search for: packetcount

...r, int myBufferSize) { SpeexDecoder speexDecoder = new SpeexDecoder(); byte[] payload = new byte[FRAME_SIZE*2]; byte[] completebuffer = new byte[4000000]; int mode = 0; int samplerate = 8000; int channels = 1; speexDecoder.init(mode, samplerate, channels, true); for (int packetCount = 0; packetCount < getNbPackets();packetCount++) { System.arraycopy(decbuffer, packetCount*encodedNbBytes(), payload, 0, encodedNbBytes()); try { speexDecoder.processData(payload,0, encodedNbBytes()); byte[] decoded = new byte[FRAME_SIZE*2]; decodedNbBytes = speexDecoder.getP...

...etEncoder().setDtx(dtx); } int pcmPacketSize = 320; speexEncoder.processData(cmbuffer, 0, pcmPacketSize); nbBytes = speexEncoder.getProcessedData(temp, 0); return temp; } public static byte[] decode(byte[] decbuffer) { SpeexDecoder speexDecoder = new SpeexDecoder(); int packetCount = 0; byte[] payload = new byte[65536]; int bodybytes = nbBytes; int decsize = 0; int Totsize = 0; byte[] completebuffer = new byte[4000000]; Totsize = myNum * bodybytes; speexDecoder.init(1, 8000, 1, true); while((packetCount*nbBytes) <= Totsize) { System.arrayco...

...serial number later os = ogg_stream_create(-1); // CAUTION: Just about anything you do wrong pops a bus error. // You need to be fairly aggressive about checking return codes // and initializing properly. int flgBailError = 0; int pageCount = -1; int flgPacketsConsumed = 0; int packetCount = -1; int flgEOSPage = 0; while(!flgBailError) { dprintf("Page: %d\n", pageCount); if (pageCount != -1) { if (pageCount == 0) { // FIXME: Silly pageCount used to indicate serial number change // because ogg_stream_pagein does braindead release on error and // ogg_p...

Hi everyone, I just changed the meaning of the timestamp in the jitter buffer. If you don't know what I'm talking about, then you're not affected. If you do use the jitter buffer, than you will need to change your code accordingly, so instead of bumping the timestamp by 20 (ms) for each frame, you'll have to increase by 160 (samples) for narrowband or 320 for wideband. The new

...= 32768, that happens after 102 puts... I would say that an int is 32 bits :-) Actually, RTP defines the timestamp as a 32-bit value. Now, what happens when it overflows (3 days for narrowband), I don't know what the RFC says about it. > In my current > implementation I do "((long)packetCounter * 20) % 32760", but speex doesn't > like me starting over at zero, and resets the buffer (every 32 seconds)...How > to do it right? Why do you insist on having considering only 16 bits? Jean-Marc

...ld be closer to what RTP does (and not > have fractional value for sample rates like 44.1 kHz). Hi, what happens if this number flows over? It is just a "int", so it might reach its limits at 2^15 = 32768, that happens after 102 puts...In my current implementation I do "((long)packetCounter * 20) % 32760", but speex doesn't like me starting over at zero, and resets the buffer (every 32 seconds)...How to do it right? Peter -- The absent ones are always at fault. -------------- next part -------------- A non-text attachment was scrubbed... Name: not available Type: applic...

...puts... > > I would say that an int is 32 bits :-) Actually, RTP defines the > timestamp as a 32-bit value. Now, what happens when it overflows (3 days > for narrowband), I don't know what the RFC says about it. > > > In my current > > implementation I do "((long)packetCounter * 20) % 32760", but speex > > doesn't like me starting over at zero, and resets the buffer (every 32 > > seconds)...How to do it right? > > Why do you insist on having considering only 16 bits? My C book taught me an int is only guaranteed to be 16bits or bigger, and...