of xymat whose row,col coordinates match ordered pairs in x and y ? Carl -- Sent from my Cray XK6 "Pendeo-navem mei anguillae plena est."

...nd(foo,bar)) x y r 1 5 4 3 2 4 5 6 Rgames> (foobar<- rbind(foobar,bar)) x y r 1 5 4 3 2 4 5 6 3 4 5 6 Rgames> (barfoo<-rbind(bar,foo)) x y r 2 4 5 6 21 5 4 3 Rgames> (barfoo<-rbind(barfoo,foo)) x y r 2 4 5 6 21 5 4 3 3 5 4 3 -- Sent from my Cray XK6 "Pendeo-navem mei anguillae plena est."

Hi everybody, I have a matrix with 3 columns (Date, MeanArea and SdArea). I want to draw a figure showing the variable MeanArea in terms of the Date. But instead to use the variable SdArea as bar error, I want to use ?polygon error?. I use this code but the output does not seem good.

Dear all I tried to find some packages (or programs) for image analysis and especially fractal dimension image analysis but so far I had not success. It shall be used for particle surface layer analysis from TEM images. Any suggestions? Best regards Petr

Esteemed colleagues I wonder if there is a package in R that performs the functions of the Excel SOLVER. Thanks in advance for the reply. Best regards, ------------------------- Estimados colegas Me pregunto si hay un paquete en R que funcione como el SOLVER de Excel. De antemano gracias por la respuesta. Saludos, -- Ricardo Bandin Llanos rbandin@udec.cl [c] Magíster Cs. m. Pesquerías

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Dear list, I have been struggling for some time now with this code... I have this vector of unique ID "EID" of length 821 extracted from one of my dataframe (skate). It looks like this: > head(skate$EID) [1] "896-19" "895-8" "899-1" "899-5" "899-8" "895-7" I would like to remove the complete rows in another dataframe

...Momadou\\Documents\\AreaMonthly.csv",sep=";",dec=",",header=TRUE) Poly y <-MeanArea x <-SdArea z <-Date matplot(x,cbind(y,z),type="n") polygon(c(x,rev(x)),c(y,rev(z)),col="grey50") Thank you in advance -- Sent from my Cray XK6 "Pendeo-navem mei anguillae plena est." ______________________________________________ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible...

Dear All, I have a bunch of data points as follows: x  100 y  200 z  300 ... where 100, 200, 300 are the values. I would like to know the distribution of my data? how can I fit my data into a distribution? Thanks a lot, Andra [[alternative HTML version deleted]]

Hi there ! I've got 7 Samples that may contain 29 differents kinds of material.... every line below corresponds to a differente kind of material, example: Sample 1, 2,3,5 and 6 has material 1 .... So I want to know how can I do a Venn Diagram with the data below .... ps ( it was generated by a csv, where every line is sep with (";")) Can someone helps me ? thanks csv file :

Everyone, I'm working with scatter plots with different colored symbols (via lattice). I'm currently using these colors for points and lines: col1 <- c(rgb(1, 0, 0), rgb(0, 0, 1), rgb(0, 1, 0), rgb(0.55482458, 0.40350876, 0.04166666), rgb(0, 0, 0)) plot(seq(along = col1), pch = 16, col = col1, cex = 1.5) I'm also using these with transparency (alpha

I want to create a list of functions in a for loop, with the index of the loop appearing explicitly in the function code. After quite a bit of thrashing around I figured out how to do it. Here is a toy example: junk <- vector("list",4) for(i in 1:4) { itmp <- i junk[[i]] <- eval(bquote(function(x){42 + .(itmp)*x})) } So I'm *basically* happy, but there's

> d = data.frame(gender=rep(c('f','m'), 5), pos=rep(c('worker', 'manager', 'speaker', 'sales', 'investor'), 2), lot1=rnorm(10), lot2=rnorm(10)) > d gender pos lot1 lot2 1 f worker 1.1035316 0.8710510 2 m manager -0.4824027 -0.2595865 3 f speaker 0.8933589 -0.5966119 4 m sales

People, I'm researching some Bayesian statistic topics and in the midle of my study i found a very simple problem and i'm trying to find a simple package to solve this type of equations: Lets say that i need to compute beta values for the beta distribution and i now for example: E(teta)=a/(a+b) = 0,5 Var(teta)=ab/((a+b)^2(a+b+1))=0.05 So if i want to solve this to non-linear system to

I thought some of you might be amused by this. In my non-work time, I'm an avid weaver and teacher of weaving. I'm working on a project involving creating many detailed weaving patterns, so I wrote R code to automate it. Details here: http://stringpage.com/blog/?p=822 If the overlap between R users and avid tablet weavers turns out to be >> 1, I'll polish it up and turn it

Hi all, I'm working with a bunch of large graphs, and stumbled across something useful. Probably many of you know this, but I didn't and so others might benefit. Using pch="." speeds up plotting considerably over using symbols. > x <- runif(1000000) > y <- runif(1000000) > system.time(plot(x, y, pch=".")) user system elapsed 1.042 0.030 1.077