Displaying 2 results from an estimated 2 matches for "oct1".
Did you mean:
oct
2016 Apr 13
1
[Fwd: Re: Samba_dlz, dhcp y zona inversa no actualiza]
...; ] && echo "Error: principal not set." && exit 8
[ -z "$REALM" ] && echo "Error: realm not set." && exit 9
[ -z "$ZONE" ] && echo "Error: zone not set." && exit 10
# Disassemble IP for reverse lookups
OCT1=$(echo $IP | cut -d . -f 1)
OCT2=$(echo $IP | cut -d . -f 2)
OCT3=$(echo $IP | cut -d . -f 3)
OCT4=$(echo $IP | cut -d . -f 4)
RZONE="$OCT3.$OCT2.$OCT1.in-addr.arpa"
kerberos_creds() {
export KRB5_KTNAME="$KEYTAB"
export KRB5CCNAME="$KRB5CC"
if [ "$KRB5MIT" =...
2011 Feb 11
0
Summarizing a response variable based on an irregular time period
...e period. The
purpose of this is to compare the summarized values (which were sampled
daily) to another variable that was sampled less frequently. Below is a
trivial example where I would like to summarize the response variable dat$x
such that I have average and sum values from Sept25-27 and Sept28-Oct1. Can
anyone suggest an efficient way to deal with dates like this? As an
extremely tedious previous effort, I simply created another grouping
variable but I had to do this manually. For a large dataset this really
isn't a good option.
Thanks in advance!
Sam
library(plyr)
dat <- data.frame...