search for: myprobit

I can get this summary of a model that I am running: summary(myprobit) Call: glm(formula = Response_Slot ~ trial_no, family = binomial(link = "probit"), data = neg_data, na.action = na.pass) Deviance Residuals: Min 1Q Median 3Q Max -0.9528 -0.8934 -0.8418 1.4420 1.6026 Coefficients: Estimate Std. Error...

Hi Saurav! On Sun, Jul 12, 2009 at 6:06 PM, Pathak, Saurav<s.pathak08 at imperial.ac.uk> wrote: > I am new to R, I have to do a 2 step Heckman model, my selection equation is > below which I was successful in running but I am unable to proceed further, > > > > I have so far used the following command > > glm(formula = s ~ age + gender + gemedu + gemhinc + es_gdppc +

..."phi" "capphi" [71] "invmil_4" "subobaby" "fearf_m" "disc_m" "dis_fear" [76] "fearf_r" "fearf_rm" "dis_ff_r" "s" > library("sampleSelection") > myProbit<- glm(s ~ age + gender + gemedu + gemhinc + es_gdppc + + imf_pop + estbbo_m, family = binomial(link = "probit")) > summary(myProbit) Call: glm(formula = s ~ age + gender + gemedu + gemhinc + es_gdppc + imf_pop + estbbo_m, family = binomial(link = "probit")) Devia...

...irst is almost about data manipulation. Consider the following snippet ################################################## mydata <- read.csv(url("http://www.ats.ucla.edu/stat/r/dae/binary.csv")) names(mydata) <- c("outcome","x1","x2","x3") myprobit <- glm(mydata$outcome~mydata$x1+mydata$x2+as.factor(mydata$x3), family=binomial(link="probit")) print(summary(myprobit)) #Now assume I can make a regression only on x1 myprobit2 <- glm(mydata$outcome~mydata$x1, family=binomial(link="probit")) print(summary(myprobit2...

...deal is financed by stock only, y=1 if the deal is financed by a mix of cash and stock and y=2 if it is by cash only. My independent variables are CollateralB, Cashavailable and Leverage. This is the code I wrote: > library(ordinal) > datareg<-read.xls("C:/regression.xls") > myprobit<-clm2(Newpercentagecash ~ CollateralB + CashavailableB + LEVERAGEB, data = datareg, link = "probit") Error in clm2(Newpercentagecash ~ CollateralB + CashavailableB + LEVERAGEB, : response needs to be a factor I do not understand this error message. My "y" only equals 0, 1...

...countries) value, essentially therefore I wish to check for 65*9 values of "yearctry" with each "yearctry" having 2000 observations roughly. Hence I use the glm/probit to look into the selection bias where all my dependant variable "s" are either 0 or 1. The formula *myProbit<- glm(s ~ age + gender + gemedu + gemhinc + es_gdppc + imf_pop + estbbo_m, family = binomial(link = "probit"), data = adpopdata)* is the Heckman selection equation based on all observations without taking into account the fact that each "yearctry" is unique, I want the selec...

Hi I am working on a panel data, my data are clustered/grouped by the variable "yearctry", I am running the regression below, but I cant make the regression recognise "yearctry" as the panel variable in the regression myProbit<- glm(s ~ age + gender + gemedu + gemhinc + es_gdppc + imf_pop + estbbo_m, family = binomial(link = "probit"), data = adpopdata) Can anyone help me do this please??? Thanks Saurav -- Dr.Saurav Pathak PhD, Univ.of.Florida Mechanical Engineering Doctoral Student Innovation and En...

...land south korea 13 14 15 16 17 20 22 23 24 I know that I could put the option factor() in the Probit model but in my output then '13' instead of 'Japan' appears, which is not so nice, i.e. > myprobit<- glm(v220bin ~ v214 + v216 + factor(v2), family=binomial(link="probit"), data=wvs1981, na.action=na.pass) Thanks a lot for your help. Best regards, Tobias -- Schon geh?rt? GMX hat einen genialen Phishing-Filter in die