Displaying 20 results from an estimated 108 matches for "noquoted".
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noquote
1997 Aug 20
1
R-alpha: R-0.50-a3(+) Method despatching bug ?
It is very wierd... Can some of you confirm the following behavior ?
It is a new bug (feature ?) which was not yet in 0.49 ...
noquote <- function(obj) {
## constructor for a useful "minor" class
if(!inherits(obj,"noquote")) class(obj) <- c(class(obj),"noquote")
obj
}
"[.noquote" <- function (x, subs) structure(unclass(x)[subs], class =
2020 Nov 05
1
Named class vector
The source to the noquote() function looks like this:
noquote <- function(obj, right = FALSE) {
## constructor for a useful "minor" class
if(!inherits(obj,"noquote"))
class(obj) <- c(attr(obj, "class"),
if(right) c(right = "noquote") else "noquote")
obj
}
Notice what happens with right =
2008 Jun 15
1
c.noquote() weirdness
I haven't been able to get anywhere tracking this down. It seems that c.noquote() does
something strange with its third (and subsequent) parameters:
R-2.7.0 under NetBSD, R-2.6.0 under Solaris, and R-2.8.0 (unstable) (2008-06-10 r45893)
under WinXP, I get:
> c(noquote('z'), 'y', 'x', '*')
[1] z y x * x *
>
or:
> c(noquote('z'),
2002 Jun 02
2
selections using text strings (result of noquote)
G'day all,
I am trying to use a string as an argument in a selection but things are
not working as I expect, seems the selection is not seeing the expanded
string and I do not know how to make it. Perhaps the noquote class value
that is returned is the problem.
Here is an example.
> selection #this is my string
[1] "attackprogress$Se=='Toona ciliata [19825: JMM35]'"
2011 Jan 24
2
normality and equal variance testing
I currently have a program that automates 2-way ANOVA on a series of endpoints,
but before the ANOVA is carried out I want the code to test the assumptions of
normality and equal variance and report along with each anova result in the
output file. How can I do this?
I have pasted below the code that I currently use.
library(car)
numFiles = x #
2011 Mar 30
1
Class noquote to matrix
Hi,
I apologize if the solution is right in front of me, but I can't find anything on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've tried coercing it by 'class(x)<-matrix', but of course that didn't work. I've been using the function 'symnum' which returns an object of class 'noquote'.
Here is an
2010 May 08
3
Count cases in a list
Hi everybody, I would like to count how many times names in list L,
nombreL, apear in list C, nombreC.
Can I improve the next program?
cuenta <- 0
topL <- length(nombreL)
topC <- length(nombreC)
for (i in 1:topL) {
for (j in 1:topC) {
k <-
grep(noquote(nombreL[i]),nombreC[j])
2009 Aug 11
1
Passing a list object to lapply
Hello,
I'm having difficulty passing an object name to a lapply function. Can
somebody tell me the trick to make this work?
#Works
T13702 <- TRACKDATA[["13702.xls"]][["data"]]
min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1],
x[1, 3]))))
16553
#Works
d<-2
assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]
2009 Apr 07
3
write text file as output without quotes
Hi R,
When I use the below to write the text file
try=data.frame(rep("a",5), rep("b",5))
write.table(try,"z:\\try.txt",row.names=F,col.names=F,sep="\t")
the output contains two columns with quotes! Is there a way to write
without quotes?
I tried
try[,1]=noquote(try[,1])
try[,2]=noquote(try[,2])
Thank you,
Regards,
Ravi Shankar
1997 Aug 15
1
R-alpha: (minor?) S-R inconsistency: NULL =~= list() -- useful is.ALL function
In S,
NULL
and
list()
are not the same.
In R they are (I think).
---------------------------------------------------
At least,
is.list(NULL) #-> 'F' in S; 'TRUE' in R
Yes: I had an instance where this broke correct S code:
match(c("xlab","ylab"), names(list(...)))
when '...' is empty,
gives an error in R,
but gives
c(NA,NA)
in S.
2009 Dec 09
4
binary string conversion to a vector (PR#14120)
Full_Name: Franc Brglez
Version: R 2.9.1 GUI 1.28 Tiger build 32-bit (5444)
OS: MacOSX -- 10.6.2
Submission from: (NULL) (24.148.163.114)
I am demonstrating what may be a bug or my lack of experience. Please review as
it would help to hear from someone.
MANY THANKS -- Franc Brglez
The function "binS2binV" returns what I consider a wrong value -- see the
terminal output
binS2binV =
2017 Sep 19
2
remove quotes from matrix
Hi Duncan and Bert;
I do appreciate for your replies. I just figured out that after x1=
noquotes(x) commend my 733*22 matrix returns into n*1 vector. Is there way
to keep this as matrix with the dimension of 733*22?
Regards,
Greg
On Tue, Sep 19, 2017 at 10:04 AM, Duncan Murdoch <murdoch.duncan at gmail.com>
wrote:
> On 19/09/2017 9:47 AM, greg holly wrote:
>
>> Hi all;
2012 Sep 17
4
Using paste to create and evaluate a variable expression
Is it possible to use "paste" to write out an expression and evaluate it?
Suppose I want to add two vectors X1 and X2, defined as follows:
X1 <- 1:6
X2 <- 6:1
If I write the following it looks like what I want but is a character:
noquote(paste(paste("X", 1, sep = ""), paste("X", 2, sep = ""), sep = "+"))
Is there a way to tell R
2023 May 02
1
'error=No space left on device' but, there is plenty of space all nodes
Hi Gluster users,
We are seeing 'error=No space left on device' issue and hoping someone might
could advise?
We are using a 12 node glusterfs v10.4 distributed vsftpd backup cluster for
years (not new) and recently 2 weeks ago upgraded to v9 > v10.4. I do not
know if the upgrade is related to this new issue.
We are seeing a new issue 'error=No space left on device' error
2009 Mar 23
2
Looping of read.table and assignment
Dear all,
I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables
2017 Oct 13
1
Quotation marks hinder for loop
Dear mailing list members,
My question is maybe very basic, but I could not find the solution.
I would like to do the following things
1)
colnames(V1)[2] <- par$V2[1]
colnames(V2)[2] <- par$V2[2]
colnames(V3)[2] <- par$V2[3]
...
colnames(V37)[2] <- par$V2[37]
2)
V1 <- V1[,-1]
V2 <- V2[,-1]
V3 <- V3[,-1]
...
V37 <- V37[,-1]
3)
ms <- merge(V1,V2)
ms <- merge(ms,V3)
2023 May 04
1
'error=No space left on device' but, there is plenty of space all nodes
Hi,Have you checked inode usage (df -i /lvbackups/brick ) ?
Best Regards,Strahil Nikolov
On Tuesday, May 2, 2023, 3:05 AM, brandon at thinkhuge.net wrote:
Hi Gluster users,
We are seeing 'error=No space left on device' issue and hoping someone might
could advise?
We are using a 12 node glusterfs v10.4 distributed vsftpd backup cluster for
years (not new) and recently 2 weeks ago
2013 Jul 02
2
Recoding variables based on reference values in data frame
I'm new to R (previously used SAS primarily) and I have a genetics data
frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3,
...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of
the data is shown below:
SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1
CC GG CT AA ID2 CC GG CC AA ID3 CC GG
nc
AA
2013 Mar 07
1
Error: no 'dimnames' attribute for array
Dear XpeRts,
I prepared a no qoute Character string by the following command
s<-noquote(paste (b1, collapse=","))
where, b1 is the vector of 24 intergers.
> dput(b1)
c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L, 48L, 58L, 64L, 65L, 68L, 82L, 97L, 98L, 101L, 113L, 115L)
> dput(s)
2008 Oct 18
5
Getting names of variables without quotes
Dear R-helpers,
hello
I am seeking your help in somehow getting names of variables without quotes (" ").
Let us say, we have a table with 3 variables V1, V2 and V3. After the table is read, I get names of the variables (thro' the following code) as under quotes (like "V1" rather than the original representation V1)