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Dear useRs, I am working on a project involving the clustering of a large dataset. I need to extract specific sub-clusters from the parent dendrogram for further analysis. The data is too large for the use of convenient tools such as identify.clust (it selects the specific group of interest on a graph), so alternatively I have saved the plot as a large image file so that it can be printed or

What's the best object browser? Dear all, I have tried all the popular R IDE or editors like Eclipse, Komodo, JGR, Revolution... They all have fancy fucntions like auto completion, syntax highlight.... BUT, I JUST WANT A OBJECT BROWSER! The easiest way to view objects in R console is fix(), but you have no global view of all the objects in the workspace. Revolution has the best object

I like your ls.obj function - how might I turn it into a standard function for me whenever I launch R? -----Original Message----- From: David Hinds [mailto:David_Hinds at perlegen.com] Sent: 17 January 2003 20:58 To: r-help at stat.math.ethz.ch Subject: [R] Re: check variables: a Q from a beginner I played around a bit with the ls.objects() code posted by Petr Pikal yesterday and came up with

This is copy & paste from my session: > xyz<-as.vector(c(ls(),as.matrix(lapply(ls(),class)))) > dim(xyz)<-c(length(xyz)/2,2) > > allobj<-function(){ + xyz<-as.vector(c(ls(),as.matrix(lapply(ls(),class)))); + dim(xyz)<-c(length(xyz)/2,2); + return(xyz) + } > xyz       [,1]              [,2]        [1,] "a"               "character"  [2,]

Dear all, I have been trying the following without avail and would be very grateful for any help. From a dendrogram (recursive list of lists with some structure), I would like to obtain some information of the component lists and of the enclosing list at the same time. In dendrogram-speech I basically would like the label of the leaf and the height of the enclosing branch. A dendrogram example

Hi I'm writing a function that uses four parameters (scalars) and I need to run it in an iterative process (the parameters vary to find the minimum RSS). I don't want to use loops and so tried the do.call function. However it didn't work. My understanding is that the do.call simple runs the function replacing the arguments (scalars by vectors), instead of runing the function for

Hi there, Given 2 lists of integer vectors, i.e.: > lista1 $"1" [1] 1 34 5 $"2" [1] 2 1 $"3" [1] 3 10 15 > lista2 $"1" [1] 1 5 $"2" [1] 2 1 $"3" [1] 3 10 29 I want to obtain the union of both, defined as the union of the vectors, that is lista.union[[1]] <- union(lista1[[1]],lista2[[1]]): > lista.union

Dear all, may be somebody have ideas to my following problem: I have to multiplicate each element of a vector with his position in the sorted vector. This isn't a problem ;-) But now i have a weighting vector with the weight of each observation, and my problem starts. A little example (due to my bad english) maybe helps to understand: x<-c(10,40,50,100) # income vector for instance