Displaying 1 result from an estimated 1 matches for "papworth".
2004 Nov 23
6
Weibull survival regression
...ut
they always return the same error msgs. I realise that the former 2 are
AFT survival models, but even when I convert the object with pphsm() in
the Design package, I get the same errors.
Please can anyone enlighten me as to what I seem to be doing /
understanding wrongly?
Regards,
Eric Lim
Papworth Hospital
Cambridge, UK
futime status
[1,] 0.40000000 1
[2,] 0.80000000 1
[3,] 7.10000000 1
[4,] 3.00000000 1
[5,] 0.63333333 1
[6,] 9.93333333 1
[7,] 0.50000000 1
[8,] 6.93333333 1
[9,] 23.33333333 1
[10,] 1.73333333...