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...- pmiss } } I tried a little bit, but not enough knowledge in C. #include <stdio.h> #include <R.h> #include <Rdefines.h> #include <math.h> SEXP ESscore(SEXP Rgeneset, SEXP Rgenemat, SEXP Rranklist, SEXP sim) { int nc = ncols(Rgenemat); double *geneset = NUMERIC_DATA(Rgeneset); double *genemat = NUMERIC_DATA(Rgenemat); SEXP Rscore; PROTECT(Rscore=NEW_NUMERIC(sim)); double *score = NUMERIC_DATA(Rscore); for(i=1; i<=sim; i++){ if(i>2) {genemat <- genemat[,sample(1:nc)];} for(k=1; k<nc ) } } [[alternative HTML version deleted]]

...assert_equal 3, m1.my_house_population assert_kind_of BigDecimal, m1.bank_balance assert_equal BigDecimal("1586.43"), m1.bank_balance assert_kind_of BigDecimal, m1.big_bank_balance assert_equal BigDecimal("1000234000567.95"), m1.big_bank_balance end The numeric_data table is defined like this CREATE TABLE `numeric_data` ( `id` INTEGER NOT NULL auto_increment PRIMARY KEY, `bank_balance` decimal(10,2), `big_bank_balance` decimal(15,2), `world_population` decimal(10), `my_house_population` decimal(2), `decimal_number_with_default` decimal(3,2) DEFAUL...

While doing some embedded programming and trying to figure out how to generate a hand coded SEXP equivalent of the line "t.test(x,conf.level=(1-p))$conf.int[2]" I had an idea for an addition to the embedded API. There are a number of hidden or static parse functions (R_ParseBuffer, R_Parse1Buffer, etc.) which take an IoBuffer* and returns a parsed tree. If one or more of these