search for: myindexes

I would like to take the values of observations and map them to a new index. I am not sure how to accomplish this. The result would look like so: x[1,2,3,4,5,6,7,8,9,10] becomes y[2,4,6,8,10,12,14,16,18,20] The "newindex" would not necessarily be this sequence, but a sequence I have stored in a vector, so it could be all kinds of values. here is what happens: > x <- rnorm(10)

Hello! # I have a data frame: mydf<-data.frame(c1=rep(NA,5),c2=rep(NA,5),c3=rep(NA,5)) # I have an index whose length is always the same as nrow(mydf): myindex<-c(1,2,3,2,1) # I need c1 to have 1s in rows 1 and 5 (based on the information in myindex) # I need c2 to have 1s in rows 2 and 4 (also based on myindex) # I need c3 to have 1 in row 3 # In other words, I am trying to achieve this

Hello, after splitting a data-frame I want to access the results. Maybe the problem is, that the factor/index is a string... ...or do I miss knowing details of the index-uasge? Please look and help: ======================================= > weblog <- read_weblog("web.log") > > > str(weblog) 'data.frame': 2247 obs. of 18 variables: $ host : Factor w/ 77

Dear All, I am using Silhouette to estimate the number of clusters in a microarray dataset. Initially, I used the iris data to test my piece of code as follows: library(cluster) data(iris) mydata<-iris[,1:4] maxk<-15 # at most 15 clusters myindex<-rep(0,maxk) # hold the si values for each k clusters mdist<-1-cor(t(mydata)) #dissimlarity

Hi, I am searching for the equivalent of the function Index from SAS. In SAS: index("abcd", "bcd") will return 2 because bcd is located in the 2nd cell of the abcd string. The equivalent in R should do this: > myIndex <- foo("abcd", "bcd") #return 2. What is the function that I am looking for? I want to use the return value in substr, like I do

Dear R users, I'm starting to use 'apply' functions rather than for loops in R, and sometimes the output is a bit different than what I want. In this case, the command was tapply(myvector,myindex,cumsum) And the output was something like this: $`SNRL1 Core 120` [1] 2.8546 4.0778 5.2983 6.3863 7.5141 8.5498 9.5839 10.6933 $`SNRL1 Core 230` [1] 7.6810 8.7648 9.8382

I have a simple question, but I couldn't find the answer in R manuals. Assume I have a list: > foo <- list() > foo[[1]] <- c(1, 2, 3) > foo[[2]] <- c(11,22,33) > foo[[3]] <- c(111,222,333) > foo [[1]] [1] 1 2 3 [[2]] [1] 11 22 33 [[3]] [1] 111 222 333 How to use list index to get a vector of, say, the first elements of list elements? That is, how to get a vector

Is there a fast way to determine how many documents a term occurs in, besides iterating through every document with TermDocEnum? -- Best regards, Stian Gryt?yr

I am trying to return an index for a data set by searching using filenames. The name may be ANG_AUT.N.0734C70411A-1_1sA_0734C70411A.fasta, but i'd just like to search it using the term "0734C70411" as the file may be 0734C70411A or 0734C70411C or 0734C70411D Any way to do this other than doing something like this. where 0734C70411A is part of matrix list[,8]

The following script creates a search index and then searches it. I get no results? Where am I going wrong? Thanks. -----------BEGIN SCRIPT---------------- require ''rubygems'' require ''ferret'' include Ferret path = ''/tmp/myindex'' field_infos = Ferret::Index::FieldInfos.new() field_infos.add_field(:name, :store => :yes, :index => :yes)

Hi List, I''ve took some time and made some tests on the performance of java-lucene, hyperestraier and ferret as Dave encourages the community of ferret to do so. Quite intersting numbers. Ferret indeed deserves to be called a high-performance port!! It''s MyFirstBenchmark ( http://ferret.davebalmain.com/trac/wiki/MyFirstBenchmark ) so please don''t be too cruel on

Hello Spse I have a matrix, say 1 2 3 4 5 6 7 8 9 and I would like to expand it by repeating rows within the matrix, to get, if the repeating factor is 2, say: 123 123 456 456 789 789 (or columnwise as well) . There must be a smart way of doing that? Many thanks Juhana Vartiainen juhana.vartiainen at labour.fi -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

list(...), I am working with environmental time series (eg rainfall, stream flow) that have attached quality codes for each data point. The quality codes have just a few factor levels, like "good", "suspect", "poor", "imputed". I use the quality codes in plots and summaries. They are carried through when a time series is aggregated to a longer time-step,

I''m getting a segmentation fault on a large index (15GB). I''m running ferret 0.11.4 on OpenSuSE 10.2 with ruby 1.8.6. The segmentation fault appeared after I optimized the index, see further below for the error message I got before that. Ferret works perfectly on other (smaller) indexes. Is this a known issue, and if so, is there a workaround? --------------------- after

Hi Atin, Please find the backtrace and logs files attached here. Also, below are the BT from core. (gdb) bt #0 0x00003fff8834b898 in __GI_raise (sig=<optimized out>) at ../sysdeps/unix/sysv/linux/raise.c:55 #1 0x00003fff88350fd0 in __GI_abort () at abort.c:89 [**ALERT: The abort() might not be exactly invoked from the following function line. If the trail function

I hope these logs were sufficient... please let me know if you require more logs. On Wed, Dec 6, 2017 at 3:26 PM, ABHISHEK PALIWAL <abhishpaliwal at gmail.com> wrote: > Hi Atin, > > Please find the backtrace and logs files attached here. > > Also, below are the BT from core. > > (gdb) bt > > #0 0x00003fff8834b898 in __GI_raise (sig=<optimized out>) at >

Without the glusterd log file and the core file or the backtrace I can't comment anything. On Wed, Dec 6, 2017 at 3:09 PM, ABHISHEK PALIWAL <abhishpaliwal at gmail.com> wrote: > Any suggestion.... > > On Dec 6, 2017 11:51, "ABHISHEK PALIWAL" <abhishpaliwal at gmail.com> wrote: > >> Hi Team, >> >> We are getting the crash in glusterd after

...42-desktop> Content-Type: text/plain; charset="UTF-8" Hello Consider following dataframe named df var1 var2 var3 3771 354 565 654654 963 6677 775 147 657754 df <- read.table('clipboard', header = TRUE) df #find indexes with '77' in var 1 myIndexes <- grep( glob2rx("*77*"), df$var1) myIndexes #find actual values of seach above myValu <- grep( glob2rx("*77*"), df$var1, value=TRUE) myValu #find all '77' in entire dataframe all77 <- lapply(df, function(x)grep( glob2rx("*77*"), x, value=TRUE)) all77...