Displaying 6 results from an estimated 6 matches for "obs3".
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2010 Jan 18
1
problem of data manipulation
...1 11/02/2000
5 n 2 1 15/02/2000
6 n 2 1 23/02/2000
I want to select the observations whose difference of "var4" is less than
7 for the cases with the same values of var1,var2 andvar3.
The obervations have the same var1, var2 and var3 are, part1 (obs2 and
obs3) and part2 (obs4,obs5, and obs6).
For obs2 and obs3, their date difference is less than 7, so we donot need
to delete any of them.
For obs4,obs5, and obs6,we can see that obs6 should be deleted becuase its
date is over 7 dyas longer than obs4.
So the final dataset should obs1,obs2,obs3,obs4,...
2006 Mar 28
0
ansari.test (one tailed)
...t;, "ouest", "ouest", "ouest",
"ouest"))
obs2<-data.frame(quanti,quali)
obs2
xr<-sort(obs2[,1])
ci<-obs2[,2]
cr<-ci[order(obs2[,1])]
n<-length(obs2[,1])
if(n%%2==0) {rAB<-c(1:(n/2),(n/2):1)} else{rAB<-c(1:((n-1)/2), (n+1)/2,
((n-1)/2):1)}
obs3<-data.frame(rAB,xr,cr)
ties<-as.numeric(names(which((table(obs2[,1])>1)==TRUE))) # extrait les xi
r?p?t?s
obs4<-obs3
for(i in
ties){obs4$rAB[(which(obs3$xr==i))]<-mean(obs3$rAB[(which(obs3$xr==i))])}
obs4
classe1<- split(obs2[,1], obs2[,2])$sud
classe2<- split(obs2[,1], obs2[,...
2009 Jun 15
1
expand data
hi, all
I inherited a data set with format like the following:
para.A para.B para.C observation.1 observation.2 observation.3
....
Essentially, the same experiment (with same parameters) are conducted
3 times, with corresponding observations.
What are the efficient ways of re-arranging this data set in a one row
per observation such that:
para.A para.B para.C observation.1
para.A
2010 Apr 08
0
selected observations based several variables
...to conduct the above
manipulation. Keep them.
#And also keep all the other observations whose donot have the same x and y
values.
#So the final result should be
x y date prior var5
1 1.1 2 2008-12-01 A 1
5 1.3 1.8 2007-05-06 C 5
2 1.3 1.8 2007-05-20 N 2
#obs1 and obs3 have same x and y; Their date difference is 5, so we will
select the earlist obs1 But we notice that its prior value is N, while
another is A, so we also need to replace N using A.
#obs2,obs4 and obs5 have same x and y; Obs4 and obs5 has a date difference
4<=8days,
so earlies obs 5 will be selec...
2005 Apr 20
1
negative p-values from fisher's test (PR#7801)
Full_Name: Martha Nason
Version: 2.0.1
OS: Windows XP
Submission from: (NULL) (137.187.154.154)
I am running simulations using fisher's test on 2 x c tables and a very small
p.value from fisher's test (<2.2e-16) is returned as a negative number. Code
follows.
> set.seed(0)
> nreps.outer <-7
> pvalue.fisher <- rep(NA,nreps.outer)
>
> population1 <- c(
2012 Jun 24
0
nouveau _BIOS method
....H.NVGA NVHA A
0570: 4d 44 41 20 44 49 44 36 20 44 49 44 37 20 44 49 MDA DID6 DID7 DI
0580: 44 38 20 45 42 41 53 20 43 50 53 50 20 45 45 43 D8 EBAS CPSP EEC
0590: 50 20 45 56 43 50 20 58 42 41 53 20 4f 42 53 31 P EVCP XBAS OBS1
05a0: 20 4f 42 53 32 20 4f 42 53 33 20 4f 42 53 34 20 OBS2 OBS3 OBS4
05b0: 4f 42 53 35 20 4f 42 53 36 20 4f 42 53 37 20 4f OBS5 OBS6 OBS7 O
05c0: 42 53 38 20 00 48 05 41 54 4d 43 08 50 54 4d 43 BS8 .H.ATMC.PTMC
05d0: 08 41 54 52 41 08 50 54 52 41 08 50 4e 48 4d 20 .ATRA.PTRA.PNHM
05e0: 54 42 41 42 20 54 42 41 48 20 52 54 49 50 08 54 TBAB TBAH RTIP...