Displaying 8 results from an estimated 8 matches for "num4".
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2006 Feb 09
1
List Conversion
Hello,
I have a list (mode and class are list) in R that is many elements long and of the form:
>length(list)
[1] 5778
>list[1:4]
$ID1
[1] "num1"
$ID2
[1] "num2" "num3"
$ID3
[1] "num4"
$ID4
[1] NA
I'd like to convert the $ID2 value to be in one element rather than in two.?? It shows up as c(\"num2\", \"num3\") if I try to use paste(list[2], collapse=""). I need to do this over the length of the entire list, however list2 <- apply(list,...
2005 Jul 28
1
Unexpected behavior in recode{car}
...avior.
Consider the following example:
## Begin cut-and-paste example
require( car )
set.seed(12345)
nn <- sample( c( 2, 4 ), size=50, replace=TRUE )
rr <- recode( nn, "2='TWO';4='FOUR'" )
table( rr, exclude=NULL )
ss <- recode( nn, "2='Num2';4='Num4'" ) # Doesn't work as expected
table( ss, exclude=NULL )
tt <- recode( nn, "2='TWO'; 4='Num4'" )
table( tt, exclude=NULL )
uu <- recode( nn, "2='Num2'; 4='FOUR'" )
table( uu, exclude=NULL )
## End cut-and-paste example
All but...
2010 Feb 01
1
How to repeat "for" function?
...-0.5,0.2,1,0.2,0.3,-0.5,0.2,1),4,4,byrow=T)
set.seed(428)
X=mvrnorm(n,m2,c4)
X.pca<-princomp(X)
loadings(X.pca)
pc=X.pca$loadings[,1]
## Part B
num1=rep(1:n)
for(i in 1:n)num1[i]=pc[1]%*%X[i,1]
num2=rep(1:n)
for(i in 1:n)num2[i]=pc[2]%*%X[i,2]
num3=rep(1:n)
for(i in 1:n)num3[i]=pc[3]%*%X[i,3]
num4=rep(1:n)
for(i in 1:n)num4[i]=pc[4]%*%X[i,4]
den=rep(1:n)
for(i in 1:n)den[i]=pc%*%X[i,]
r1=num1/den
r2=num2/den
r3=num3/den
r4=num4/den
MLAV=sum(r2>r1 & r2>r3 & r2>r4)
MLAV
Best regards,
ayu
--
View this message in context: http://n4.nabble.com/How-to-repeat-for-function-tp...
2013 Jun 11
1
mapply on multiple data frames
...ple data frames. All data frames have the same structure.
Here is my code so far:
f<-function(x,y) {
test<-t.test(x$col1[x$col3=="num",],v$col2[x$col3=="num",],paired=T,alternative="greater")
out<-test$p.value
return(out)
}
all_nums<-list(num1,num2,num3,num4)
all_dfs<-list(df1,df2,df3,df4)
mapply(f,all_dfs,all_nums)
This tells me that $ operator is invalid for atomic vectors. I have tried shifting to notation using [ ,] to denote columns, but that gives me this error: incorrect number of dimensions.
Thank you in advance,
Elizabeth
2012 Aug 31
2
[LLVMdev] How to write a regression test case?
...dNameAllUsedStructsAndMergeFunctions() was removed.for
this the module data can not be translated correctly.
when i try to rewrite this pass,i found much interfaces of module have
been changed.
i write a test which contian a struct like this
struct student{
long num;
int num2;
int num3;
int num4;
};
after analyze the struct should be modify like this:
struct student{
long num;
int num2;
int num3;
int num4;
char add[4];
};
but now, i do not know which function can do this work in Module in llvm162227.
thanks,
Regards,
changcheng
On Wed, Aug 29, 2012 at 10:29 PM, Triple Yang...
2012 Aug 29
0
[LLVMdev] How to write a regression test case?
aha, that's quite straightforward.
2012/8/29 Changcheng Wang <changcheng at multicorewareinc.com>:
> hi,yang:
> i had delete the temporary files,sorry to trouble you.
> it is so easy: // RUN: rm ....
>
> Regards
> changcheng
>
> On Wed, Aug 29, 2012 at 2:41 PM, Changcheng Wang
> <changcheng at multicorewareinc.com> wrote:
>> hi,yang:
>> how
2012 Aug 29
3
[LLVMdev] How to write a regression test case?
hi,yang:
i had delete the temporary files,sorry to trouble you.
it is so easy: // RUN: rm ....
Regards
changcheng
On Wed, Aug 29, 2012 at 2:41 PM, Changcheng Wang
<changcheng at multicorewareinc.com> wrote:
> hi,yang:
> how can i remove the temporary files?
> if i can remove them,all is ok!
>
> yours:
>
> changcheng
>
> On Wed, Aug 29, 2012 at 2:14 PM, Changcheng
2010 Aug 24
0
mlm for within subject design
...gam.object <- gam(YVAR~1, data=gam.data)
step.object <-step.gam(gam.object, scope=list(
"FAC1"=~1+FAC1,
"FAC2"=~1+FAC2,
"FAC3"=~1+FAC3,
"NUM1"=~1+NUM1+ns(NUM1,df=2),
"NUM2"=~1+NUM2+ns(NUM2,df=2),
"NUM3"=~1+NUM3+ns(NUM3,df=2),
"NUM4"=~1+NUM4+ns(NUM4,df=2),
"NUM5"=~1+NUM5+ns(NUM5,df=2),
"NUM6"=~1+NUM6+ns(NUM6,df=2),
"NUM7"=~1+NUM7+ns(NUM7,df=2),
"NUM8"=~1+NUM8+ns(NUM8,df=2),
"NUM9"=~1+NUM9+ns(NUM9,df=2),
"NUM10"=~1+NUM10+ns(NUM10,df=2),
"NUM11"=~1+NUM11+...