Displaying 6 results from an estimated 6 matches for "parrappli".
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parrapply
2017 Sep 14
1
Print All Warnings that Occurr in All Parallel Nodes
Dear R Users,
I have developed the following code for importing a series of zipped CSV by parallel computing.
My problems are that:
A) Some ZIP Files (Which contain CSVs inside) are corrupted, and cannot be opened.
B) After executing parRapply I can only see the last.warning variable error, for knowing which CSV have failed in each node, but I cannot see all warnings, only 1 at a time.
So:
*
2020 May 18
1
parRapply and parCapply return a list in corner cases
According to ?parCapply:
parRapply and parCapply always return a vector.
This appears not to be the case in the following minimal reproducible example:
> library(parallel)
> nslaves <- 2
> cl <- makeCluster(nslaves)
> X <- matrix(2,nrow=3,ncol=4)
> X <- rbind(c(1,1,0,1),X)
> tv <- parCapply(cl,X,FUN=function(x){
+
2012 Oct 23
0
Typos/omissions/inconsistencies in man page for clusterApply
Hi,
Here are the issues I found:
Typos
-----
(a) Found: It a parallel version of ?evalq?,
"is" missing.
(b) Found: 'parLapplyLB', 'parSapplyLB' are load-balancing versions,
intended for use when applying ?FUN? to
'parLapplyLB' has no 'FUN' arg (more on this below).
(c) Found: 'clusterApply' calls 'fun' on the first
2016 Apr 10
2
what is the faster way to search for a pattern in a few million entries data frame ?
Hi there,
I have a data frame DF with 40 millions strings and their frequency. I
am searching for strings with a given pattern and I am trying to speed
up this part of my code. I try many options but so far I am not
satisfied. I tried:
- grepl and subset are equivalent in term of processing time
grepl(paste0("^",pattern),df$Strings)
subset(df,
2016 Apr 09
0
fast way to search for a pattern in a few million entries data frame
Hi there,
I have a data frame DF with 40 millions strings and their frequency. I
am searching for strings with a given pattern and I am trying to speed
up this part of my code. I try many options but so far I am not
satisfied. I tried:
- grepl and subset are equivalent in term of processing time
grepl(paste0("^",pattern),df$Strings)
subset(df,
2016 Apr 10
0
what is the faster way to search for a pattern in a few million entries data frame ?
On 10/04/2016 2:03 PM, Fabien Tarrade wrote:
> Hi there,
>
> I have a data frame DF with 40 millions strings and their frequency. I
> am searching for strings with a given pattern and I am trying to speed
> up this part of my code. I try many options but so far I am not
> satisfied. I tried:
> - grepl and subset are equivalent in term of processing time
>