Displaying 3 results from an estimated 3 matches for "ordidnary".
2010 Jun 26
2
subset arg in subset(). was: converting result of substitute to 'ordidnary' expression
Dear R users,
Please disregard my previous post "converting result of substitute to 'ordidnary' expression". The problem I have has nothing to do with substitute.
Consider:
> dat <- data.frame(x=1:10, y=1:10)
> subsetexp <- expression(5<x)
> ## this does work
> subset(dat, eval(subsetexp))
x y
6 6 6
7 7 7
8 8 8
9 9 9
10 10 10
> ## and so...
2010 Jun 26
3
converting result of substitute to 'ordidnary' expression
Dear R users,
As substitute() help page points out:
Substituting and quoting often causes confusion when the argument
is 'expression(...)'. The result is a call to the 'expression'
constructor function and needs to be evaluated with 'eval' to give
the actual expression object.
And indeed I am confused. Consider:
> dat <- data.frame(x=1:10,
2010 Jun 26
3
converting result of substitute to 'ordidnary' expression
Dear R users,
As substitute() help page points out:
Substituting and quoting often causes confusion when the argument
is 'expression(...)'. The result is a call to the 'expression'
constructor function and needs to be evaluated with 'eval' to give
the actual expression object.
And indeed I am confused. Consider:
> dat <- data.frame(x=1:10,