search for: numerate

Hi, Using S=1000 and simdata <- replicate(S, generate(3000)) #If you want both "m1" and "m0" #here the missing values are 0 res1<-sapply(seq_len(ncol(simdata.psm1)),function(i) {x1<-merge(simdata.psm0[,i],simdata.psm1[,i],all=TRUE); x1[is.na(x1)]<-0; x1}) res1[,997:1000] #????? [,1]???????? [,2]???????? [,3]???????? [,4]??????? #x1??? Numeric,3000 Numeric,3000

Hi: I have a small problem that I'm not quite sure how to figure out. I've generated some randomized (permutated) data which consists of nrows=3 by ncols=165 (see below) per element (3 x 165 = 495 sub-elements). [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13] [,14]....... [1,] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 [2,]

Howdy, R Grues I have enjoyed R, but I cannot solve one problem easily. Please help my problem. When I tried the R script, I got the following Error. This error results from input data file exported through a Excel spreadsheet software. Error in step(lm(pop.rate ~ as.numeric(year) + as.factor(policy) + as.numeric(nation.grant) + ?: ??number of rows in use has changed: remove missing values?

I have a matrix named "spec" (see below), it is a 6x3 matrix, and each element of spec is a list. For example, spec[1,"wavenumber"] is a list, and it contains 1876 numeric numbers and NAs. I want to replace the NAs to zero, but don't know how to change it, the difficulty may be all the elements are of the class list, so it is hard to change. Thank you for your help!

Hi, > class(as(1:4, "numeric")) [1] "integer" Surprising but an explanation could be that an integer vector being a particular case of numeric vector, this coercion has nothing to do because 1:4 is already numeric. And indeed: > is.numeric(1:4) [1] TRUE > is.numeric(as(1:4, "numeric")) [1] TRUE However, 'as(1:4,

Hi, You might need to check library(boot).? I have never used that before.? So, I can't comment much.? It is better to post on R-help list.? I had seen your postings on Nabble in the past.? Unfortunately those postings were not accepted in R-help.? You have to directly post at ? r-help at r-project.org after registering at: https://stat.ethz.ch/mailman/listinfo/r-help ?

I am fairly new to R and would like help with the problem below. I am trying to sum and count several rows in the data frame yy below. All works well as in example 1. When I try to add the columns, with an NA in Q21, I get as NA as mySum. I would like NA to be treated as O, or igored. I wrote a function to try to count an NA element as 0, Example 3 function. It works with a few warnings,

Dear R-list I am having troubles understanding how the function is.numeric() works. Any help appreciated. Some commands are given here (the output and my comments are given below) vec <- c(1.4, NA, NA, NA) sapply(vec,FUN=is.numeric) is.numeric(vec[2]) is.na(vec[2]) is.numeric(NA) vec <- c(TRUE, FALSE, NA, NA) sapply(vec,FUN=is.numeric) is.numeric(vec[2]) is.numeric(vec[3])

>>>>> John Chambers <jmc at r-project.org> >>>>> on Fri, 11 Dec 2015 10:11:05 -0800 writes: > Somehow, the most obvious fixes are always back-incompatible these days. > The example intrigued me, so I looked into it a bit (should have been doing something else, but ....) > You're right that this is the proverbial

As I tried to say on Dec. 11, there are two levels of "fix": 1. The fix to the complaint in the OP's subject heading is to conform to the default third argument, strict=TRUE: as(1L, "numeric") == 1.0 This generates some incompatibilities, as for classes that extend "numeric". But still leaves class(1.0) "numeric" and typeof(1.0) "double".

>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>> on Tue, 8 Dec 2015 15:25:21 +0100 writes: >>>>> John Chambers <jmc at r-project.org> >>>>> on Mon, 7 Dec 2015 16:05:59 -0800 writes: >> We do need an explicit method here, I think. >> The issue is that as() uses methods for the generic

We do need an explicit method here, I think. The issue is that as() uses methods for the generic function coerce() but cannot use inheritance in the usual way (if it did, you would be immediately back with no change, since "integer" inherits from "numeric"). Copying in the general method for coercing to "numeric" as an explicit method for "integer" gives

Here's the surprising behavior: x <- 1L xx <- as(x, "numeric") class(xx) ## [1] "integer" It occurs because the call to `as(x, "numeric")` dispatches the coerce S4 method for the signature `c("integer", "numeric")`, whose body is copied in below. function (from, to = "numeric", strict = TRUE) if (strict) {

I am trying to calculate quantiles of a data frame column split up by two factors: # Calculate the quantiles quarts = tapply(gdf$tt, list(gdf$Runway, gdf$OnHour), FUN=quantile, na.rm = TRUE) This does not work: > quarts 04L 04R 15R 22L 22R 27 32 33L 33R 0 NULL Numeric,5 NULL Numeric,5 NULL Numeric,5 NULL Numeric,5 NULL 1 NULL

I am trying to read and write database tables that have a date field in them. I am constructing a data.frame, then using dbWriteTable to create the table and dbReadTable to read it. >datatbl<-data.frame( dates, trialnum, fooddel, ethdel, trialtime, trialtype, deliveries, food, ethanol, fcumrec, dcumrec, rrf, rrd) >ifelse(startdate==filelist,

It surprised me that prod(numeric(0)) is 1. I guess if you say (operation(nothing) == identity element) this makes sense, but ?? Looking in the code, this makes sense: basically (s=1; for i=0 to length(x), multiply s by x[i]) -- which comes out to 1. What *should* prod(numeric(0)) produce? I couldn't find the answer documented anywhere. (And how about sum(numeric(0))==0, which for

hello,everyone. I have one question: example 1 > x=numeric(0) > y=5 > print(x+y) numeric(0) example 2 > x=numeric(1) > y=5 > print(x+y) [1] 5 why the print(x+y) is numeric(0) at the first example, but the result is 0 at the second example? __________________________________________________ 佈伵伝仮伱佲伔佈G佊伿佅佷仯伃佒佇伖侜伒佢佉伝伨侙佄佫伬伂伝侙佊伿伡侢伾仹伻伵伋伂伌侒佊伿佅佷

Full_Name: c fillekes Version: Version 2.2.1 (2005-12-20 r36812) OS: Gentoo Linux kernel 2.6.12 Submission from: (NULL) (129.116.71.233) "Not Available" is of course not a numeric: R > is.numeric (NA) [1] FALSE But for some reason, all arithmetic operations on NA's are in fact numeric, even if it's with other NA's. > is.numeric (NA+NA) [1] TRUE >

Dear R users, I am trying to simulate some multitrait-multimethod models using the packages sem and psych but whatever I do to deal with models which do not converge I always get stuck and get error messages such as these: "Error in summary.sem(M1) : coefficient covariances cannot be computed" "Error in solve.default(res$hessian) : System ist f?r den Rechner singul?r: reziproke

On Dec 19, 2015, at 3:32 AM, Martin Maechler <maechler at stat.math.ethz.ch> wrote: >>>>>> Martin Maechler <maechler at stat.math.ethz.ch> >>>>>> on Sat, 12 Dec 2015 10:32:51 +0100 writes: > >>>>>> John Chambers <jmc at r-project.org> >>>>>> on Fri, 11 Dec 2015 10:11:05 -0800 writes: >