Displaying 2 results from an estimated 2 matches for "news1o".
2010 Jul 12
2
a small puzzle?
I know the following may sound too basic but I thought the mailing list is
for the benefit of all levels of people. I ran a simple if statement on two
numeric vectors (news1o and s2o) which are of equal length. I have done an
str on both of them for your kind perusal below. I am trying to compare the
numbers in both and initiate a new vector s as 1 or 0 depending on if the
elements in the arrays are greater or lesser than each other. When I do a
simple s=(news1o>s2o)...
2010 Jul 12
6
in continuation with the earlier R puzzle
...just run a for loop it works. But if I am going to run a for loop
every time for large vectors I might as well use C or any other language.
The reason R is powerful is becasue it can handle large vectors without each
element being manipulated? Please let me know where I am wrong.
for(i in 1:length(news1o)){
+ if(news1o[i]>s2o[i])
+ s[i]<-1
+ else
+ s[i]<--1
+ }
--
'Raghu'
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