Displaying 19 results from an estimated 19 matches for "newtimes".
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newtime
2006 Sep 22
4
Creating Movies with R
Dear All,
I'd like to know if it is possible to create animations with R.
To be specific, I attach a code I am using for my research to plot
some analytical results in 3D using the lattice package. It is not
necessary to go through the code.
Simply, it plots some 3D density profiles at two different times
selected by the user.
I wonder if it is possible to use the data generated for different
2006 Oct 03
1
do.call with Vectorial Argument
Dear All,
I am trying to use the do.call command to avoid tedious loops in R
when I need to call repetitively a function.
I am experiencing a problem when the arguments of a function are given
with a vector (I need to express then this way to be able later on to
integrate them numerically with the adapt package).
Consider the small script:
remove(list=ls())
#library(adapt)
# first a list of the
2011 Sep 08
2
help subsetting data based on date AND time
Dear R Community,
I am new to R, and have a question that I suspect may be quite simple but is
proving a formidable roadblock for me. I have a large data set that
includes water-quality measurements collected over many 24-hour periods.
The date and time of sample collection are in a combined Date/Time field in
the format yyyy-mm-dd hh:mm:ss. I need to be able to subset the data for
analysis of
2012 Oct 02
2
Basic question about: <<- and method start with dot.
Dear list,
When I read some source code, I find lot of place used symbol <<- , e.g.
lastTime <<- newTime;
What is the meaning here?
Also, I find some method with the name start with dot, e.g.
.RowStandardizeCentered = function(x) {
div = sqrt( rowSums(x^2) );
div[ div == 0 ] = 1;
return( x/div );
}
What is the special meaning for the method name start with a dot?
Thank you
2004 Mar 08
2
a question on CSV file
I have a csv file,
heartrate excercise medicine Time
12 0 0 4:30 am
23 5 0 5:00 am
34 6 0 5:30 am
56 3 0 6:00 am
24 12
2012 Jul 14
3
Can't understand syntax
OK, I need help!!
I've been searching, but I don't understand the logic of some this
dataframe addressing syntax.
What is this type of code called?
test [["v3"]] [is.na(test[["v2"]])] <-10 #choose column v3 where column v2
is == 4 and replace with 10
and where is it documented?
The code below works for what I want to do (find the non-missing value in a
row),
2003 Oct 16
0
[alert] DST change and date comparisons
Description of Problem
We are rapidly approaching the time of year when some will
transition from standard time (ST) to daylight savings time
(DST) and others will make the opposite transition. These
vernal and autumnal transitions have important implications
for those with Microsoft systems and use utilities that
compare file timestamps on different filesystem types or
with filesystems on other
2016 Jun 28
1
[Bug 1077] New: New traffic reduces conntrack timeout
https://bugzilla.netfilter.org/show_bug.cgi?id=1077
Bug ID: 1077
Summary: New traffic reduces conntrack timeout
Product: netfilter/iptables
Version: unspecified
Hardware: All
OS: All
Status: NEW
Severity: normal
Priority: P5
Component: nf_conntrack
Assignee: netfilter-buglog
2007 Oct 08
2
Applying function to data.frame
Hi,
If I have the following data.frame
>y
time val
1 08:00:05.834 1
2 08:03:13.345 2
3 08:10:12.443 3
>
and the following function which converts the time string to the number
of milliseconds since midnight
> str_to_millis
function( s )
{
a <- as.numeric( unlist( strsplit(s,":",fixed="TRUE") ) )
m <- a[1]*3600000 + a[2]*60000 + a[3]*1000
}
2009 Apr 12
2
Convert string to time
One variable contains values (1.30 - one hour and thirty minutes, 1.2
(which is supposed to be 1.20 - one hour and twenty minutes)). I would
like to convert to a minute variable so 1.2 is converted to 80
minutes. How?
2008 Feb 18
4
Compare mean survival time
Dear List,
Does anybody no how to compare mean survival times for two (more) groups in
R? What test statistics should I use?
Thank you very much!
Joe
[[alternative HTML version deleted]]
2013 Oct 15
2
Data handling
Hello all,
I'm having a problem with data handling. My input data is (dput in the
after the signature):
Date Time Fraction
06/19/13 22:15:39 0.3205
06/19/13 22:15:44 0.3205
06/19/13 22:15:49 0.3205
06/19/13 22:15:54 0.3205
06/19/13 22:15:59 0.3205
06/19/13 22:16:09 0.3205
Date in format month/day/year, Time in HH:MM:SS and fraction represents the
fractions of
2003 Oct 18
0
Added functionality --compare-file and --compare-auto
Recently various needs for multiple version handling were discussed
and I put forward a plan of mine. Subsequently the proposal for a
--compare-file=<FILE> switch had support, so I have implemented
this. I have also implemented an experimental --compare-auto which
decides which file to match against using a rule.
Instructions for patch:
1. Install rsync-2.5.6 source
2. "patch -p1
2012 Nov 28
2
hhmm time format, strptime and %k
Hello,
I am having trouble with the conversion specifications as described in
the strptime help page.
> head(dat)
Date Time Open High Low Close Up Down Volume
1 11/19/2012 935 137.89 138.06 137.82 138.05 3202541 3013215 0
2 11/19/2012 940 138.04 138.40 138.02 138.38 2549660 2107595 4657255
3 11/19/2012 945 138.38 138.40 138.18 138.19 1627379 1856318 3483697
4
2007 Jul 07
0
Error Coefficient matrix not invertible using nlme correlation
Hi,
I am learning R. I am using nlme function to my dataset. I am getting error
"Coefficient matrix not invertible". I don't know how to fix this problem.
> bcows1.nlme<-nlme(Temp~model(newTime, beta, delta, kappa), data=
bcows.group,
+ fixed=beta+delta+kappa~1,
+ random=beta+delta+kappa~1,
+ start=list(fixed=c(coef(bcows.nls)[1],
2011 Jan 26
0
build interval
Hello,
I have some question on chron
I currently doing this
t1 <- chron(,"11:30:00")
t2 <- chron(,"11:45:00")
tt <- seq(t1,t2,by=times("00:00:01"))
tt has 901 values (15 minutes * 60 secs) and then
x1 <- rnorm(1:901)
x2 <- rnorm(1:901)
x3 <- rnorm(1:901)
df <- data.frame(tt, x1, x2, x3)
I would like to write a function such that I can
2010 Mar 19
2
Dataframe calculations
Hi everyone,
My question will probably seem simple to most of you, but I
have spent many hours trying to solve it. I need to perform
a series of sequential calculations on my dataframe that move
across rows and down columns, and then repeat themselves at
each unique 'MM' by 'DD' grouping. Specifically, I want to add
'DEPART' time (24 hr time) to 'TRAVEL'(minutes)
2002 Feb 05
1
Still no luck on command line parse [Bug 417]
As suggested, I checked that I was getting wine of the right vintage,
and as you see below, I indeed seem to have the version designated by
the codeweavers rpm name I downloaded
(codeweavers-wine-20011108-5.i386.rpm):
[cafl@emma cafl]$ which wine
/usr/bin/wine
[cafl@emma cafl]$ /usr/bin/wine --version
Wine release 20011108
Wine exited with a successful status
[cafl@emma
2014 Jan 22
2
[LLVMdev] MergeFunctions: reduce complexity to O(log(N))
On 2014 Jan 22, at 07:35, Stepan Dyatkovskiy <stpworld at narod.ru> wrote:
> Hi Raul and Duncan,
>
> Duncan,
> Thank you for review. I hope to present fixed patch tomorrow.
>
> First, I would like to show few performance results:
>
> command: "time opt -mergefunc <test>"
>
> File: tramp3d-v4.ll, 12963 functions
> Current