search for: pancotto

Thanks a lot, so simple so efficient! I will study more the grep command I did not know. Thanks! Francesca Pancotto > Il giorno 19 ott 2017, alle ore 12:12, Enrico Schumann <es at enricoschumann.net> ha scritto: > > df[grep("strat", row.names(df)), ] [[alternative HTML version deleted]]

...o strat:crt.dummy ", "Common to strat, and crt.dummy ", "Common to strat, and gender ", "Common to strat, and age ") ,] -- Sent from my phone. Please excuse my brevity. On October 19, 2017 3:14:53 AM PDT, Francesca PANCOTTO <f.pancotto at unimore.it> wrote: >Thanks a lot, so simple so efficient! > >I will study more the grep command I did not know. > >Thanks! > > >Francesca Pancotto > >> Il giorno 19 ott 2017, alle ore 12:12, Enrico Schumann ><es at enricoschumann.net> h...

...bject like an array of dimension (2,3,12) which contains each matrix @cval produced by ca.jo for the 12 subjects that i tested. Can anyone help me with that? I hope my explanation of the problem is clear. Thanks in advance for any help. -- Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: http://www2.dse.unibo.it/francesca.pancotto/ ---------------------------------- [[alternative HTML version deleted]]

...ese names were simple, but they are not and involve also spaces. I tried with select matches from dplyr but works for column names but I did not find how to use it on row names, which are of course character values. Thanks for any help you can provide. ---------------------------------- Francesca Pancotto, PhD

Quoting Francesca PANCOTTO <f.pancotto at unimore.it>: > Dear R contributors, > > I have a problem in selecting in an efficient way, rows of a data > frame according to a condition, > which is a part of a row name of the table. > > The data frame is made of 64 rows and 2 columns, but the row nam...

Dear Contributors, I have an easy question for you which is puzzling me instead. I am running loops similar to the following: for (i in c(100,1000,10000)){ print((mean(i))) #var<-var(rnorm(i,0,1)) } This is what I obtain: [1] 100 [1] 1000 [1] 10000 In this case I ask the software to print out the result, but I would like to store it in an object. I have tried a second loop, because if I

...zation of the data, as it takes date as the id values. PS: the n1 index names are not ordered in the original database, so I cannot fill in the NA with the names using a recursive formula. Thank you for any help you can provide. Francesca -- Francesca ---------------------------------- Francesca Pancotto, PhD Dipartimento di Economia Università di Bologna Piazza Scaravilli, 2 40126 Bologna Office: +39 051 2098135 Cell: +39 393 6019138 Web: http://www2.dse.unibo.it/francesca.pancotto/ ---------------------------------- [[alternative HTML version deleted]]

...for (i in 1:3){ fa1b[i]<-(100-(100*abs(fa1[i]/sum(fa1[i])-(1/3)))) } fa2b<-c() for (i in 1:3){ fa2b[i]<-(100-(100*abs(fa2[i]/sum(fa2[i])-(1/3)))) } and so on. Is there a more efficient way to do this? Thanks for your time! Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: https://sites.google.com/site/francescapancotto/ ---------------------------------- [[alternative HTML version deleted]]

...row of the same matrix. The resulting matrix should be composed of these distances. I need to repeat this for each of the subsamples. I realize that there arecalculations that are repeated but I did not find a strategy that does not require Francesca ---------------------------------- Francesca Pancotto, PhD Università di Modena e Reggio Emilia Viale A. Allegri, 9 40121 Reggio Emilia Office: +39 0522 523264 Web: https://sites.google.com/site/francescapancotto/ ---------------------------------- [[alternative HTML version deleted]]

Dear Contributors, I am trying to perform a simulation over sample data, but I need to reproduce the same simulation over 4 groups of data. My ability with for loop is null, in particular related to dimensions as I always get, no matter what I try, "number of items to replace is not a multiple of replacement length" This is what I intend to do: replicate this operation for four

Dear Contributors I have a problem with the collection of data from the results of a test. I need to perform a comparative test over groups of data , recall the value of the pvalue and create a table. My problem is in the way to replicate the analysis over and over again over subsets of data according to a condition. I have this database, called y: gg t1 t2 d 40 1 1

Dear Contributors I would like to perform this operation using a loop, instead of repeating the same operation many times. The numbers from 1 to 4 related to different groups that are in the database and for which I have the same data. x<-c(1,3,7) datiP1 <- datiP[datiP$city ==1,x]; datiP2 <- datiP[datiP$city ==2,x]; datiP3 <- datiP[datiP$city ==3,x] datiP4 <-