Displaying 20 results from an estimated 21 matches for "nagelkerkes".
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nagelkerke
2012 Mar 05
1
Nagelkerke R2
Dear R community.
I´m working with a generalized linear model which the response variable is
a categorical one and the predictive variables are weather conditions. I
have 250 different places where I need to fit the model. In some of these
places I have strong correlations between some of the variables so I need
to deal with this problem.
I found a work similar than mine where they use tha
2009 Jul 15
0
Nagelkerkes R2N
I am interested Andrea is whether you ever established why your R2 was 1.
I have had a similar situation previously.
My main issue though, which I'd be v grateful for advice on, is why I am obtaining such negative values -0.3 for Somers Dxy using validate.cph from the Design package given my value of Nagelkerke R2 is not so low 13.2%.
I have this output when fitting 6 variables all with
2011 Apr 12
0
cross-validation complex model AUC Nagelkerke R squared code
Hi there,
I really tried hard to understand and find my own solution, but now I
think I have to ask for your help.
I already developed some script code for my problem but I doubt that it
is correct.
I have the following problem:
Image you develop a logistic regression model with a binary outcome Y
(0/1) with possible preditors (X1,X2,X3......). The development of the
final model would be
2010 Dec 27
0
Nagelkerke R square for Prediction data
Hello
I found some small postings dated to 22 Oct 2008 on the message subject. Recently, I have been working with binary logistic regressions. I didn't use the design package. Yet, I needed the "fit" indices. Therefore, I wrote a small function to output the Nagelkerke's R, and the Cox-&-Snell R from a fitted model. I am no professional programmer by far, yet, I hope, that
2009 May 13
1
Nagelkerkes R2N
Hello All,
as I?m new to R and survival analysis, I?ve got a question about the
Design::validate function:
My Code:
cox <- cph(Surv(t,status) ~ var1 + var2 + var3, data=data, x=TRUE, y=TRUE,
surv=TRUE)
cox.val <- validate(cox, B=10, dxy=TRUE, pr=TRUE);
My output (cox.val):
index.orig training test
Dxy -0.3639222921368090891
2011 Apr 11
1
pseudo-R by hand
hello dear list! since we want to do a model analysis and some people
would like to see pseudo-R^2 values for different types of glm of a
logistic regression, i've decided to write a function that computes
either nagelkerkes normed pseudo-R or cox & snells pseudo-R. however, i
am not clear as in the decisive step, i need to calculate the log of
(maximum likelihood estimates of model divided by mle of null model). i
am well aware of the functions stats::mle and stats::logLik as well as
of Design::lrm. however, I...
2019 Apr 25
0
new CRAN package : modelplotr
Hi there!
We would like to share the news that our package *modelplotr *has recently
been added to CRAN with your audience. Here's a some text for the
introduction:
---------------------
*Title:*
*modelplotr v1.0 now on CRAN: Visualize the Business Value of your
Predictive Models *
*Visual:*
https://modelplot.github.io/img/modelplotr_CRAN-topviz-1.gif
*Intro text:*
Modelplotr - Build
2019 Apr 25
0
new CRAN package : modelplotr
Hi there!
We would like to share the news that our package *modelplotr *has recently
been added to CRAN with your audience. Here's a some text for the
introduction:
---------------------
*Title:*
*modelplotr v1.0 now on CRAN: Visualize the Business Value of your
Predictive Models *
*Visual:*
https://modelplot.github.io/img/modelplotr_CRAN-topviz-1.gif
*Intro text:*
Modelplotr - Build
2010 Jul 08
0
Psudeo R^2 (or other effect size) in spatial gls regressions
Dear all,
I have been using the function gls in the package nlme in R to fit some spatial
regressions (as described in Dormann et al.). However, I have been struggling
trying to find a way to calculate a measure of effect size from these models, so
I wanted to know if any of you had an idea on how to do this.
More precisely, I am producing a multiple model with an exponential correlation
2003 Aug 27
1
how to calculate Rsquare
I think you've badly misinterpreted the purpose
of the R listserv with this request:
https://www.stat.math.ethz.ch/mailman/listinfo/r-help says
"The `main' R mailing list, for announcements about the
development of R and the availability of new code, questions
and answers about problems and solutions using R, enhancements
and patches to the source code and documentation of R,
2005 May 13
1
multinom(): likelihood of model?
Hi all,
I'm working on a multinomial (or "polytomous") logistic regression
using R and have made great progress using multinom() from the nnet
library. My response variable has three categories, and there are two
different possible predictors. I'd like to use the likelihoods of
certain models (ie, saturated, fitteds, and null) to calculate
Nagelkerke R-squared values for
2009 Jul 15
1
negative Somers D from Design package
Dear R help
My problem is very similar to the analysis detailed here.
If we use the mayo dataset provided with the survivalROC package the estimate for Somer's Dxy is very negative -0.56.
The Nagelkerke R2 is positive though 0.32.
I know there is a difference between explained variation and predictive ability but I am surprised there is usch a difference given that even a non predictive model
2002 Aug 04
5
Pseudo R^2 for logit - really naive question
I am using GLM to calculate logit models based on cross-sectional data. I
am now down to the hard work of making the results intelligible to very
average readers. Is there any way to calculate a psuedo analoque to the R^2
in standard linear regression for use as a purely descriptive statistic of
goodness of fit? Most of the readers of my report will be vaguely familiar
and more comfortable with
2007 Feb 14
1
model diagnostics for logistic regression
Greetings,
I am using both the lrm() {Design} and glm( , family=binomial()) to perform a
a logisitic regression in R. Apart from the typical summary() methods, what
other methods of diagnosing logistic regression models does R provide? i.e.
plotting an 'lm' object, etc.
Secondly, is there any facility to calculate the R^{2)_{L} as suggested by
Menard in "Applied Logistic
2008 Apr 24
0
Coefficient of determination in a regression model with AR(1) residuals
Dear R-users,
I used lm() to fit a standard linear regression model to a given data
set, which led to a coefficient of determination (R^2) of about
0.96. After checking the residuals I realized that they follow an
autoregressive process (AR) of order 1 (and therefore contradicting
the i.i.d. assumption of the regression model). I then used gls()
[library nlme] to fit a linear
2011 Jun 22
0
GLS models and variance explained
Dear list,
Inspecting residuals of my linear models, I detected spatial autocorrelation.
In order to take this into account, I decided to use the GLS method
with the correlation = corGaus ( ~ X + Y).
Then, I can sort my GLS models based on their AIC.
But ... how to know the proportion of the variance explained by the
best one (it can be best of the worst models) ?
R-squared value has not the
2012 Oct 21
0
R^2 in Poisson via pr2() function: skeptical about r^2 results
Hello.
I am running 9 poisson regressions with 5 predictors each, using glm with
family=gaussian.
Gaussian distribution fits better than linear regression on fit indices,
and also for theoretical reasons (e.g. the dependent variables are counts,
and the distribution is highly positively skewed).
I want to determine pseudo R^2 now. However, using the pR2() of the pscl
package offers drastically
2012 Nov 08
3
Obtaining R-squared value in Logistic Regression
I do not see an R-squared value after preforming the glm regression.
Is there a separate command for this?
Thanks
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2003 Jul 21
1
how to calculate Rsquare
Hi,
I have something like this:
> x <- 1:10
> y2 <- 30+5*x+rnorm(x,sd=3)
> y <- c(y1,y2)
> x <- c(x,x)
> plot(x,y)
> x <- 1:10
> y1 <- 1+5*x+rnorm(x,sd=2)
> y2 <- 30+5*x+rnorm(x,sd=5)
> y <- c(y1,y2)
> x <- c(x,x)
> f <- factor(rep(c("a","b"),c(10,10)))
> m <- lm(y~x+f)
> anova(m)
Analysis of Variance
2005 Mar 29
2
R-squared in Logistic Regression
Dear all,
How do I make R show the R-squared (deviance explained by the model) in
a logistic regression?
Below is how I write my syntax. Basically I want to investigate
density-dependence in parasitism of larvae. Note that in the end I
perform a F-test because the dispersion factor (residual deviance /
residual df) is significantly higher than 1. But how do I make R show
the