search for: p1s

...nnounce mailing list, but on the other hand, things that promote the use and value of FreeBSD seem like a good thing too. So if this is too commercial for the list you can let me know at brian@mediacity.com. ----------------------------------------------------------------------- Talisman Sequence P1S $299 PCI Video Capture Card based on Phillips 7110/7116/7196 chipset The Sequence P1S is a "matrox meteor"-like video capture card for the PCI BUS. It works well with the meteor driver available under FreeBSD and has been tested with most of the video tools in general use un...

Hello, I am trying to make a data frame from many elements after running a function which creates many elements, some of which may not end up being real elements due to errors or missing data. For example, I have the following three elements p1s, p2s, and p3s. p9s did not generate the same data as there was an error in the function for some reason. I currently have to delete p9s from the data.frame() command to get the data.frame to work.? How can I make a data frame by somehow ignoring elements (e.g., p9s) that do not exist, without havin...

...ot; ) ) ) np <- length( players ) p1 <- factor( c( rep( "jeff", ng ) , rep( levels( players ), np ) ) , levels=players ) p2 <- factor( c( rep( "mike", ng ) , rep( levels( players ), each=np ) ) , levels=players ) p1s <- c( rnorm( n=ng, mean=-0.5, sd=2 ), rep( 1, np^2 ) ) p2s <- c( rnorm( n=ng, mean=0.5, sd=2 ), rep( 0, np^2 ) ) results <- data.frame( winner=factor( levels(players)[ ifelse(p1s<p2s,p2,p1)], levels=players ) , loser=factor( levels(players)[ ifelse(p1s<p2s,p1,p2) ], levels=pl...

...a1 b3 # 8 a2 b3 # 9 a3 b3 # I have a set of equations of the form : # P1 <- af*cata + pf*catb^cf + mf*doga # S1 <- am*cata + pm*catb^cm + mm*doga #Is there any way that I can do something like this and keep track of #what condition is what since I need to be able to sum the P1s and P2, for # for each combination (or a subset of them) ? I suspect it may be a fairly # straight-forward "apply " problem but I am having a real problem with it. # I am only likely to need to report, perhaps. 15 combinations but at the # moment Idon't see any easy way to do them a...