Displaying 7 results from an estimated 7 matches for "n_vehicl".
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n_vehicles
2017 Nov 09
4
weighted average grouped by variables
...ructure(c(1L, 2L, 3L, 4L, 1L, 2L, 3L), .Label = c("car", "light_duty", "heavy_duty", "motorcycle"), class = "factor"),
avg_speed = c(41.1029082774049, 40.3333333333333, 40.3157894736842, 36.0869565217391, 33.4065155807365, 37.6222222222222, 35.5),
n_vehicles = c(447L, 24L, 19L, 23L, 706L, 45L, 26L)),
.Names = c("date_time", "direction", "type", "speed", "n_vehicles"),
row.names = c(NA, -7L),
class = "data.frame")
mydf
and I need to get to this final result
mydf_final<-structure(l...
2017 Nov 09
1
weighted average grouped by variables
Hello,
Using base R only, the following seems to do what you want.
with(mydf, ave(speed, date_time, type, FUN = weighted.mean, w = n_vehicles))
Hope this helps,
Rui Barradas
Em 09-11-2017 13:16, Massimo Bressan escreveu:
> Hello
>
> an update about my question: I worked out the following solution (with the package "dplyr")
>
> library(dplyr)
>
> mydf%>%
> mutate(speed_vehicles=n_vehicles*mydf$sp...
2017 Nov 09
0
weighted average grouped by variables
Hello
an update about my question: I worked out the following solution (with the package "dplyr")
library(dplyr)
mydf%>%
mutate(speed_vehicles=n_vehicles*mydf$speed) %>%
group_by(date_time,type) %>%
summarise(
sum_n_times_speed=sum(speed_vehicles),
n_vehicles=sum(n_vehicles),
vel=sum(speed_vehicles)/sum(n_vehicles)
)
In fact I was hoping to manage everything in a "one-go": i.e. without the need to create the "intermed...
2017 Nov 09
2
weighted average grouped by variables
Hi
Thanks for working example.
you could use split/ lapply approach, however it is probably not much better than dplyr method.
sapply(split(mydf, mydf$type), function(speed, n_vehicles) sum(mydf$speed*mydf$n_vehicles)/sum(mydf$n_vehicles))
gives you averages
aggregate(mydf$n_vehicles, list(mydf$type), sum)$x
gives you sums
Cheers
Petr
> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Massimo
> Bressan
> Sent: Thursd...
2017 Nov 11
0
weighted average grouped by variables
> On 9 Nov 2017, at 14:58, PIKAL Petr <petr.pikal at precheza.cz> wrote:
>
> Hi
>
> Thanks for working example.
>
> you could use split/ lapply approach, however it is probably not much better than dplyr method.
>
> sapply(split(mydf, mydf$type), function(speed, n_vehicles) sum(mydf$speed*mydf$n_vehicles)/sum(mydf$n_vehicles))
> gives you averages
>
The result of this calculation is:
car light_duty heavy_duty motorcycle
36.54109 36.54109 36.54109 36.54109
But this doesn't give the same result as the dplyr method which is:
d...
2017 Nov 09
1
weighted average grouped by variables
Dear Massimo,
It seems straightforward to use weighted.mean() in a dplyr context
library(dplyr)
mydf %>%
group_by(date_time, type) %>%
summarise(vel = weighted.mean(speed, n_vehicles))
Best regards,
ir. Thierry Onkelinx
Statisticus / Statistician
Vlaamse Overheid / Government of Flanders
INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND
FOREST
Team Biometrie & Kwaliteitszorg / Team Biometrics & Quality Assurance
thierry.onkelinx at inbo.b...
2017 Nov 09
0
weighted average grouped by variables
...ject.org>
Inviato: Gioved?, 9 novembre 2017 15:17:31
Oggetto: Re: [R] weighted average grouped by variables
Dear Massimo,
It seems straightforward to use weighted.mean() in a dplyr context
library(dplyr)
mydf %>%
group_by(date_time, type) %>%
summarise(vel = weighted.mean(speed, n_vehicles))
Best regards,
ir. Thierry Onkelinx
Statisticus / Statistician
Vlaamse Overheid / Government of Flanders
INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND FOREST
Team Biometrie & Kwaliteitszorg / Team Biometrics & Quality Assurance
thierry.onkelinx at...