search for: newvector

Is there some (much) more efficient way to do this? VECTOR=c(3,2,4,5,5,3,3,5,1,6,6); NEWVECTOR=VECTOR[1]; for(i in 1:(length(VECTOR)-1)) { if((identical(VECTOR[i], VECTOR[i+1]))==FALSE){ NEWVECTOR=c(NEWVECTOR,VECTOR[i+1])} } > VECTOR [1] 3 2 4 5 5 3 3 5 1 6 6 > NEWVECTOR [1] 3 2 4 5 3 5 1 6 _______________________________ Atte Tenkanen University of Turku, Finland

Dear all, I need to stack the columns of a matrix with a variable number of columns. I am aware of new<-c(a[,1],a[,2]) if I have a matrix 'a' with e.g. two columns. For a simulation study I need to stack the matrix with a variable number of columns. Is there a way to do this? Many thanks in advance Peter

Dear List Apologies for such a simple question: I have a vector of 738 elements, coded with values between 1 and 16 (but not containing 7, 10, 11 or 13) and wish to recode value 14 to 1, 4 to 2, 1 to 3, 2 to 4 and all other values to 5. I've been trying to use the replace function (in base) and %in%, but without success. Many thanks Roy