Displaying 3 results from an estimated 3 matches for "numna".
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numa
2019 Jan 21
0
orderVector1 (sort.c): Tiny improvement concerning nalast
...RSXP:
! for (i = 0; i < n; i++) isna[i] = (sx[i] == NA_STRING);
! break;
case CPLXSXP:
! for (i = 0; i < n; i++) isna[i] = ISNAN(cx[i].r) || ISNAN(cx[i].i);
! break;
default:
! UNIMPLEMENTED_TYPE("orderVector1", key);
}
! for (i = 0; i < n; i++) numna += isna[i];
if(numna)
switch (TYPEOF(key)) {
--- 1079,1111 ----
switch (TYPEOF(key)) {
case LGLSXP:
case INTSXP:
! for (i = 0; i < n; i++) {
! isna[i] = (ix[i] == NA_INTEGER);
! numna += isna[i];
! }
! break;
case REALSXP:
! for (i = 0; i < n; i++){
!...
2006 Jul 28
1
(no subject)
Dear R-Helpers,
I have a large data matrix (9707 rows, 60 columns), which contains missing
data. The matrix looks something like this:
1) X X X X X X NA X X X X X X X X X
2) NA NA NA NA X NA NA NA X NA NA
3) NA NA X NA NA NA NA NA NA NA
5) NA X NA X X X NA X X X X NA X
..
9708) X NA NA X NA NA X X NA NA X
.and so on. Notice that every row has a varying number of entries, all rows
2015 Jun 19
4
Sobre data.table
Hola, ¿qué tal?
¿Y por qué no, simplemente, sapply(mi.data.table, function(x) sum(is.na(x)))?
Un saludo,
Carlos J. Gil Bellosta
http://www.datanalytics.com
El día 19 de junio de 2015, 14:44, Olivier Nuñez <onunez en unex.es> escribió:
> Si te devuelve 0 para todas las columnas es que no hay NA's.
> Tal vez son caracteres igual a "NA".
> Para asegurarte de ello,