search for: names2

Hi all, let say I have following matrix: > Dat <- matrix(1:30, 5, 6); colnames(Dat) <- rep(c("Name1", "Names2"), 3) > Dat Name1 Names2 Name1 Names2 Name1 Names2 [1,] 1 6 11 16 21 26 [2,] 2 7 12 17 22 27 [3,] 3 8 13 18 23 28 [4,] 4 9 14 19 24 29 [5,] 5 10 15 20 25 30 >...

...quot;one","two","three") Now I want to concatenate the items to one string, seperateted by space or something else, >str >"one, two, three" If possible without a loop. My actual goal ist to create string like >str.names >"female = names1, male = names2" and pass it as argument to list(), intending to create a list >names.list<-list( female = names1, male = names2) Thanks a lot, Robin

Hi all, probably really simple to solve, but having no background in programming I haven't been able to figure this out: I have two dataframes like df1 <- data.frame(names1=c('aa','ab', 'ac', 'ad'), var1=c(1,5,7,12)) df2 <- data.frame(names2=c('aa', 'ab', 'ac', 'ad', 'ae'), var2=c(3,6,9,12,15)) Now I want merge var1 to df2 by matching the dataframes by the 'names' columns, i.e. something like df3 <- merge (df2, df1, by.x='names2', by.y='names1', all.x=T) However, the...

...","Curly")) and I simply want to get a single column NamesLong<-data.frame(Names=c("Tom","Dick","Larry","Curly")) > NamesLong Names 1 Tom 2 Dick 3 Larry 4 Curly Stack produces an error NamesLong<-stack(NamesWide$Name1,NamesWide$Names2) Error in if (drop) { : argument is of length zero So does bind_rows > NamesLong<-dplyr::bind_rows(NamesWide$Name1,NamesWide$Name2) Error in `dplyr::bind_rows()`: ! Argument 1 must be a data frame or a named atomic vector. Run `rlang::last_error()` to see where the error occurred. I tried m...

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

...because NamesLong <- data.frame(Names = c(NamesWide$Name1, NamesWide$Name2)) appears to do the job in the simplest possible manner. There are all sorts of alternatives, such as data.frame(Name = as.vector(as.matrix(NamesWide[, 1:2]))) As for stack(), the main problem there was a typo (Names2 for Name2). > stack(NamesWide) values ind 1 Tom Name1 2 Dick Name1 3 Larry Name2 4 Curly Name2 If there were multiple columns, you might do > stack(NamesWide[,c("Name1","Name2")])$values [1] "Tom" "Dick" "Larry" "Curly&qu...

...), border=NA ) I need help with: 1. How can I remove the (y-axis) tick marks on the right side of the plot. 2. While reading in the data, I'm using "row.names=Names". Can I generalize this? What I mean is if for some other data set, the row names column has some other name (say Names2) or may be just blank. Can I still produce a similar graph plotting row labels (in this case they are Row1, Row2, ...) on x-axis. Any help would be appreciated, Thanks, Peng -------------- next part -------------- Names Col1 Col2 Col3 Row1 -20 40 -10 Row2 30 -20 40 Row3 30 10 -20 Row4 20 20 -10

...get a single column > NamesLong<-data.frame(Names=c("Tom","Dick","Larry","Curly")) > > NamesLong > Names > 1 Tom > 2 Dick > 3 Larry > 4 Curly > > > Stack produces an error > NamesLong<-stack(NamesWide$Name1,NamesWide$Names2) > Error in if (drop) { : argument is of length zero > > So does bind_rows > > NamesLong<-dplyr::bind_rows(NamesWide$Name1,NamesWide$Name2) > Error in `dplyr::bind_rows()`: > ! Argument 1 must be a data frame or a named atomic vector. > Run `rlang::last_error()` to see wh...

...a.frame(Names=c("Tom","Dick","Larry","Curly")) >>> NamesLong >> Names >> 1 Tom >> 2 Dick >> 3 Larry >> 4 Curly >> >> >> Stack produces an error >> NamesLong<-stack(NamesWide$Name1,NamesWide$Names2) >> Error in if (drop) { : argument is of length zero >> >> So does bind_rows >>> NamesLong<-dplyr::bind_rows(NamesWide$Name1,NamesWide$Name2) >> Error in `dplyr::bind_rows()`: >> ! Argument 1 must be a data frame or a named atomic vector. >> Run `rla...

...free" > >> > >> > >> > 2. While reading in the data, I'm using "row.names=Names". Can I > >> > generalize > >> > this? What I mean is if for some other data set, the row names column > >> > has some other name (say Names2) or may be just blank. Can I still > >> > produce a > >> > similar graph plotting row labels (in this case they are Row1, Row2, > >> > ...) on > >> > x-axis. > >> > >> row.names can be a column number (1) > >> See ?read.tabl...