search for: noquotes

It is very wierd... Can some of you confirm the following behavior ? It is a new bug (feature ?) which was not yet in 0.49 ... noquote <- function(obj) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(class(obj),"noquote") obj } "[.noquote" <- function (x, subs) structure(unclass(x)[subs], class =

The source to the noquote() function looks like this: noquote <- function(obj, right = FALSE) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(attr(obj, "class"), if(right) c(right = "noquote") else "noquote") obj } Notice what happens with right =

I haven't been able to get anywhere tracking this down. It seems that c.noquote() does something strange with its third (and subsequent) parameters: R-2.7.0 under NetBSD, R-2.6.0 under Solaris, and R-2.8.0 (unstable) (2008-06-10 r45893) under WinXP, I get: > c(noquote('z'), 'y', 'x', '*') [1] z y x * x * > or: > c(noquote('z'),

G'day all, I am trying to use a string as an argument in a selection but things are not working as I expect, seems the selection is not seeing the expanded string and I do not know how to make it. Perhaps the noquote class value that is returned is the problem. Here is an example. > selection #this is my string [1] "attackprogress$Se=='Toona ciliata [19825: JMM35]'"

I currently have a program that automates 2-way ANOVA on a series of endpoints, but before the ANOVA is carried out I want the code to test the assumptions of normality and equal variance and report along with each anova result in the output file.  How can I do this? I have pasted below the code that I currently use.   library(car) numFiles = x #

Hi, I apologize if the solution is right in front of me, but I can't find anything on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've tried coercing it by 'class(x)<-matrix', but of course that didn't work. I've been using the function 'symnum' which returns an object of class 'noquote'. Here is an

Hi everybody, I would like to count how many times names in list L, nombreL, apear in list C, nombreC. Can I improve the next program? cuenta <- 0 topL <- length(nombreL) topC <- length(nombreC) for (i in 1:topL) { for (j in 1:topC) { k <- grep(noquote(nombreL[i]),nombreC[j])

Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]

Hi R, When I use the below to write the text file try=data.frame(rep("a",5), rep("b",5)) write.table(try,"z:\\try.txt",row.names=F,col.names=F,sep="\t") the output contains two columns with quotes! Is there a way to write without quotes? I tried try[,1]=noquote(try[,1]) try[,2]=noquote(try[,2]) Thank you, Regards, Ravi Shankar

In S, NULL and list() are not the same. In R they are (I think). --------------------------------------------------- At least, is.list(NULL) #-> 'F' in S; 'TRUE' in R Yes: I had an instance where this broke correct S code: match(c("xlab","ylab"), names(list(...))) when '...' is empty, gives an error in R, but gives c(NA,NA) in S.

Full_Name: Franc Brglez Version: R 2.9.1 GUI 1.28 Tiger build 32-bit (5444) OS: MacOSX -- 10.6.2 Submission from: (NULL) (24.148.163.114) I am demonstrating what may be a bug or my lack of experience. Please review as it would help to hear from someone. MANY THANKS -- Franc Brglez The function "binS2binV" returns what I consider a wrong value -- see the terminal output binS2binV =

Hi Duncan and Bert; I do appreciate for your replies. I just figured out that after x1= noquotes(x) commend my 733*22 matrix returns into n*1 vector. Is there way to keep this as matrix with the dimension of 733*22? Regards, Greg On Tue, Sep 19, 2017 at 10:04 AM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > On 19/09/2017 9:47 AM, greg holly wrote: > >> Hi all; &...

Is it possible to use "paste" to write out an expression and evaluate it? Suppose I want to add two vectors X1 and X2, defined as follows: X1 <- 1:6 X2 <- 6:1 If I write the following it looks like what I want but is a character: noquote(paste(paste("X", 1, sep = ""), paste("X", 2, sep = ""), sep = "+")) Is there a way to tell R

Hi Gluster users, We are seeing 'error=No space left on device' issue and hoping someone might could advise? We are using a 12 node glusterfs v10.4 distributed vsftpd backup cluster for years (not new) and recently 2 weeks ago upgraded to v9 > v10.4. I do not know if the upgrade is related to this new issue. We are seeing a new issue 'error=No space left on device' error

Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables

Dear mailing list members, My question is maybe very basic, but I could not find the solution. I would like to do the following things 1) colnames(V1)[2] <- par$V2[1] colnames(V2)[2] <- par$V2[2] colnames(V3)[2] <- par$V2[3] ... colnames(V37)[2] <- par$V2[37] 2) V1 <- V1[,-1] V2 <- V2[,-1] V3 <- V3[,-1] ... V37 <- V37[,-1] 3) ms <- merge(V1,V2) ms <- merge(ms,V3)

Hi,Have you checked inode usage (df -i /lvbackups/brick ) ? Best Regards,Strahil Nikolov On Tuesday, May 2, 2023, 3:05 AM, brandon at thinkhuge.net wrote: Hi Gluster users, We are seeing 'error=No space left on device' issue and hoping someone might could advise? We are using a 12 node glusterfs v10.4 distributed vsftpd backup cluster for years (not new) and recently 2 weeks ago

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Dear XpeRts, I prepared a no qoute Character string by the following command s<-noquote(paste (b1, collapse=",")) where, b1 is the vector of 24 intergers. > dput(b1) c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L, 48L, 58L, 64L, 65L, 68L, 82L, 97L, 98L, 101L, 113L, 115L) > dput(s)

  Dear R-helpers, hello I am seeking your help in somehow getting names of variables without quotes (" "). Let us say, we have a table with 3 variables V1, V2 and V3. After the table is read, I get names of the variables (thro' the following code) as under quotes (like "V1" rather than the original representation V1)