search for: outers

Displaying 20 results from an estimated 2556 matches for "outers".

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2012 Sep 02
2
Impact of cex changing as a function of mfrow
R 2.15.1 OS X (MLion) Colleagues, I am aware that changes in mfrow / mfcol in par() affect cex (from help: In a layout with exactly two rows and columns the base value of ?"cex"? is reduced by a factor of 0.83: if there are three or more of either rows or columns, the reduction factor is 0.66). I generate a multipage PDF in which mfrow varies such that cex is impacted. This affect
2017 Mar 19
2
outer not applying a constant function
Hi, the function outer can not apply a constant function as in the last line of the following example: > xg <- 1:4 > yg <- 1:4 > fxyg <- outer(xg, yg, function(x,y) x*y) > fconstg <- outer(xg, yg, function(x,y) 1.0) Error in outer(xg, yg, function(x, y) 1) : dims [product 16] do not match the length of object [1] Of course there are simpler ways to construct a constant
2003 Jul 11
3
short puzzles
Dear R users, can someone help with these short puzzles? 1) Is there a function like outer() that evaluates a three-argument function on a threedimensional grid - or else how to define such a function, say, outer.3()? E.g., calculate (x/y)^z on (x,y,z) element of {1,2,3}x{3,4}x{4,5} and return the results in a 3-dimensional array. I would naively use outer() on two of the arguments within a
2017 Mar 20
1
outer not applying a constant function
> Or is this a bad idea? I don't like the proposal. I have seen code like the following (in fact, I have written such code, where I had forgotten a function was not vectorized) where the error would have been discovered much later if outer() didn't catch it. > outer(1:3, 11:13, sum) Error in outer(1:3, 11:13, sum) : dims [product 9] do not match the length of object [1]
2008 Jul 18
1
problem with putting text in outer margins (mtext outer=TRUE)
Hi there, I'm trying to get some text in the outer margins of my plots and am having trouble - the margin text is overlapping my plots, even though the outer margin I'm trying to put it in is very big. I've simplified my problem down to this: ------------------------- X11(width=7.5,height=10) par(mfrow=c(6,1),oma=c(20,0,20,0), mar=c(0,3.1,1,2.1)) for (i in 1:6) {
2017 Mar 20
0
outer not applying a constant function
>>>>> Gebhardt, Albrecht <Albrecht.Gebhardt at aau.at> >>>>> on Sun, 19 Mar 2017 09:14:56 +0000 writes: > Hi, > the function outer can not apply a constant function as in the last line of the following example: >> xg <- 1:4 >> yg <- 1:4 >> fxyg <- outer(xg, yg, function(x,y) x*y) >> fconstg
2006 Mar 23
3
outer() function
Greetings R-help community, I am relatively new to R, which may be why I am having trouble understanding this problem. I am trying to use outer() to generate a graphable surface of a function. If there is a better way to do this, I would appreciate the insight. Otherwise, could someone suggest a method to get the outer() function to work here? Below is my simplified R program. Further down
2017 Dec 06
3
[RFC][LV][VPlan] Proposal for Outer Loop Vectorization Implementation Plan
Proposal for Outer Loop Vectorization Implementation Plan ============================================= ===== Goal: ===== Extending Loop Vectorizer (LV) such that it can handle outer loops, via VPlan infrastructure enhancements. Understand the trade-offs in trying to make concurrent progress with moving remaining inner loop vectorization functionality to VPlan infrastructure   ===========
2006 Dec 07
2
groupedData Error Using outer=TRUE
I'm using groupedData from nlme. I set up a groupedData data.frame with outer=~group1. When I try to plot with outer=TRUE, I get "subscript out of bounds." This happens most of the time. When it works, I get spaghetti-type plots for comparing groups. But I don't understand why it doesn't usually work. > longa.mod.1.gd <- groupedData(mod1.logit~time|
2005 Feb 28
2
A problem about outer()
Dear all, I have something about function outer() that I can't understand. Just see the following example. The two NaNs are due to 0/0, but I can't figure out the cause of the last two errors. I wonder if some one can explain this for me. ___________________________________________________________________ > sx=rbinom(10,1,0.5);ot=rbinom(10,1,0.5);ag <- rbinom(10,100,0.3);ho <-
2013 Sep 05
0
[LLVMdev] [ast-dump] Class template partial specializations missing from an implicit class template instantiation?
I was looking at the ClassTemplatePartialSpecializationDecl::getInstantiatedFromMember documentation, in the included example it says: "(..) the instantiation of Outer<float>::Inner<int*> will end up instantiating the partial specialization Outer<float>::Inner<U*> (...)". To understand the concept better, I dumped the AST for the following code:
2017 Dec 14
3
[RFC][LV][VPlan] Proposal for Outer Loop Vectorization Implementation Plan
>Another might be to introduce changes under feature flags to ease the revert/reintroduce/revert cycle. This is essentially the first guard. We plan to have flags/settings to control which types of outer loops are handled. The new code path is initially exclusive to outer loop vectorization. If we disable all types of outer loops (and that's the initial default), LV continues to be good
2011 Mar 28
2
mgcv gam predict problem
Hello I'm using function gam from package mgcv to fit splines. ?When I try to make a prediction slightly beyond the original 'x' range, I get this error: > A = runif(50,1,149) > B = sqrt(A) + rnorm(50) > range(A) [1] 3.289136 145.342961 > > > fit1 = gam(B ~ s(A, bs="ps"), outer.ok=TRUE) > predict(fit1, newdata=data.frame(A=149.9), outer.ok=TRUE) Error
2001 Mar 15
3
outer
Dear r-plus users, i would like to use outer in the following case outer(x,y,FUN="fun") i suppose that my function fun is of the following form: fun<-function(x,y) { if(y>x) return(x+y) if(y<=x) return(0) } My problem is that the command outer(x,y,FUN="fun") return me a null matrix instead of an upper triangular matrix. Is somebody have a solution ? Thanks for your
2012 Dec 30
2
[LLVMdev] alignment issue, getting corrupt double values
I'm having an issue where a certain set of types and insert/extractvalue are producing the incorrect values. It appears as though extractvalue getting my sub-structure is not getting the correct data. I have these types: %outer = type { i32, %inner, i1 } %inner = type { double, i32 } The trouble is that when I have a value of type %outer then proceed to extract the components of the
2018 Jan 15
0
[RFC][LV][VPlan] Proposal for Outer Loop Vectorization Implementation Plan
To revive the discussion around vectorizer testing, here's a quick sample of a few of the issues hit recently in the loop vectorizer.  I want to be careful to say that I am not stating these are the result of any recent work, just that they're issues that have been triaged down to the loop vectorizer doing something incorrect or questionable from a performance perspective.
2013 Apr 23
2
[LLVMdev] 'loop invariant code motion' and 'Reassociate Expression'
Hi, I am investigating a performance degradation between llvm-3.1 and llvm-3.2 (Note: current top-of-tree shows a similar degradation) One issue I see is the following: - 'loop invariant code motion' seems to be depending on the result of the 'reassociate expression' pass: In the samples below I observer the following behavior: Both start with the same expression: %add = add
2008 Jan 04
2
subsetting
I'm using R Version 2.6.1 under Windows XP. > search() [1] ".GlobalEnv" "s" "s" "package:cairoDevice" [5] "package:datasets" "package:foreign" "package:graphics" "package:grDevices" [9] "package:gWidgetsrJava"
2000 Jan 10
1
'at' parameter in mtext(.., adj=0, outer=T) (PR#396)
Depending on the setting of par()$usr, the 'at' setting in mtext(.., adj=0, outer=T) may cause the text to appear in an anomalous position (e. g. in the first instance below, at the left of the plot region rather than at 'at=0' in the figure region), or the text may not appear at all. If one does not set the 'at' parameter the text appears (with 'adj=0') on the
2005 Oct 27
3
outer-question
Dear all, This is a rather lengthy message, but I don't know what I made wrong in my real example since the simple code works. I have two variables a, b and a function f for which I would like to calculate all possible combinations of the values of a and b. If f is multiplication, I would simply do: a <- 1:5 b <- 1:5 outer(a,b) ## A bit more complicated is this: f <-