Displaying 1 result from an estimated 1 matches for "paydex".
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adex
2009 Nov 18
2
Median on Aggregated data
...nts variable is a frequency.
So, the question is, is there a simple way to do the same thing in R? I
have to run this on a large dataset -- for a small set it is not a
problem.
---------------------- Begin R code ------------------------------------
N <- 1005 * 14;
myNorm <- data.frame(PaydexNormingCategory = numeric(N),
SIC = numeric(N), CatMedian = numeric(N));
k=1;
#j = 7941; ## For testing only
for (j in levels(SIC)){
for (i in levels(PaydexNormingCategory)){
myData <- dfpaydex[(Paydex==i) & (SIC==j),];
myMedian <- with(myData, levels(Paydex)[median(rep(as.numeri...