search for: nonzero

Using functions how would I go about do this question? (I already have a mean defined for a function of x.) Write a function called MyMean2. This function has two arguments, x and nonzero, where nonzero has the default value TRUE. This function should return the (Previous defined mean of x) if nonzero=FALSE (Previous defined mean of x) for all x's>0 if nonzero=TRUE Much appreciated. elliot.welch at virgin.net Sent from my BlackBerry? smartphone

...ix a is a 4x4 covariance matrix with equal variance and zero covariance elements, i.e. [,1] [,2] [,3] [,4] [1,] 4 0 0 0 [2,] 0 4 0 0 [3,] 0 0 4 0 [4,] 0 0 0 4 Now if we let a[1,2]=a[2,1]=3, then the inverse covariance matrix will have nonzero elements on the diagonals as well as for elements [1,2] and [2,1]. If we further let a[3,4]=a[4,3]=0.5 then the indices of the nonzero elements of the covariance matrix also matches those indices of the inverse. The problem is, if any of the nonzero off-diagonal indices match, then th...

...t;, count, "\n") cat("Nulls:\n") zeros Here's some code to recreate a file of the same length with nulls in the same places, and spaces everywhere else: size <- count f2 <- tempfile() con <- file(f2, open="wb") count <- 0 while (count < size) { nonzeros <- min(c(size - count, 1000000, zeros - 1)) if (nonzeros) { writeBin(rep(32L, nonzeros), con, size = 1) count <- count + nonzeros } zeros <- zeros - nonzeros if (length(zeros) && min(zeros) == 1) { writeBin(0L, con, size = 1) count <- count + 1...

Can someone verify for me if the for loop below is really calculating the nonzero min for each row of a matrix? I have a bug somewhere in the is section of code. My first guess is how I am find the the nonzero min of each row of my matrix. The overall idea is to make sure I am investing all of my money, i.e. new.set is a set of indicator variables for each stock for a particular...

Hi folks, I''ve got most everything done for the pure Ruby version of win32-file. The last thing left (since I''ll be moving the IO methods to a different package eventually) is the file security stuff. Here''s what I''ve got so far for the get_permissions method. However, I''m stuck at GetAce(). If someone could help me finish up this method, I

HI, I would like to extract data in a specific way.  For example, the rainfall data 0,0,1.5,0,0, 3,1,2.5,0,0,0,0, 2.3,0,0,0, 2.1,1.4,0,0,0, 3,2,1,0,0,0... data_1: 1.5, 2.3               ( a single nonzero data between zeros data) data_2: 3.1, 2.5, 2.1,1.4   ( two nonzero data between zeros data) data_3: 3,1,2.5, 3,2,1       ( three nonzero data between zeros data) Thank you so much for any help given. Roslina [[alternative HTML version deleted]]

...) > zeros > > Here's some code to recreate a file of the same length with nulls in the > same places, and spaces everywhere else: > > size <- count > f2 <- tempfile() > con <- file(f2, open="wb") > count <- 0 > while (count < size) { > nonzeros <- min(c(size - count, 1000000, zeros - 1)) > if (nonzeros) { > writeBin(rep(32L, nonzeros), con, size = 1) > count <- count + nonzeros > } > zeros <- zeros - nonzeros > if (length(zeros) && min(zeros) == 1) { > writeBin(0L, con, size = 1)...

...This command however causes an additional change that on encountering an error R exits with a 0 error status. Although it's just an example, it's an important one as it's referenced in the 'Details' section of the help file. I think it would be better to encourage exiting with a nonzero error status: options(error = quote({dump.frames(to.file = TRUE); q(status = 1)})) Scott -- Scott Kostyshak Economics PhD Candidate Princeton University

Hello! I have data containing a large number of probabilities (about 60) of nonzero coefficients to predict 10 different independent variables (in 10 different BMA models). i've arranged these probabilities in a matrix like so: (IV1) (IV2) (IV3) ... p(b0) p(b0) p(b0) p(b1) p(b1) p(b1) p(b2) p(b2) p(b2) ... where p(b1) for independent varia...

...#39;s some code to recreate a file of the same length with nulls in > the same places, and spaces everywhere else: > > size <- count > f2 <- tempfile() > con <- file(f2, open="wb") > count <- 0 > while (count < size) { > nonzeros <- min(c(size - count, 1000000, zeros - 1)) > if (nonzeros) { > writeBin(rep(32L, nonzeros), con, size = 1) > count <- count + nonzeros > } > zeros <- zeros - nonzeros > if (length(zeros) && min(zeros) == 1) { >...

hello all, i'm trying to use QPmat, from the popbio package. it appears to be based on solve.QP and is intended for making a population projection matrix. QPmat asks for: nout, A time series of population vectors and C, C constraint matrix, (with two more vectors, b and nonzero). i believe the relevant code from QPmat is: function (nout, C, b, nonzero) { if (!"quadprog" %in% (.packages())) { library(quadprog) } n <- dim(nout) z <- nout[, 2:n[2]] z <- matrix(z, n[1] * (n[2] - 1), 1) M <- c() for (i in 1:(n[2] - 1))...

If this is posted elsewhere I cannot find it. I need to perform multiple integration where some of the variables are in the bounds of the other variables. I was trying to use R2Cuba function but cannot set the upper and lower bounds. My code so far is : int <- function(y){ u2 = y[1] z2 = y[2] u1 =y[3] z1 = y[4] ff <- u1*(z1-u1)*u2*(z2-u2)*exp(-0.027*(12-z2)) return(ff) }

.... 2.990 . [3,] 1.115 0.592 . . 5.349 . [4,] . . . . 2.804 1.836 [5,] . 6.961 1.077 . . . But I would like the new sparse matrix to look like this...where only the nonzero elements are permuted. [1,] 1.656 . 5.003 2.983 . . [2,] . . 2.990 . . . [3,] . 5.349 1.115 0.592 . . [4,] 2.804 . 1.836 . . . [5,] . 1.077 . . ....

...table, the output is not the same as SAS's. I don't know that the result consist with one of SAS's. But it works correctly for 2 x 2 x K table. In addition, the function mantelhaen.test does not contain such as test for general association, test for row means scores differ, and test for nonzero correlation in SAS. Could you tell me "Is it something wrong in the function (mantelhaen.test) for R x C x K (R, C > 2) table"? Therefore, I modify part of the function such that output looks as the same as SASs. mh.test <- function(x) { if (any(apply(x, 3, sum) <...

...</span><span class="cx"> </span><span class="cx"> def on_tree_sel_changed(event) </span><span class="cx"> item = event.get_item() </span><del>- if item.is_ok </del><ins>+ if item.nonzero? </ins><span class="cx"> itemText = @tree.get_item_text(item) </span><span class="cx"> run_demo(itemText) </span><span class="cx"> end </span></span></pre></div> <a id="trun...

This is useful for probing probing for cache files such as: external_command ?ignore_error:(Some true) ~prog "ls .cache/something.*" will return command output (matched files) on its success or empty list whenits exit code is other than 0 (there are no such files). --- mllib/common_utils.ml | 15 ++++++++++----- mllib/common_utils.mli | 2 +- 2 files changed, 11 insertions(+), 6

Hi, Is there a function func(x) where x is an array such that it returns a list of the indices of all non-zero elements of the array? for example: a: 1 0 0 0 0 1 0 1 0 func(a) returns two vectors r and c: r c 1 1 2 3 3 2 daver +-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+-+ |David Richmond It works on a | + Dept. of Sociology complex scientific

...zero. However, say I have a dataset that I know has some underlying "baseline" covariance/correlation (say, a value of 0.3), how can I change or incorporate that into to the code? Basically instead of "let's restrict some of these elements are 0 and others have different nonzero values", I'd like it to be "let's restrict some of these elements are 0.3 and others are different or higher/lower than this 0.3". Does that make any sense? Here is the glasso code if it helps: > library(glasso) > glasso function (s, rho, zero = NULL, thr = 1e-04...

hi ?integer says: Note that on almost all implementations of R the range of representable integers is restricted to about +/-2*10^9: 'double's can hold much larger integers exactly. I am getting very confused as to when to use integers and when not to. In my line I need exact comparisons of large integer-valued arrays, so I often use as.integer(), but the above

Dear all, I have a task to find the first all zero row of a matrix X ( nothing known about X). I need to write a function which returns either the row index of the first all-zero row, or NA if there are no all-zero rows. and I also need to locate all rows which are non-zero (should be a vector of row indexes). Can somebody give me some hints on this? Thanks a lot. Rene. [[alternative HTML