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...0 ?***? 0.001 ?**? 0.01 ?*? 0.05 ?.? 0.1 ? ? 1 Residual standard error: 13.21 on 13 degrees of freedom Number of iterations to convergence: 6 Achieved convergence tolerance: 9.123e-06 I know that my parameters are significant but I need to say something about the whole model. Many thanks, Nerak -- View this message in context: http://r.789695.n4.nabble.com/nls-how-do-you-know-if-the-model-is-significant-tp4632401.html Sent from the R help mailing list archive at Nabble.com.

...the objects for year 1981 and so on. Does somebody knows a way to do this? I was thinking about some kind of form of apply, but it?s not that I have created a function that has to be applied on a whole column, calculations are done for the different rows? Many thanks for your help! Kind regards, Nerak -- View this message in context: http://r.789695.n4.nabble.com/different-way-for-a-for-loop-for-several-columns-tp4385705p4385705.html Sent from the R help mailing list archive at Nabble.com.

...s in the gradient (the number of nonlinear parameters), or less than the number of rows (the number of observations), nls stops.") I hope someone can help me with this questions. I would like to know what's happening and not just having to accept the results I get now :). Kind regards, Nerak -- View this message in context: http://r.789695.n4.nabble.com/Non-linear-curve-fitting-nls-starting-point-and-quality-of-fit-tp4632295.html Sent from the R help mailing list archive at Nabble.com.

...in the opposite way. results5$R2[which(results5$Cvalue == "1.8")] # But neither results5$Cvalue[which(results5$R2 == "0.6081547")] # nor results5$Cvalue[which(results5$R2 == "max(results5$R2)")] # works? I hope someone can help me with this problem Kind regards Nerak -- View this message in context: http://r.789695.n4.nabble.com/result-numeric-0-when-using-variable1-which-variable2-max-variable2-tp4302887p4302887.html Sent from the R help mailing list archive at Nabble.com.

...umber? If you want for example to do something with the columns depth_1, depth_1.5, depth_2, depth_2.5, depth_3 ? belonging to a dataframe with also other columns not related with the name depth (Like here, there is also the column time). I?m hoping there is something useful for that. Many thanks, Nerak -- View this message in context: http://r.789695.n4.nabble.com/manipulating-data-of-several-columns-simultaneously-tp4306278p4306278.html Sent from the R help mailing list archive at Nabble.com.

...;) hist(islands, freq=FALSE,col="blue",main="test") mtext("testen") hist(islands, freq=FALSE,col="blue",main="test") mtext("testen") (normally, I specify my breaks, ylab and xlab, xlim and y lim) I hope someone can help me. Many thanks, Nerak -- View this message in context: http://r.789695.n4.nabble.com/size-of-graphs-when-using-multiple-figures-by-row-tp4468610p4468610.html Sent from the R help mailing list archive at Nabble.com.

...==0),1,0))) But I get 3 times the amount of rows than that I want? what I should achieve: test.result<-data.frame(C=c(0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0),B=c(0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0),F=c(0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0)) Has someone a suggestions about what I?m doing wrong? Many thanks, Nerak -- View this message in context: http://r.789695.n4.nabble.com/apply-with-as-function-ifelse-with-2-logical-conditions-tp4403637p4403637.html Sent from the R help mailing list archive at Nabble.com.

...cbind(test.number$numberb) } If someone knows a way to get rid of the loops, let me know! Because I want to make this script as fast as possible for larger datasets. I'm trying to get through the apply family to find solutions but it's a hard issue. Many thanks in advance, Kind regards, Nerak -- View this message in context: http://r.789695.n4.nabble.com/function-similar-to-ddply-calculations-based-on-previous-row-tp4390925p4390925.html Sent from the R help mailing list archive at Nabble.com.

...replacing results6[i] by results6[,c([i])] in the for loop is apparently also no a solution). I?m looking for a manner to repeat a calculation/function on several columns. I kind of need this as well further in my script, not only in this part? I would greatly appreciate any suggestions! Thanks! Nerak -- View this message in context: http://r.789695.n4.nabble.com/Accomplishing-a-loop-on-multiple-columns-tp4284974p4284974.html Sent from the R help mailing list archive at Nabble.com.