search for: nameb

I have a data frame with data similar to this: NameA GrpA NameB GrpB Dist A Alpha B Alpha 0.2 A Alpha C Beta 0.2 A Alpha D Beta 0.4 B Alpha C Beta 0.2 B Alpha D Beta 0.1 C Beta D Beta 0.3 Dist is a distance measure between two entities. The table displays all...

...figured I was screwed and had to add the machine to the domain again. I moved the MACHINE.SID and PAYCHEX.<netbios-nameA>.mac files out of the way (not removed, but, out of the "private" directory). I asked the NT administrator to create a new "workstation" called netbios-nameB. I edited the SMB.CONF file to reflect the change from netbios-nameA to netbios-nameB. I then executed the command (the real PDC name has been changed to protect the innocent): smbpasswd -j PAYCHEX -r PAYXPDCNAME and I received the following error after attempting to add a Solaris 2.7 UNIX syste...

...irst I just want to say thanks for all the help I've had from the list so far..) I now have what I think is a clustering problem. I have lots of objects which I have measured a dissimilarity between. Now, this list only has one entry per pair, so it is not symmetrical. Example input: NameA NameB Dist 189_1C2 189_1C1 0 189_1C3 189_1C1 0.017 189_1C3 189_1C2 0.017 189_1C4 189_1C1 0 189_1C4 189_1C2 0 189_1C4 189_1C3 0.017 189_1C5 189_1C1 0.05 189_1C5 189_1C2 0.05 189_1C5 189_1C3 0.067 189_1C5 189_1C4 0.05 189_1C6 189_1C1 0.05 189_1C6 189_1C2 0.05 189_1C6 189_1C3 0.067 189_1C6 189_1C4 0.05 18...

...her the case of https://bugzilla.mindrot.org/show_bug.cgi?id=1008 As a summary, GSSAPI auth against machine in a DNS load-balanced server farm fails. SSH-1 Kerberos works. DNS load-balanced farm: Individual machines in the farm have separate IP addresses (ipA, ipB), separate hostnames (nameA, nameB, ..) and separate Kerberos identities (host/nameA.domain at REALM) . A common DNS name (clustername) resolves to one or several IPs. Reverse lookup on the IP gives the individual machine name. (seems to be a common & cheap way to spread load). The problem is that GSSAPI insists on doing its...

...e(NULL) = 1197643660 15:47:40 time(NULL) = 1197643660 15:47:40 send(27, "\1\1\0\v\0\0\0\1\1G\0\22attributes-charset\0\niso-8859-1H\0\33attributes-natural-language\0\5en-usE\0\vprinter-uri\0\31ipp:///printers/5000-001BB\0\24requested-attributes\0\fprinter-nameB\0\0\0\fprinter-infoB\0\0\0\20printer-location\3", 196, 0) = 196 15:47:40 getrlimit(RLIMIT_NOFILE, {rlim_cur=10020, rlim_max=10020}) = 0 15:47:40 select(28, [27], NULL, NULL, {1, 0}) = 1 (in [27], left {1, 0}) 15:47:40 recv(27, "HTTP/1.1 100 Continue\r\n\r\n", 2048, 0) = 25 15:47:40 t...

Dear list, I have a list, as follows : a <- 5 names(a) <- "a" b <- 9 names(b) <- "b" c <- 15 names(c) <- "c" x <- list("i" = a, "j" = b, "j" = c) I want to invert the list, like this : $a i 5 $b j k 9 15 I do not find a clean solution. Could anyone give me elegant ideas ? Thanks in advance, Carlos