search for: newvariable

Hello, I would like to select cases using multiple logical operations (e.g. X or Y or Z) without having to repeat the dataframe$variable within the subscript. My working code (with a single logical operator) currently looks like this: dataframe$newvariable[data$oldvariable=="X"]<-"group1" I thought this next line of code might do what I wanted, but it doesn't: dataframe$newvariable[data$oldvariable=="X" | "Y" | "Z"]<-"group1" I'd appreciate any suggestions. I've tried pl...

...ight3)) for (x in 1:length(new.variable)) {f<-((((age1[x]-7)*(weight[x]-mw))+((age2[x]-7)*(weight2[x]-mw))+((age3[x]-7)* (weight3[x]-mw)))/(((age1[x]-7)^2)+((age2[x]-7)^2)+((age3[x]-7)^2))); new.variable[x]<-f} #then bind it into the existing old data frame data.frame2<-cbind(data.frame1,newvariable) rm(dat.frame1) attach(data.frame2) #everything o.k. so far but now the problem part... I basically want to remove all the rows with NA in the new data frame including corresponding rows in the new variable data.frame3<-na.omit(data.frame2) rm(data.frame2) attach(data.frame3) length of new.var...

Hi, I'm training an SVM (C-classification from e1071 library) Some of the variables in my data set are nominal. Is there some easy/automatic way to convert them to numerical representations? Thanks, -N

...rvation| Variable 1 | Variable 1 Flag ----------------|------------------|------------------ 1 | 10000 | NA 2 | NA | A 3 | 631 | NA please note | represents another column. this is for a large data set and I cannot manually go through this: my attempt to this was : l=0 # placeholder m<-c() #newvariable 1 v<-c() #newvariable flag for (z in tablename1$Variable_1) (if (is.numeric(z) ) m[z:l] l=l+1 else v[z:1] l=l+1 Can you please guide me as to how to approach this problem? Any help would be greatly appreciated. Tarun Manchanda [[alternative HTML version deleted]]

Hi, I have a simple question. I have a variable with 3 levels. Variable A A A A A A B B B B B B C C C C C C I need to make a new vector renaming de levels B and C for D. NewVariable A A A A A A D D D D D D D D D D D D I dont find how to make it in manuals or in this list. Can anyone help-me??? Thank you Ronaldo -- Agnes' Law: Almost everything in life is easier to get into than out of. -- | //|\\ [*****************************][*******************] || ( ? ? ) [Rona...

..."Yes", then then the new variable should also be "Yes", however if any one of the three existing variables is a "No", then then new variable should be a "No". I would then use that new variable as an exclusion for data in a new or existing dataset (i.e., if NewVariable = "No" then delete): Take this: Column1, Column2, Column3 Yes, Yes, Yes Yes, No, Yes No, No, No No, Yes, No Yes, Yes, No Generate this: Column1, Column2, Column3, NewVariable1 Yes, Yes, Yes, Yes Yes, No, Yes, No No, No, No, No No, Yes, No, No Yes, Yes, No, No And end up with this: Col...

...ed output files (.Rout.save). However, if I change an R file in the /R/ folder, some calls to the Fortran code (called by ".Fortran()") return different results, although the change of the R file is not related to this, e.g. when I add the commands 'print("abc")' or 'newVariable <- 123' to an R file that even does not call the Fortran code. However, adding empty lines or comments does NOT change the values returned by the Fortran code. Different modifications of the R files lead to different results but the same modification always leads to the same results (hence,...

...nal I am currently able to issue this command: echo | date > date.txt I end up with a file called date.txt with the contents: Mon Aug 29 18:32:45 EDT 2005 I would like to issue a command in my dialplan that puts the date into a new variable something like this: System(echo | date > Set(newVariableName=theDateEchoReturns) So that the newVariableName=Mon Aug 29 18:32:45 EDT 2005 The objective in this case is to format the date according to the Unix Time format listed above. I am certainly open to other options for doing this. The default ${TIMESTAMP} format doesn't work for my ne...

Hi! I'm using a large panel data, and now I have faced some difficulties with my analysis. The predictors are not normally distributed and there are quite many outliers (some of them are influential though). I have tried to change the logarythm, but i'm not sure, how to do that. I want also draw a plot picture in which logarythms of predictors x and y are changed. How could I do that?

...0x000000000044da80 in ast_var_name (var=0x10f1d58a0) at chanvars.c:69 name = 0x10f1d58b0 <Address 0x10f1d58b0 out of bounds> #1 0x000000000049948f in pbx_builtin_setvar_helper (chan=0xf460320, name=0x2aaabf53cbf7 "DIALSTATUS", value=0x417a0690 "BUSY") at pbx.c:5825 newvariable = (struct ast_var_t *) 0x10f1d58a0 headp = (struct varshead *) 0xf460880 nametail = 0x2aaabf53cbf7 "DIALSTATUS" __PRETTY_FUNCTION__ = "pbx_builtin_setvar_helper" #2 0x00002aaabf53938e in dial_exec_full (chan=0xf460320, data=0x417a2e50, peerflags=0x417a0c50, continue_exec=0x0...

...nes in some tables or something. I don?t understand the mechanism behind ?for?, but it does not seem to just substitute in a value like in a SAS macro variable. So what I tried was making one big table (in SAS and replacing duplicated data with missing values?i.e. ?if not first.(variable) then (newvariable)=?.?, etc) so when there was more genotype entries than drug entries, for example, ?NA?s filled the corresponding drug data cells. This results, however, in a lot of ?NA?s being printed in the table sections, since there are many lines of data for the graph data. Ccreating this big table was c...