search for: objdtass2

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2017 Jun 18
3
R_using non linear regression with constraints
...log1ab <- with( objdta, log( 1000 - a * b ) ) objdta$myfun2 <- with( objdta , myfun2( a = a , log1ab = log1ab , r = 2 , t = t ) ) objdtass2 <- aggregate( ( objdta$myfun2 - objdta$y )^2 , objdta[ , c( "a", "b" ) ] , FUN = function( x ) if ( all( is.na( x ) ) ) NA else sum( x, na.rm=TRUE )...
2017 Jun 18
0
R_using non linear regression with constraints
...* b ) ) > objdta$myfun2 <- with( objdta > , myfun2( a = a > , log1ab = log1ab > , r = 2 > , t = t > ) > ) > objdtass2 <- aggregate( ( objdta$myfun2 - objdta$y )^2 > , objdta[ , c( "a", "b" ) ] > , FUN = function( x ) > if ( all( is.na( x ) ) ) NA > else sum( x, na.rm=TRUE...
2017 Jun 18
0
R_using non linear regression with constraints
I ran the following script. I satisfied the constraint by making a*b a single parameter, which isn't always possible. I also ran nlxb() from nlsr package, and this gives singular values of the Jacobian. In the unconstrained case, the svs are pretty awful, and I wouldn't trust the results as a model, though the minimum is probably OK. The constrained result has a much larger sum of squares.
2017 Jun 18
3
R_using non linear regression with constraints
https://cran.r-project.org/web/views/Optimization.html (Cran's optimization task view -- as always, you should search before posting) In general, nonlinear optimization with nonlinear constraints is hard, and the strategy used here (multiplying by a*b < 1000) may not work -- it introduces a discontinuity into the objective function, so gradient based methods may in particular be