Displaying 1 result from an estimated 1 matches for "newthirdcolumn".
2009 Sep 03
1
extract and replace columns of matrices stored in a list
Dear All,
I created a list (of length Z) in the following way:
my.array <- vector("list", Z)
then i assigned a matrix (of T rows by N columns) in each of the elements of
the list my.array in the following way:
my.array[[i]] <- matrix.data ##( matrix.data has dimensions TxN, and i
repeated this command for i from 1 to Z, the matrix.data contains only
numeric data)
and
1. i