search for: oarray

Hello everybody [R-2.12.1] I am having difficulty dealing with Oarray objects. I have a generic function, call it foo(), and I wish to define a method for Oarray objects. I do not have or want a method for regular arrays [actually, I want to coerce to an Oarray, and give a warning]. But setMethod() does not behave as desired, giving an error message when I try to...

Also https://cran.r-project.org/package=Oarray (which is older and hence possibly more stable) On 2024-04-21 3:55 a.m., Hans W wrote: > As we all know, in R indices for vectors start with 1, i.e, x[0] is not a > correct expression. Some algorithms, e.g. in graph theory or combinatorics, > are much easier to formulate and code if 0 is...

https://cran.r-project.org/package=index0 On Sun, Apr 21, 2024, 3:56 AM Hans W <hwborchers at gmail.com> wrote: > As we all know, in R indices for vectors start with 1, i.e, x[0] is not a > correct expression. Some algorithms, e.g. in graph theory or combinatorics, > are much easier to formulate and code if 0 is an allowed index pointing to > the first element of the vector.

Hello Peter, Unless I too misunderstand your point, negative indices for removal do work with the Oarray package (though -0 doesn't work to remove the 0th element, since -0 == 0 -- perhaps what you meant): > library(Oarray) > v <- Oarray(1:10, offset=0) > v [0,] [1,] [2,] [3,] [4,] [5,] [6,] [7,] [8,] [9,] 1 2 3 4 5 6 7 8 9 10 > dim(v) [1] 10...

Doesn't sound like you got the point. x[-1] normally removes the first element. With 0-based indices, this cannot work. - pd > On 22 Apr 2024, at 17:31 , Ebert,Timothy Aaron <tebert at ufl.edu> wrote: > > You could have negative indices. There are two ways to do this. > 1) provide a large offset. > Offset <- 30 > for (i in -29 to 120) { print(df[i+Offset])} >

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1. I want to extend the 'array' class, and prefer to use S4 in the belief that this is the best structure for new projects (as the documentation says). I actually wish to do something similar to the excellent Oarray by Jonathan Rougier, but as this class is S3, I can't see how to extend it by S4. Am I being dumb here? 2. Seeking then to define a similar class in S4, my principal task is to modify (extend?) a the extractor "[", modifying the range variables i,j,... . I run into problems here, th...

Hello, How would one index vectors and matrices starting from 0 (or some other value other than the default of 1) in R? Thanks, Rashmi [[alternative HTML version deleted]]

I'm very new to R and utterly blown away by not only the language but the unbelievable set of packages and the documentation and the documentation standards and... I was an early APL user and never lost my love for it and in R I find most of the essential things I loved about APL except for one thing. At this early stage of my learning I can't yet determine if there is a way to

...ter Dalgaard <pd.mes at cbs.dk> Cc: R help project <r-help at r-project.org>; Hans W <hwborchers at gmail.com> Subject: Re: [R] x[0]: Can '0' be made an allowed index in R? Hello Peter, Unless I too misunderstand your point, negative indices for removal do work with the Oarray package (though -0 doesn't work to remove the 0th element, since -0 == 0 -- perhaps what you meant): > library(Oarray) > v <- Oarray(1:10, offset=0) > v [0,] [1,] [2,] [3,] [4,] [5,] [6,] [7,] [8,] [9,] 1 2 3 4 5 6 7 8 9 10 > dim(v) [1] 10...

Hello all, When I create a matrix, is there a way to make it start at [0,0], instead of [1,1]? That way, a 2x2 matrix would go from [0,0] to [1,1], instead of [1,1] to [2,2]. Best, Guillaume

Hi everyone, I'm building a matrix in R with a cycle for like this: pp_ris2=matrix(NA,6,6) for(i in 0:6){ for(j in 0:6){ if(i>j){ pp_ris2[i,j]=myfunction} else if(i==j){ print(c(i,j)) pp_ris2[i,j]=myfunction} }} but the result is: [,1] [,2] [,3] [,4] [,5] [,6] [1,] 0.062 NaN NaN NaN NaN NaN [2,] 0.083 0.022 NaN NaN NaN NaN [3,]

I want to make the matrix to be indexed from row (column) 0, not 1 Can I do that? How? Thanks

Hello, Does anyone knows how to deal with zero subscript in R. I have this code: for (i in 1:nitems){ + for (j in 1:ncat-1) { + draw<-matrix(rnorm(nitems*(ncat-1),seed1,seed2),nitems,(ncat-1)) + d<-( sigma_d*draw ) + mu_d + draw<-matrix(rtnorm((nitems*(ncat-1)),mean = seed1, sd = seed2, lower = .1, upper = 1.5),nitems,(ncat-1)) +

Hi, I have got a lot of SPSS data for years 1993-2010. I load all data into lists so I can easily index the values over the years. Unfortunately loaded data occupy quite a lot of memory (10Gb) - so my question is, what's the best approach to work with big data files? Can R get a value from the file data without full loading into memory? How can a slower computer with not enough memory work

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Dear R-helpers, my data.frame is of the form x <- data.frame( f=gl(4,3), X=rep(0:2,4), p=c(.1,.2,.3)) x f X p 1 1 0 0.1 2 1 1 0.2 3 1 2 0.3 4 2 0 0.1 5 2 1 0.2 6 2 2 0.3 7 3 0 0.1 8 3 1 0.2 9 3 2 0.3 10 4 0 0.1 11 4 1 0.2 12 4 2 0.3 which tabulates some values p(X) for several factors f. Now I want to put it in "wide"

As we all know, in R indices for vectors start with 1, i.e, x[0] is not a correct expression. Some algorithms, e.g. in graph theory or combinatorics, are much easier to formulate and code if 0 is an allowed index pointing to the first element of the vector. Some programming languages, for instance Julia (where the index for normal vectors also starts with 1), provide libraries/packages that allow

...;neural","nFDR","NISTnls","nlme","nlmeODE","nlreg","nnet","nor1mix","norm","normalp","NORMT3","nortest","noverlap","npmc","numDeriv","nws","Oarray","odesolve","onion","optmatch","orientlib","ouch","outliers","oz","pamr","pan","panel","papply","partitions","partsm","party","pastecs","pb...

...9) { > z <- myMatrix[i+1,] > ... > } > > But as Josh said, I think this falls into the class of "You are just > asking for trouble, so don't do it." > > Cheers, > Bert But if you still want to after all those warnings, you can ... see the "Oarray" package, where the first letter of the package name is a capital letter "oh" (O), not a zero (0). library("fortunes"); fortune("Yoda") There ought also to be a clever fortune() expressing the sentiment that you may eventually find (weeks, months, or years lat...