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Dear All, I need some help arranging data that was imported. The imported data frame looks something like this (the actual file is huge, so this is example data) DF: IDKey X1 Y1 X2 Y2 X3 Y3 X4 Y4 Name1 21 15 25 10 Name2 15 18 35 24 27 45 Name3 17 21 30 22 15 40 32 55 I would like to create a new data frame with the following NewDF: IDKey X Y Name1 21 15 Name1 25 10 Name2 15 18 Name2 35 24 Name2 27 45 Name3 17 21 Name3 30 22 Name3 15 40 Name3 32 55 With the data like this I think I can do the following g...

...s the sample data since you say you have already imported it. > The imported data frame looks something like this (the actual file is > huge, so this is example data) > > DF: > IDKey X1 Y1 X2 Y2 X3 Y3 X4 Y4 > Name1 21 15 25 10 > Name2 15 18 35 24 27 45 > Name3 17 21 30 22 15 40 32 55 That data is missing in X3 etc, but would be NA in an actual data frame, so I don't know if my workaround was the same as your workaround. Dput would have clarified the starting point. > I would like to create a new data frame with the following > > N...

Hi! I suspect there must be an easy way to access components of a data frame by name, i.e. the input should look like "name1 name2 name3 ..." and the output be a data frame of those components with the corresponding names. I ´ve been trying for hours, but only found the long way to do it (which is not feasible, since I have lots of components to select): dframe[names(dframe)=="name1" | dframe=="name2" |...

...;) > V [1] "Fred" "Mary" "SAM" > class(V) [1] "character" I would like to change it to a list: > L=as.list(V) > L [[1]] [1] "Fred" [[2]] [1] "Mary" [[3]] [1] "SAM" but I need to name the components as name1, name2, name3, … so it should look like this: $name1 [1] "Fred" $name2 [1] "Mary" $name3 [1] "SAM" Any help will be much appreciated Joseph [[alternative HTML version deleted]]

...ept they have a max string length of 7. Examples are mcw0045, adl0003, lei0101. Now, what I want to do is Function(M1, M2, M3, datafile) { xnew <- readtable(datafile) name1 <- paste("time",M1",sep"") name2 <- paste(status",M1,sep"") name3 <- paste("x",M1,sep"") fit1 <- survfit(Surv(name1,name2)~name3,data=xnew) . . repeat for M2 and M3 . . par(mfcol=c(1,3)) plot(fit1) plot(fit2) plot(fit3) } When I try to pass name1 into the Surv function it give the following error...

...d -r LINE do NODENAME=` echo $LINE | cut -f 1 -d ','` IP=` echo $LINE | cut -f 2 -d ','` names[index]="$NODENAME" ip[index]="$IP" index=`expr index+1` total=`expr total+1` done <<< $(cat list.txt) simple file: more list.txt name1,ip1 name2,ip2 name3,ip3 output when running: sh -x ./test_bash.sh + index=0 + total=0 + names=() + ip=() ++ cat list.txt + read -r LINE ++ echo name1,ip1 name2,ip2 name3,ip3 ++ cut -f 1 -d , + NODENAME=name1 ++ echo name1,ip1 name2,ip2 name3,ip3 ++ cut -f 2 -d , + IP='ip1 name2' + names[index]=name1 + ip[ind...

...oblem: one of the guests does not start automatically after reboot. [root at farm1 xen]# pwd /etc/xen [root at farm1 xen]# ls -l auto total 0 lrwxrwxrwx 1 root root 8 Dec 11 17:25 name1 -> ../name1 lrwxrwxrwx 1 root root 8 May 5 21:10 name2 -> ../name2 lrwxrwxrwx 1 root root 8 Nov 26 11:43 name3 -> ../name3 lrwxrwxrwx 1 root root 6 Oct 29 2009 name4 -> ../name4 (I retyped the names there.) [root at farm1 xen]# ls -l total 88 drwxr-xr-x 2 root root 4096 Apr 3 15:15 auto -rw------- 1 root root 430 Dec 11 13:14 name1 -rw------- 1 root root 610 May 7 12:07 name2 -rw------- 1 root...

Here is a small reproducible example: data <- structure(list(V1 = structure(1:3, .Label = c("Name1", "Name2", "Name3"), class = "factor"), V2 = structure(c(1L, 3L, 2L), .Label = c("nam1", "name-1", "name_12"), class = "factor"), V3 = structure(1:3, .Label = c("nam2", "nam_34", "name-2"), class = "factor"), V4 = structur...

the content of th character vector (of length 1) is as follows: a <- "something2 ....pat1 name1 pat2 something2....pat1 name2 pat2....pat1 name3 pat2 " I would like to extract the character bewteen pat1 and pat2. That's to say, I would like to get a vecter of c("name1", "name2","name3"). What I did is use strsplit() twise. But I wonder if there any function to this specific task? Thanks.

Hi, I'm an R beginner and I'm struggling with what should be a rudimentary task. My data is along these lines: ID name1 name2 name3 name4 Class 0 1 0 2 Var1 A B C A Var2 B C C A Var3 C A B A etc. I'm using the following: foo <- data.frame(t(read.table("file", header=FALSE))) but of course now it's not using ID, Class, etc. as column names. As you can imagine, I'd like to be able to use, say, foo$Va...

Is this the solution? > d1<- as.data.frame(lapply(data,as.character),stringsAsFactors=FALSE) > str(d1) 'data.frame': 3 obs. of 5 variables: $ V1: chr "Name1" "Name2" "Name3" $ V2: chr "nam1" "name_12" "name-1" $ V3: chr "nam2" "nam_34" "name-2" $ V4: chr "nam3" "nam_56" "" $ V5: chr "" "name_78" "" > melt(d1,id.vars="V1")...

...hat has joined the campus wide W2K3 domain. I am currently in the process of trying to setup the smb.conf file so that users of a W2K3 security group can access a single share on the instrument. If this is pedestrian to ask, please forgive me. W2K3 Security Group = [user.name1, user.name2, user.name3] <smb.conf> # Global parameters [global] workgroup = nsm netbios name = NMR server string = Varian NMR security = DOMAIN browseable = yes client code page = 437 encrypt passwords = Yes password server = nsm-dc10 userna...

Hi all, I'm using R 1.5.1 on Windows 2000. The following snippet of code doesn't seem to do anything - no error is reported, and there is no name change. names(myFrame[,c(1:3)]) <- c("name1", "name2", "name3") This code however works nicely: names(myFrame)[c(1:3)] <- c("name1", "name2", "name3") Can anyone suggest why the first doesn't work? Ought an error be reported? Thanks, Andrew Andrew Robinson Phone: 208-885-7115 Department of Fore...

Hi everyone, I have a question for R code to merge. Say I have two dataframes: File1 is: V1 V2 V3 V4 1 100 101 name1 2 200 201 name2 2 300 301 name3 3 400 401 name4 3 500 501 name5 4 600 601 name6 4 700 701 name7 File2 is: V1 V2 V3 V4 1 50 55 p1 3 402 449 p2 4 550 650 p3 4 651 660 p4 2 150 250 p5 2 250 350 p6 3 450 499 p7 2 100 250...

...file called exp.batch which contains 2 cols The first col contains names of R objects the user would like to use. The second col contains the file names which will be read in using read.table i.e. exp.batch may look like this..... name1 complex/filename/path1.txt name2 complex/filename/path2.txt name3 complex/filename/path3.txt name4 complex/filename/path4.txt I want to have a function which will read in the files and make them into the objects named in the 1st column - automatically (by just providing exp.batch) for(i in 1:nrow(exp.batch)){ tmp<-read.table(as.name(exp.batch[i,2]),...) ##...

...f XYZ. Thus, I am keeping the (input) file names constant but the contents of each of these input files may change from one case to another case.   As an example, my input files are as given below.   input1.csv name1   value1 DEF         10   input2.csv name2   value2   LMN         8   input3.csv name3   value3 PQR       7   ## __________________________________________________________________   ## The Problem   name1 = read.csv('input1.csv')$name1 value1 = read.csv('input1.csv')$value1   name2 = read.csv('input2.csv')$name2 value2 = read.csv('input2.csv')$value2...

Hi, I have a table similar structure below. id name position page 1 name1 1 1 2 name2 2 1 3 name3 3 1 4 name4 1 1 5 name5 1 1 6 name6 1 2 What i want is to select all the items for a given page number grouped by pos and displayed in a view using a loop like: display position number, number of records for how many records have the same po...

...How can you associate names with a list when names have not been assigned? For example if you have a list like this: list2<-list(1,2,3) list2 [[1]] [1] 1 [[2]] [1] 2 [[3]] [1] 3 How do you make it look like this with names? : f1<-1 f2<-2 f3<-3 list1<-list(name1=f1, name2=f2, name3=f3) list1 $name1 [1] 1 $name2 [1] 2 $name3 [1] 3 Thanks for any help. I expect there is a simple answer but I cannot find it ... Regards John ---

Hello, I have two matrices as shown below: Matrix 1 ID AB1 BC1 CD1 ... name1 1,1 2,1 0,2 ... name2 2,0 1,2 1,2 ... name3 0,2 1,1 2,0 ... name4 2,0 0,2 0,2 ... Matrix 2 ID AB2 BC2 CD2 ... name1 1,1 2,1 0,2 ... name2 2,0 1,2 1,2 ... name3 0,2 1,0 2,0...

...OpenFile()) if (!nchar(name2)) tkmessageBox(message="Aucun fichier n'a ?t? s?lectionn?!") else tkmessageBox(message=paste("Vous avez s?lectionn? le fichier ",name2)) assign("fileName2",name2,envir=.GlobalEnv) } openListespeces.f = function(){ name3<-tclvalue(tkgetOpenFile()) if (!nchar(name3)) tkmessageBox(message="Aucun fichier n'a ?t? s?lectionn?!") else tkmessageBox(message=paste("Vous avez s?lectionn? le fichier ",name3)) assign("fileName3",name3,envir=.GlobalEnv) } tt <- tktople...