Displaying 4 results from an estimated 4 matches for "myvar1".
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myvar
2006 May 21
2
nls & fitting
...4.4272 130.390552
6 1264.9111 36.727069
7 1788.8544 52.848587
8 2449.4897 25.128742
9 3464.1016 7.531766
10 4472.1360 8.827367
11 6123.7244 6.600603
12 8660.2540 4.083339
I would like to fit N as a function of x according to a function
depending on 9 parameters (A1,A2,A3,mu1,mu2,mu3,myvar1,myvar2,myvar3),
namely
N ~
(log(10)*A1/sqrt(2*pi)/log(myvar1)*exp(-((log(x/mu1))^2)/2/log(myvar1)/log(myvar1))
+log(10)*A2/sqrt(2*pi)/log(myvar2)*exp(-((log(x/mu2))^2)/2/log(myvar2)/log(myvar2))
+log(10)*A3/sqrt(2*pi)/log(myvar3)*exp(-((log(x/mu3))^2)/2/log(myvar3)/log(myvar3)))
(i.e. N is to be...
2004 Nov 04
3
calling a var by name in another var
Hello list,
I'd like to use a variable (or a column of a data frame) by using its name as a
string. E.g.:
Data2003 <- c(150,200,120)
Data2004 <- c(145,211,110)
myvar1 <- "Data2003"
myvar2 <- "Data2004"
# now I'd like do do this
total <- Data2003 + Data2004
# in any way like
# total <- ???(myvar1, myvar2)
# or
# total <- ???(myvar1) + ???(myvar2)
# or something like that
Is there a possibility to do this in R - can't...
2012 Jul 26
4
names function not working at the 2nd place in a program
Hello,
I am using names function to name an array.
It works first time when I use *as.numeric(names(myVar1)*
However, at a place later, when I tried to use a very similar line of code
*as.numeric(names(myVar2)*, it always returned 'numeric(0)' (or if I only
type 'names(myVar2), it gave me NULL'.
Both myVar1 and myVar2 are type of integer. The only difference that I can
tell is where th...
2011 Jun 13
2
use variable value to create new variable name
Hi,
Is it possible (and how) to use a variable value to create a name of a new R
variable? I want to do something like this:
for (i in 1:3) {
newvarialbe_#i# = somedata
}
where #i# is a value stored by i. In the first loop, there will be
newvariable_1, in second newvariable_2 and so on.
Thanks in advance,
Maciek
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