search for: pages_to_alloc

...quals to 1024 pages) free pages blocks that the system can have */ > 4m_page_blocks = totalram_pages / 1024; > > /* Allocating one page can hold 512 free page blocks, so calculates the number of pages that can hold those 4MB blocks. And this allocation should not exceed 1024 pages */ > pages_to_allocate = min(4m_page_blocks / 512, 1024); > > For a 2TB guests, which has 2^19 page blocks (4MB each), we will allocate 1024 pages as the buffer. > > When the guest has large memory, it should be easier to succeed in allocation of large buffer. If that allocation fails, that implies that...

...quals to 1024 pages) free pages blocks that the system can have */ > 4m_page_blocks = totalram_pages / 1024; > > /* Allocating one page can hold 512 free page blocks, so calculates the number of pages that can hold those 4MB blocks. And this allocation should not exceed 1024 pages */ > pages_to_allocate = min(4m_page_blocks / 512, 1024); > > For a 2TB guests, which has 2^19 page blocks (4MB each), we will allocate 1024 pages as the buffer. > > When the guest has large memory, it should be easier to succeed in allocation of large buffer. If that allocation fails, that implies that...

On Fri, Jun 15, 2018 at 12:43:11PM +0800, Wei Wang wrote: > Negotiation of the VIRTIO_BALLOON_F_FREE_PAGE_HINT feature indicates the > support of reporting hints of guest free pages to host via virtio-balloon. > > Host requests the guest to report free page hints by sending a command > to the guest via setting the VIRTIO_BALLOON_HOST_CMD_FREE_PAGE_HINT bit > of the host_cmd

On Fri, Jun 15, 2018 at 12:43:11PM +0800, Wei Wang wrote: > Negotiation of the VIRTIO_BALLOON_F_FREE_PAGE_HINT feature indicates the > support of reporting hints of guest free pages to host via virtio-balloon. > > Host requests the guest to report free page hints by sending a command > to the guest via setting the VIRTIO_BALLOON_HOST_CMD_FREE_PAGE_HINT bit > of the host_cmd

...mum number of 4MB (equals to 1024 pages) free pages blocks that the system can have */ 4m_page_blocks = totalram_pages / 1024; /* Allocating one page can hold 512 free page blocks, so calculates the number of pages that can hold those 4MB blocks. And this allocation should not exceed 1024 pages */ pages_to_allocate = min(4m_page_blocks / 512, 1024); For a 2TB guests, which has 2^19 page blocks (4MB each), we will allocate 1024 pages as the buffer. When the guest has large memory, it should be easier to succeed in allocation of large buffer. If that allocation fails, that implies that nothing would be got...

...es blocks that the system can have */ 4m_page_blocks = > > totalram_pages / 1024; > > > > /* Allocating one page can hold 512 free page blocks, so calculates > > the number of pages that can hold those 4MB blocks. And this > > allocation should not exceed 1024 pages */ pages_to_allocate = > > min(4m_page_blocks / 512, 1024); > > > > For a 2TB guests, which has 2^19 page blocks (4MB each), we will allocate > 1024 pages as the buffer. > > > > When the guest has large memory, it should be easier to succeed in > allocation of large buffer. If tha...

...can have */ 4m_page_blocks = > > > totalram_pages / 1024; > > > > > > /* Allocating one page can hold 512 free page blocks, so calculates > > > the number of pages that can hold those 4MB blocks. And this > > > allocation should not exceed 1024 pages */ pages_to_allocate = > > > min(4m_page_blocks / 512, 1024); > > > > > > For a 2TB guests, which has 2^19 page blocks (4MB each), we will allocate > > 1024 pages as the buffer. > > > > > > When the guest has large memory, it should be easier to succeed in > >...